Codeforces Round #334 (Div. 2) A. Uncowed Forces 水题
A. Uncowed Forces
Time Limit: 20 Sec
Memory Limit: 256 MB
题目连接
http://codeforces.com/contest/604/problem/A
Description
Kevin Sun has just finished competing in Codeforces Round #334! The round was 120 minutes long and featured five problems with maximum point values of 500, 1000, 1500, 2000, and 2500, respectively. Despite the challenging tasks, Kevin was uncowed and bulldozed through all of them, distinguishing himself from the herd as the best cowmputer scientist in all of Bovinia. Kevin knows his submission time for each problem, the number of wrong submissions that he made on each problem, and his total numbers of successful and unsuccessful hacks. Because Codeforces scoring is complicated, Kevin wants you to write a program to compute his final score.
Codeforces scores are computed as follows: If the maximum point value of a problem is x, and Kevin submitted correctly at minute m but made w wrong submissions, then his score on that problem is
. His total score is equal to the sum of his scores for each problem. In addition, Kevin's total score gets increased by 100 points for each successful hack, but gets decreased by 50 points for each unsuccessful hack.
All arithmetic operations are performed with absolute precision and no rounding. It is guaranteed that Kevin's final score is an integer.
Input
The first line of the input contains five space-separated integers m1, m2, m3, m4, m5, where mi (0 ≤ mi ≤ 119) is the time of Kevin's last submission for problem i. His last submission is always correct and gets accepted.
The second line contains five space-separated integers w1, w2, w3, w4, w5, where wi (0 ≤ wi ≤ 10) is Kevin's number of wrong submissions on problem i.
The last line contains two space-separated integers hs and hu (0 ≤ hs, hu ≤ 20), denoting the Kevin's numbers of successful and unsuccessful hacks, respectively.
Output
Print a single integer, the value of Kevin's final score.
Sample Input
20 40 60 80 100
0 1 2 3 4
1 0
Sample Output
4900
HINT
题意
给你CF的积分规则,然后告诉你一个人的每道题的提交时间,已经wa了几发,以及hack成功和hack失败次数
问你最后得了多少分
题解:
水题,唯一注意的一点就是,不要直接用题目给你的公式,会挂精度的
代码:
#include<iostream>
#include<math.h>
#include<stdio.h>
using namespace std; int m[];
int w[];
int main()
{
for(int i=;i<=;i++)
cin>>m[i];
for(int i=;i<=;i++)
cin>>w[i];
int H,IH;
cin>>H>>IH;
int ans = ;
for(int i=;i<=;i++)
ans+=max((*i),(-m[i])*i*-*w[i]);
ans+=*H - *IH;
cout<<ans<<endl;
}
Codeforces Round #334 (Div. 2) A. Uncowed Forces 水题的更多相关文章
- Codeforces Round #367 (Div. 2) A. Beru-taxi (水题)
Beru-taxi 题目链接: http://codeforces.com/contest/706/problem/A Description Vasiliy lives at point (a, b ...
- Codeforces Round #353 (Div. 2) A. Infinite Sequence 水题
A. Infinite Sequence 题目连接: http://www.codeforces.com/contest/675/problem/A Description Vasya likes e ...
- Codeforces Round #327 (Div. 2) A. Wizards' Duel 水题
A. Wizards' Duel Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/591/prob ...
- Codeforces Round #146 (Div. 1) A. LCM Challenge 水题
A. LCM Challenge 题目连接: http://www.codeforces.com/contest/235/problem/A Description Some days ago, I ...
- Codeforces Round #335 (Div. 2) B. Testing Robots 水题
B. Testing Robots Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://www.codeforces.com/contest/606 ...
- Codeforces Round #335 (Div. 2) A. Magic Spheres 水题
A. Magic Spheres Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://www.codeforces.com/contest/606/ ...
- Codeforces Round #306 (Div. 2) A. Two Substrings 水题
A. Two Substrings Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/550/pro ...
- Codeforces Round #188 (Div. 2) A. Even Odds 水题
A. Even Odds Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/318/problem/ ...
- Codeforces Round #333 (Div. 2) A. Two Bases 水题
A. Two Bases Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/602/problem/ ...
随机推荐
- Mem Cgroup目录无法清理问题分析
http://blogs.360.cn/360xitong/2013/05/02/mem-cgroup%E7%9B%AE%E5%BD%95%E6%97%A0%E6%B3%95%E6%B8%85%E7% ...
- GitHub托管
借助GitHub托管你的项目代码 PS:话说自己注册了GitHub都很久了,却没有怎么去弄,现在系统学习一下,也把自己的学习经历总结下来share给大家,希望大家都能把GitHub用起来,把你的项 ...
- java web 学习二(Tomcat服务器学习和使用1)
一.Tomcat服务器端口的配置 Tomcat的所有配置都放在conf文件夹之中,里面的server.xml文件是配置的核心文件. 如果想修改Tomcat服务器的启动端口,则可以在server.xml ...
- replace() MySQL批量替换指定字段字符串
mysql replace实例说明: UPDATE tb1 SET f1=REPLACE(f1, 'abc', 'def'); REPLACE(str,from_str,to_str) 在字符串 st ...
- SDUT 3568 Rock Paper Scissors 状压统计
就是改成把一个字符串改成三进制状压,然后分成前5位,后5位统计, 然后直接统计 f[i][j][k]代表,后5局状压为k的,前5局比和j状态比输了5局的有多少个人 复杂度是O(T*30000*25*m ...
- IOS 给图片添加水印 打印文字
1.加文字 -(UIImage *)addText:(UIImage *)img text:(NSString *)text1 { //get image width and ...
- 线性模型(1):Perceptron Learning Algorithm (PLA)
此笔记源于台湾大学林轩田老师<机器学习基石><机器学习技法> (一) PLA算法是基本的binary Classification算法. 一个基本的问题是,对于银行,假设我知道 ...
- JavaEE5 Tutorial_Servlet
Web资源:web组件,静态web文件如图片 Web程序:可发布的Web资源集合 Web程序根目录下有个web-inf文件夹,如果只有jsp和静态资源,里面可以没有web.xml 根目录下可以直接 ...
- 20150913K-means聚类
1.聚类的思想: 将一个有N个对象的数据集,构造成k(k<=n)个划分,每个划分代表一个簇.使得每个簇包含一个对象,每个对象有且仅属于一个簇.对于给定的k,算法首先给出一个初始的划分方法,以后通 ...
- (转)Http协议经典详解
转自:http://blog.csdn.net/gueter/archive/2007/03/08/1524447.aspx Author :Jeffrey 引言 HTTP 是一个属于应用层的面向对象 ...