Codeforces Gym100735 I.Yet another A + B-Java大数 (KTU Programming Camp (Day 1) Lithuania, Birˇstonas, August 19, 2015)
I.Yet another A + B
You are given three numbers. Is there a way to replace variables A, B and C with these numbers so the equality A + B = C is correct?
Input
There are three numbers X1, X2 and X3 (1 ≤ Xi ≤ 10100), each on a separate line of input.
Output
either "YES if there is a way to substitute variables A, B and C with given numbers so the equality is correct, or "NO"otherwise.
Examples
input
1 2 3
output
YES
input
1 2 4
output
YES
input
1 3 5
output
NO
大数计算,给出的数任选2个相加能否等于第三个数或者重复选1个数相加是否等于剩下的2个中的1个,因为是大数,所以直接用Java写的,偷懒专用,哈哈哈哈哈哈。
代码:
1 import java.util.Scanner;
2
3 public class BigInteger {
4 private static Scanner cin;
5
6 public static void main(String[] args) {
7 cin = new Scanner(System.in);
8 java.math.BigInteger a;
9 java.math.BigInteger b;
10 java.math.BigInteger c;
11 a = cin.nextBigInteger();
12 b = cin.nextBigInteger();
13 c = cin.nextBigInteger();
14 if((a.add(b)).compareTo(c)==0)System.out.println("YES\n");
15 else if((a.add(c)).compareTo(b)==0)System.out.println("YES\n");
16 else if((b.add(c)).compareTo(a)==0)System.out.println("YES\n");
17 else if((a.add(a)).compareTo(b)==0||(a.add(a)).compareTo(c)==0)System.out.println("YES\n");
18 else if((b.add(b)).compareTo(a)==0||(b.add(b)).compareTo(c)==0)System.out.println("YES\n");
19 else if((c.add(c)).compareTo(a)==0||(c.add(c)).compareTo(b)==0)System.out.println("YES\n");
20 else System.out.println("NO\n");
21 }
22 }
Codeforces Gym100735 I.Yet another A + B-Java大数 (KTU Programming Camp (Day 1) Lithuania, Birˇstonas, August 19, 2015)的更多相关文章
- Codeforces Gym100735 G.LCS Revised (KTU Programming Camp (Day 1) Lithuania, Birˇstonas, August 19, 2015)
G.LCS Revised The longest common subsequence is a well known DP problem: given two strings A and B ...
- Codeforces Gym100735 E.Restore (KTU Programming Camp (Day 1) Lithuania, Birˇstonas, August 19, 2015)
E - Restore Given a matrix A of size N * N. The rows are numbered from 0 to N-1, the columns are num ...
- Codeforces Gym100735 D.Triangle Formation (KTU Programming Camp (Day 1) Lithuania, Birˇstonas, August 19, 2015)
日常训练题解 D.Triangle Formation You are given N wooden sticks. Your task is to determine how many triang ...
- java大数
java大数还是很好用的! 基本加入: import java.math.BigInteger; import jave.math.BigDecimal; 分别是大数和大浮点数. 首先读入可以用: S ...
- JAVA大数运算
java大数是个好东西,用起来方便,代码短. 代码如下: import java.util.*; import java.math.*; public class Main { public stat ...
- java大数总结【转】
java大数(2013长春网络赛)--hdu4762总结一下:1.java提交类要写Main.2.读取大数. Scanner read=new Scanner(System.in); BigInteg ...
- HDU5047Sawtooth(java大数)
HDU5047Sawtooth(java大数) 题目链接 题目大意:在一个矩形内画n个"M".问如何画可以把这个矩形分成最多的区域. 给出这个区域的数目. 解题思路:最好的方式就是 ...
- JAVA大数类
JAVA大数类api http://man.ddvip.com/program/java_api_zh/java/math/BigInteger.html#method_summary 不仅仅只能查J ...
- HDU4762(JAVA大数)
Cut the Cake Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Tota ...
随机推荐
- HDU:2594-Simpsons’ Hidden Talents
Simpsons' Hidden Talents Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Ot ...
- POJ:2185-Milking Grid(KMP找矩阵循环节)
Milking Grid Time Limit: 3000MS Memory Limit: 65536K Description Every morning when they are milked, ...
- [Poj3281]Dining(最大流)
Description 有n头牛,f种食物,d种饮料,每头牛有nf种喜欢的食物,nd种喜欢的饮料,每种食物如果给一头牛吃了,那么另一个牛就不能吃这种食物了,饮料也同理,问最多有多少头牛可以吃到它喜欢的 ...
- UVA_1025 a Spy in the Metro 有向无环图的动态规划问题
应当认为,有向无环图上的动态规划问题是动态规划的基本模型之一,对于某个模型,如果可以转换为某一有向无环图的最长.最短路径问题,则可以套用动态规划若干方法解决. 原题参见刘汝佳紫薯267页. 在这个题目 ...
- sql优化系列3(收集来源http://bbs.csdn.net/topics/250004467)
如何加快查询速度? 1.升级硬件 2.根据查询条件,建立索引,优化索引.优化访问方式,限制结果集的数据量. 3.扩大服务器的内存 4.增加服务器CPU个数 5.对于大的数据库不要设置数据库自动增长 ...
- Pre 自动换行和手动换行
pre { white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre ...
- Html语言的标签讲解
一.head头部中的内容: 1.<meta charset="UTF-8"> <--!告诉浏览器什么编码--> 2.<meta http-equiv= ...
- [python][django学习篇][3]创建django web的数据库模型
推荐学习博客:http://pythonzh.cn/post/8/ 博客或者web界面向用户展示内容,它需要从某个地方获取博客内容或者web界面内容,才能够展示出来.通常来说:某个地方指的就是数据库 ...
- activemq概念介绍
ActiveMQ概念介绍 是Apache下的开源项目,完全支持JMS1.1和J2EE1.4规范的JMS Provider实现,消息中间件. 消息中间件: A传递消息到B(功能或者系统),有比较强的耦合 ...
- iOS-字体UIFont的lineHeight与pointSize
首先我们来看一看UIFont的API里面有哪些属性: // Font attributes @property(nonatomic,readonly,strong) NSString *familyN ...