[LeetCode] LRU Cache [Forward]
Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set.
get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.set(key, value) - Set or insert the value if the key is not already present. When the cache reached its capacity, it should invalidate the least recently used item before inserting a new item.
struct node {
node* pre;
int key;
int value;
node* next;
node(int k, int v):key(k),value(v),pre(NULL),next(NULL) {};
};
class LRUCache {
map<int, node*> mp;
node* head;
node* tail;
int size;
int capacity;
public:
LRUCache(int c) {
if (c < )return;
head = new node(, );
tail = new node(, );
head->next = tail;
tail->pre = head;
mp.clear();
size = ;
capacity = c;
}
int get(int k) {
map<int, node*>::iterator it = mp.find(k);
if (it != mp.end()) {
node* cur = (*it).second;
cur->pre->next = cur->next;
cur->next->pre = cur->pre;
putToHead(cur);
return cur->value;
} else
return -;
}
void set(int k, int val) {
if (capacity < )return;
map<int, node*>::iterator it = mp.find(k);
if (it != mp.end()) {//find
node* cur = (*it).second;
cur->pre->next = cur->next;
cur->next->pre = cur->pre;
cur->value = val;
putToHead(cur);
} else {//not find
node* tmp = new node(k,val);
putToHead(tmp);
mp[k] = tmp;
if (size < capacity) {//size < capacity
size++;
} else {//size >= capacity
node* deltmp = tail->pre;
tail->pre = deltmp->pre;
deltmp->pre->next = tail;
it = mp.find(deltmp->key);
mp.erase(it);
delete deltmp;
}
}
}
void putToHead(node* cur)
{
cur->next = head->next;
cur->pre = head;
cur->next->pre = cur;
head->next = cur;
}
};
[LeetCode] LRU Cache [Forward]的更多相关文章
- [LeetCode] LRU Cache 最近最少使用页面置换缓存器
Design and implement a data structure for Least Recently Used (LRU) cache. It should support the fol ...
- [LeetCode]LRU Cache有个问题,求大神解答【已解决】
题目: Design and implement a data structure for Least Recently Used (LRU) cache. It should support the ...
- LeetCode:LRU Cache
题目大意:设计一个用于LRU cache算法的数据结构. 题目链接.关于LRU的基本知识可参考here 分析:为了保持cache的性能,使查找,插入,删除都有较高的性能,我们使用双向链表(std::l ...
- LeetCode——LRU Cache
Description: Design and implement a data structure for Least Recently Used (LRU) cache. It should su ...
- LeetCode: LRU Cache [146]
[题目] Design and implement a data structure for Least Recently Used (LRU) cache. It should support th ...
- LeetCode – LRU Cache (Java)
Problem Design and implement a data structure for Least Recently Used (LRU) cache. It should support ...
- Leetcode: LRU Cache 解题报告
LRU Cache Design and implement a data structure for Least Recently Used (LRU) cache. It should supp ...
- Leetcode:LRU Cache,LFU Cache
在Leetcode上遇到了两个有趣的题目,分别是利用LRU和LFU算法实现两个缓存.缓存支持和字典一样的get和put操作,且要求两个操作的时间复杂度均为O(1). 首先说一下如何在O(1)时间复杂度 ...
- leetcode LRU Cache python
class Node(object): def __init__(self,k,x): self.key=k self.val=x self.prev=None self.next=None clas ...
随机推荐
- 第二次 Ubuntu16.04 vi编辑器的方向键和退格问题
新安装ubuntu后,好多人可能都碰到过这样的问题,vi对文件进行编辑时,上下左右键变成了ABDC,退格键也不管用. 解决办法其实也很简单,首先卸载掉旧的vim-common. apt-get rem ...
- jQuery的ready与js的load事件的区别
摘自:http://www.cnblogs.com/see7di/archive/2011/07/15/2239677.html 为了理解这两个事件的异同,读者应该先了解HTML文档加载的顺序. DO ...
- ROS 笔记 程序包/节点/topic
官方教程: wiki.ros.org/cn/ROS/tutorials 程序包打创建于编译 创建程序包 在工作空间的src底下,输入如下命令: $ catkin_create_pkg 要创建的包名 依 ...
- BNUOJ 35759 The Great Pan
The Great Pan Time Limit: 1000ms Memory Limit: 65536KB This problem will be judged on HDU. Original ...
- 九度oj 题目1473:二进制数(stack)
题目1473:二进制数 时间限制:1 秒 内存限制:128 兆 特殊判题:否 提交:9371 解决:2631 题目描述: 大家都知道,数据在计算机里中存储是以二进制的形式存储的. 有一天,小明学了C语 ...
- hihoCoder#1082 然而沼跃鱼早就看穿了一切
原题地址 字符串匹配+替换 注意替换串和原串长度是不等的,所以替换完还要进行收缩 可以顺带练习一下KMP 代码: #include <iostream> #include <cstr ...
- [luoguP1056] 排座椅(sort + 模拟)
传送门 nc题,一直sort就过了 代码 #include <cstdio> #include <iostream> #include <algorithm> #d ...
- EasyUI单击行数据时动态编写editor
$.extend($.fn.treegrid.methods, { addEditor: function (jq, param) { if (param instanceof Array) { $. ...
- 乱记结论之OI常用四大数列
一.斐波那契数列 $f(0)=1,f(1)=1,f(i)=f(i-1)+f(i-2) \ \ \ \ (i>=2)$ 经典的解释是兔子生小孩,第0年一对兔子,一对兔子需要一年长大,后面每年都生小 ...
- hdu - 1151 Air Raid(有向无环图的最小路径覆盖)
http://acm.hdu.edu.cn/showproblem.php?pid=1151 在一个城市里有n个地点和k条道路,道路都是单向的,并且不存在环.(DAG) 现在伞兵需要去n个地点视察,伞 ...