Alice is providing print service, while the pricing doesn't seem to be reasonable, so people using her print service found some tricks to save money.
For example, the price when printing less than 100 pages is 20 cents per page, but when printing not less than 100 pages, you just need to pay only 10 cents per page. It's easy to figure out that if you want to print 99 pages, the best choice is to print an extra blank page so that the money you need to pay is 100 × 10 cents instead of 99 × 20 cents.
Now given the description of pricing strategy and some queries, your task is to figure out the best ways to complete those queries in order to save money.

 
Input
The first line contains an integer T (≈ 10) which is the number of test cases. Then T cases follow.
Each case contains 3 lines. The first line contains two integers n, m (0 < n, m ≤ 105 ). The second line contains 2n integers s1, p1 , s2, p2 , ..., sn, pn (0=s1 < s2 < ... < sn ≤ 109 , 109 ≥ p1 ≥ p2 ≥ ... ≥ pn ≥ 0).. The price when printing no less than si but less than si+1 pages is pi cents per page (for i=1..n-1). The price when printing no less than sn pages is pn cents per page. The third line containing m integers q1 .. qm (0 ≤ qi ≤ 109 ) are the queries.
 
Output
For each query qi, you should output the minimum amount of money (in cents) to pay if you want to print qi pages, one output in one line.
 
Sample Input
1
2 3
0 20 100 10
0 99 100
 
Sample Output
0
1000
1000
 
Source
 
/* ***********************************************
Author :pk28
Created Time :2015/10/15 20:05:30
File Name :changchun1.cpp
************************************************ */
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <stdio.h>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <math.h>
#include <stdlib.h>
#include <iomanip>
#include <list>
#include <deque>
#include <stack>
#define ull unsigned long long
#define ll long long
#define mod 90001
#define INF 1e13
#define maxn 100070
#define cle(a) memset(a,0,sizeof(a))
const ull inf = 1LL << ;
const double eps=1e-;
using namespace std; bool cmp(int a,int b){
return a>b;
}
int n,m;
ll x[maxn],p[maxn];
ll minn[maxn];
int main()
{
#ifndef ONLINE_JUDGE
freopen("in.txt","r",stdin);
#endif
//freopen("out.txt","w",stdout);
int t;
cin>>t;
while(t--){
cin>>n>>m;
for(int i=;i<=n;i++){
scanf("%lld %lld",&x[i],&p[i]);
}
minn[n+]=INF;
for(int i=n;i>=;i--){
minn[i]=min(minn[i+],p[i]*x[i]);
}
ll a,ans;
for(int i=;i<=m;i++){
scanf("%lld",&a);
int pos=lower_bound(x+,x++n,a)-x;
ans=min(a*p[pos-],minn[pos]);
printf("%lld\n",ans);
}
}
return ;
}

UVAlive 6611 Alice's Print Service 二分的更多相关文章

  1. HDU 4791 Alice's Print Service (2013长沙现场赛,二分)

    Alice's Print Service Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Ot ...

  2. 2013 ACM/ICPC 长沙现场赛 A题 - Alice's Print Service (ZOJ 3726)

    Alice's Print Service Time Limit: 2 Seconds      Memory Limit: 65536 KB Alice is providing print ser ...

  3. HDU 4791 Alice's Print Service 思路,dp 难度:2

    A - Alice's Print Service Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & ...

  4. Alice's Print Service

    Alice's Print Service Time Limit: 2 Seconds      Memory Limit: 65536 KB Alice is providing print ser ...

  5. A - Alice's Print Service ZOJ - 3726 (二分)

    Alice is providing print service, while the pricing doesn't seem to be reasonable, so people using h ...

  6. HDU 4791 Alice's Print Service(2013长沙区域赛现场赛A题)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4791 解题报告:打印店提供打印纸张服务,需要收取费用,输入格式是s1 p1 s2 p2 s3 p3.. ...

  7. 2013 ACM区域赛长沙 A Alice’s Print Service HDU 4791

    题意:就是一个打印分段收费政策,印的越多,单张价格越低,输入需要印刷的数量,求最小印刷费用一个细节就是,比当前还小的状态可能是最后几个. #include<stdio.h> #includ ...

  8. HDU 4791 Alice&#39;s Print Service 水二分

    点击打开链接 Alice's Print Service Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K ( ...

  9. HDU 4791 &amp; ZOJ 3726 Alice&#39;s Print Service (数学 打表)

    题目链接: HDU:http://acm.hdu.edu.cn/showproblem.php?pid=4791 ZJU:http://acm.zju.edu.cn/onlinejudge/showP ...

随机推荐

  1. *AtCoder Regular Contest 094 F - Normalization

    $n \leq 200000$的abc字符串,现能进行如下变换零次或若干次:选一个$i<n$且$s_i \neq s_{i+1}$,把$s_i$和$s_{i+1}$替换成abc三个字母中除了这两 ...

  2. 【黑科技】读写优化 orz bdd

    转自 bdd :http://www.cnblogs.com/kevince/p/3924688.html 读入优化: inline int read() { char ch; bool flag = ...

  3. 标准C程序设计七---01

    Linux应用             编程深入            语言编程 标准C程序设计七---经典C11程序设计    以下内容为阅读:    <标准C程序设计>(第7版) 作者 ...

  4. Perl、PHP、Python、Java和Ruby的比较

    提问 ◆ Perl.Python.Ruby和PHP各自有何特点? ◆ 为什么动态语言多作为轻量级的解决方案? ◆ LAMP为什么受欢迎? ◆ Ruby on Rails为什么会流行? ◆ 编程语言的发 ...

  5. Flutter学习(一)——搭建开发环境(Windows)

    久闻 Flutter 大名,今天终于有时间体验一下了 ٩(๑>◡<๑)۶ 官网:https://flutter.dev/ 中文官网:https://flutterchina.club/ 一 ...

  6. Log4J使用详情

    一 .Log4J使用详情 Log4J的配置文件(Configuration File)就是用来设置记录器的级别.存放器和布局的,它可接key=value格式的设置或xml格式的设置信息.通过配置,可以 ...

  7. IntelliJ IDEA删除项目

    删除项目一向比较奇葩,因为当你点击到该项目名称右键时,并没有delete选项,导致我们不知道怎么删除,查找多方文档,得到以下解决: 1.将鼠标移到要删除的项目名称上,单击并按“Delete”按钮删除项 ...

  8. Linux下的搜索命令grep(转)

    一.简介 grep(global search regular expression(RE) and print out the line,全面搜索正则表达式并把行打印出来)是一种强大的文本搜索工具, ...

  9. JS那些事儿——Gulp的入门使用

    前言 新人使用gulp的一个记录. 首先对于第一个新事物,我会问gulp这是什么? 答:gulp是一个自动化构建工具,它可以做一些自动化的任务,比如: 检查Javascript 编译Sass(或Les ...

  10. Go -- type 和断言 interface{}转换

    摘要 类型转换在程序设计中都是不可避免的问题.当然有一些语言将这个过程给模糊了,大多数时候开发者并不需要去关 注这方面的问题.但是golang中的类型匹配是很严格的,不同的类型之间通常需要手动转换,编 ...