给一个datastream和一个fixed window size, 让我design一个class可以完成add number还有find average in the window. 就是不能用vector得用array. 

当然用queue是最好的

package DataStreamAverage;

import java.util.*;

public class Solution {
int count;
int sum;
Queue<Integer> q; public Solution() {
this.count = 0;
this.sum = 0;
this.q = new LinkedList<Integer>();
} public ArrayList<Double> average (HashSet<Integer> set, int L) {
ArrayList<Double> result = new ArrayList<Double>();
Iterator<Integer> iter = set.iterator();
while (iter.hasNext()) {
int cur = iter.next();
q.offer(cur);
count++;
sum += cur;
if (q.size()>L) {
int front = q.peek();
sum -= front;
count--;
q.poll();
}
double aver = (double)sum/count;
result.add(aver);
}
return result; } /**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
HashSet<Integer> set = new HashSet<Integer>();
for (int i=1; i<=10; i++) {
set.add(i);
}
Solution sol = new Solution();
ArrayList<Double> res = sol.average(set, 2);
System.out.println(res);
} }

当然用fixed size array也可以,但是要小心,一个是要折回,二个是要删除数组元素之前存在的数

 package DataStreamAverage;

 import java.util.*;

 public class Solution2 {
int count;
int sum;
int[] arr;
int pos; public Solution2(int size) {
this.count = 0;
this.sum = 0;
this.arr = new int[size];
Arrays.fill(arr, Integer.MIN_VALUE);
this.pos = 0;
} public ArrayList<Double> average (HashSet<Integer> set, int L) {
ArrayList<Double> result = new ArrayList<Double>();
Iterator<Integer> iter = set.iterator();
while (iter.hasNext()) {
int cur = iter.next();
if (pos == arr.length) {
pos = 0;
}
if (arr[pos] != Integer.MIN_VALUE) {
sum -= arr[pos];
count--;
}
arr[pos] = cur;
sum += arr[pos];
pos++;
count++;
double aver = (double)sum/count;
result.add(aver);
}
return result;
} /**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
HashSet<Integer> set = new HashSet<Integer>();
for (int i=1; i<=10; i++) {
set.add(i);
}
Solution2 sol = new Solution2(2);
ArrayList<Double> res = sol.average(set, 2);
System.out.println(res);
} }

G面经prepare: Data Stream Average的更多相关文章

  1. 346. Moving Average from Data Stream

    /* * 346. Moving Average from Data Stream * 2016-7-11 by Mingyang * 这里注意的就是(double) sum / count * su ...

  2. [LeetCode] Data Stream as Disjoint Intervals 分离区间的数据流

    Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen ...

  3. [LeetCode] Find Median from Data Stream 找出数据流的中位数

    Median is the middle value in an ordered integer list. If the size of the list is even, there is no ...

  4. Find Median from Data Stream

    常规方法 超时 class MedianFinder { vector<int> coll; public: MedianFinder(){ } void heapfu(vector< ...

  5. 数据结构与算法(1)支线任务8——Find Median from Data Stream

    题目如下:(https://leetcode.com/problems/find-median-from-data-stream/) Median is the middle value in an ...

  6. [LeetCode] Find Median from Data Stream

    Find Median from Data Stream Median is the middle value in an ordered integer list. If the size of t ...

  7. LeetCode——Find Median from Data Stream

    Median is the middle value in an ordered integer list. If the size of the list is even, there is no ...

  8. Leetcode: Data Stream as Disjoint Intervals && Summary of TreeMap

    Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen ...

  9. 295. Find Median from Data Stream

    题目: Median is the middle value in an ordered integer list. If the size of the list is even, there is ...

随机推荐

  1. Ubuntu/Deepin下常用软件汇总(持续更新)

    最近开始用Ubuntu了,好多软件都不是常用的了,在这边留底,以免忘记.如果没有写安装方法,则直接在软件源中可以找到 UNetbootin U盘制作工具,制作Ubuntu的安装U盘超好用 Braser ...

  2. Android源码剖析之Framework层进阶版(Wms窗口管理)

    本文来自http://blog.csdn.net/liuxian13183/ ,引用必须注明出处! 上一篇我们主要讲了Ams,篇幅有限,本篇再讲讲Wms,即WindowManagerService,管 ...

  3. UML时序图总结

    前言 在我的工作中,用的最多的就是时序图了.可能由于工作的原因,我也是最喜欢画时序图了,很清楚,很明了,什么时候发送什么消息,到达什么状态,一下子就展示在你的脑海里,对于消息驱动的程序来说,是再好不过 ...

  4. 经常在eclipse中导入web项目时,出现转不了项目类型的问题,导入后就是一个java项目。

    1.在eclipse的项目上点右键,刷新项目.2.在项目上点右键,进入属性(properties)3.在左侧列表项目中点击选择“Project Facets”,在右侧选择“Dynamic Web Mo ...

  5. QGridLayout--01

    #include "mainwindow.h" #include <QApplication> #include<QLabel> #include<Q ...

  6. 1012 最小公倍数LCM

    1012 最小公倍数LCM 基准时间限制:1 秒 空间限制:131072 KB 输入2个正整数A,B,求A与B的最小公倍数. Input 2个数A,B,中间用空格隔开.(1<= A,B < ...

  7. ArcGIS API for Silverlight动态标绘的实现

    原文:ArcGIS API for Silverlight动态标绘的实现 1.下载2个dll文件,分别是: ArcGISPlotSilverlightAPI.dll 和 Matrix.dll 其下载地 ...

  8. Linux下/etc/resolv.conf 配置DNS客户

    文件/etc/resolv.conf配置DNS客户,它包含了主机的域名搜索顺序和DNS服务器的地址,每一行应包含一个关键字和一个或多个的由空格隔开的参数.下面是一个例子文件: search mydom ...

  9. SQL Server 2008 R2中,“选择前1000行”为“选择所有行”

    从SQL Server 2008开始,微软为了提高查询效率等原因,右键点击表时弹出菜单中默认没有"显示所有行",而以"选择前1000行"替代. 点击[工具]-& ...

  10. 在Fedora8上安装jdk-7u25-linux-i586.rpm的步骤

    按:我们身处一个信息爆炸的年代,当有事不决时,打开搜索引擎瞬息间就能得到海量的答案.但是,这未必会让你的问题迎刃而解,因此很多“答案”会把你引向错误的方向,浪费你的时间.希望搜索引擎能有所改进,对明确 ...