class Solution {
public: int lengthOfLastWord(string s) {
int i=;
int len=; while(s[i]&&s[i]==' ') i++; //去掉开头的空格
bool flag = false; while(s[i]){
cout<<len<<endl;
if(s[i]!=' '){
if(flag == true) //如果要计算下一个word,那么len=1
{len=;flag=false;}
else //如果还是当前word,len++
len++;
}
else flag=true; //是空格表示接下来,要统计的另外一个word了
i++;
} return len;
}
};

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