Spring源码 19 IOC getBean方法
前面实现了
ClassPathXmlApplicationContext的构造,接下来分析其调用的getBean方法。
以getBean(UserDao.class)为例。
1 AbstractApplicationContext
public <T> T getBean(Class<T> requiredType) throws BeansException {
// 断言 Bean 工厂活动
assertBeanFactoryActive();
// 获取 Bean 工厂
// 获取 Bean
return getBeanFactory().getBean(requiredType);
}
1-1 断言 Bean 工厂活动
assertBeanFactoryActive()
protected void assertBeanFactoryActive() {
if (!this.active.get()) {
if (this.closed.get()) {
// 获取显示名称
throw new IllegalStateException(getDisplayName() + " has been closed already");
}
else {
// 获取显示名称
throw new IllegalStateException(getDisplayName() + " has not been refreshed yet");
}
}
}
获取显示名称前面已经分析过了,这里不再分析。
1-1 获取 Bean 工厂
getBeanFactory()
2 AbstractRefreshableApplicationContext
public final ConfigurableListableBeanFactory getBeanFactory() {
DefaultListableBeanFactory beanFactory = this.beanFactory;
if (beanFactory == null) {
throw new IllegalStateException("BeanFactory not initialized or already closed - " + "call 'refresh' before accessing beans via the ApplicationContext");
}
return beanFactory;
}
if (beanFactory == null)由于前面定义了beanFactory,这里直接返回。
1 AbstractApplicationContext
1-1 获取 Bean
getBean(requiredType)
3 DefaultListableBeanFactory
public <T> T getBean(Class<T> requiredType) throws BeansException {
// 获取 Bean
return getBean(requiredType, (Object[]) null);
}
public <T> T getBean(Class<T> requiredType, @Nullable Object... args) throws BeansException {
Assert.notNull(requiredType, "Required type must not be null");
// 解析 Bean
Object resolved = resolveBean(ResolvableType.forRawClass(requiredType), args, false);
if (resolved == null) {
throw new NoSuchBeanDefinitionException(requiredType);
}
return (T) resolved;
}
3-1 解析 Bean
resolveBean(ResolvableType.forRawClass(requiredType), args, false)
private <T> T resolveBean(ResolvableType requiredType, @Nullable Object[] args, boolean nonUniqueAsNull) {
// 解析 Bean 命名
NamedBeanHolder<T> namedBean = resolveNamedBean(requiredType, args, nonUniqueAsNull);
if (namedBean != null) {
return namedBean.getBeanInstance();
}
// 获取父级 Bean 工厂
BeanFactory parent = getParentBeanFactory();
if (parent instanceof DefaultListableBeanFactory) {
// 解析 Bean,递归调用
return ((DefaultListableBeanFactory) parent).resolveBean(requiredType, args, nonUniqueAsNull);
}
else if (parent != null) {
ObjectProvider<T> parentProvider = parent.getBeanProvider(requiredType);
if (args != null) {
return parentProvider.getObject(args);
}
else {
return (nonUniqueAsNull ? parentProvider.getIfUnique() : parentProvider.getIfAvailable());
}
}
return null;
}
3-2 解析 Bean 命名
resolveNamedBean(requiredType, args, nonUniqueAsNull)
private <T> NamedBeanHolder<T> resolveNamedBean(ResolvableType requiredType, @Nullable Object[] args, boolean nonUniqueAsNull) throws BeansException {
Assert.notNull(requiredType, "Required type must not be null");
// 获取类型的 Bean 名称
String[] candidateNames = getBeanNamesForType(requiredType);
if (candidateNames.length > 1) {
List<String> autowireCandidates = new ArrayList<>(candidateNames.length);
for (String beanName : candidateNames) {
if (!containsBeanDefinition(beanName) || getBeanDefinition(beanName).isAutowireCandidate()) {
autowireCandidates.add(beanName);
}
}
if (!autowireCandidates.isEmpty()) {
candidateNames = StringUtils.toStringArray(autowireCandidates);
}
}
if (candidateNames.length == 1) {
// 解析 Bean 命名
return resolveNamedBean(candidateNames[0], requiredType, args);
} else if (candidateNames.length > 1) {
Map<String, Object> candidates = CollectionUtils.newLinkedHashMap(candidateNames.length);
for (String beanName : candidateNames) {
if (containsSingleton(beanName) && args == null) {
Object beanInstance = getBean(beanName);
candidates.put(beanName, (beanInstance instanceof NullBean ? null : beanInstance));
} else {
candidates.put(beanName, getType(beanName));
}
}
// 确定主要候选
String candidateName = determinePrimaryCandidate(candidates, requiredType.toClass());
if (candidateName == null) {
// 确定最高优先级候选
candidateName = determineHighestPriorityCandidate(candidates, requiredType.toClass());
}
if (candidateName != null) {
Object beanInstance = candidates.get(candidateName);
if (beanInstance == null) {
return null;
}
if (beanInstance instanceof Class) {
// 解析 Bean 命名
return resolveNamedBean(candidateName, requiredType, args);
}
return new NamedBeanHolder<>(candidateName, (T) beanInstance);
}
if (!nonUniqueAsNull) {
throw new NoUniqueBeanDefinitionException(requiredType, candidates.keySet());
}
}
return null;
}
3-3 确定主要候选
determinePrimaryCandidate(candidates, requiredType.toClass())
protected String determinePrimaryCandidate(Map<String, Object> candidates, Class<?> requiredType) {
String primaryBeanName = null;
for (Map.Entry<String, Object> entry : candidates.entrySet()) {
String candidateBeanName = entry.getKey();
Object beanInstance = entry.getValue();
if (isPrimary(candidateBeanName, beanInstance)) {
if (primaryBeanName != null) {
boolean candidateLocal = containsBeanDefinition(candidateBeanName);
boolean primaryLocal = containsBeanDefinition(primaryBeanName);
if (candidateLocal && primaryLocal) {
throw new NoUniqueBeanDefinitionException(requiredType, candidates.size(), "more than one 'primary' bean found among candidates: " + candidates.keySet());
} else if (candidateLocal) {
primaryBeanName = candidateBeanName;
}
} else {
primaryBeanName = candidateBeanName;
}
}
}
return primaryBeanName;
}
3-3 确定最高优先级候选
determineHighestPriorityCandidate(candidates, requiredType.toClass())
protected String determineHighestPriorityCandidate(Map<String, Object> candidates, Class<?> requiredType) {
String highestPriorityBeanName = null;
Integer highestPriority = null;
for (Map.Entry<String, Object> entry : candidates.entrySet()) {
String candidateBeanName = entry.getKey();
Object beanInstance = entry.getValue();
if (beanInstance != null) {
Integer candidatePriority = getPriority(beanInstance);
if (candidatePriority != null) {
if (highestPriorityBeanName != null) {
if (candidatePriority.equals(highestPriority)) {
throw new NoUniqueBeanDefinitionException(requiredType, candidates.size(), "Multiple beans found with the same priority ('" + highestPriority + "') among candidates: " + candidates.keySet());
} else if (candidatePriority < highestPriority) {
highestPriorityBeanName = candidateBeanName;
highestPriority = candidatePriority;
}
} else {
highestPriorityBeanName = candidateBeanName;
highestPriority = candidatePriority;
}
}
}
}
return highestPriorityBeanName;
}
参考
https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click
https://www.bilibili.com/video/BV12Z4y197MU?spm_id_from=333.999.0.0
《Spring源码深度解析(第2版)》
版本
Spring 5.3.15
Spring源码 19 IOC getBean方法的更多相关文章
- Spring源码 19 IOC getBean
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 16 IOC refresh方法11
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 17 IOC refresh方法12
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 11 IOC refresh方法6
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 07 IOC refresh方法2
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 06 IOC refresh方法1
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 18 IOC refresh方法13
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 15 IOC refresh方法10
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 14 IOC refresh方法9
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
- Spring源码 09 IOC refresh方法4
参考源 https://www.bilibili.com/video/BV1tR4y1F75R?spm_id_from=333.337.search-card.all.click https://ww ...
随机推荐
- 矩池云 | GPU 分布式使用教程之 Pytorch
GPU 分布式使用教程之 Pytorch Pytorch 官方推荐使用 DistributedDataParallel(DDP) 模块来实现单机多卡和多机多卡分布式计算.DDP 模块涉及了一些新概念, ...
- 第一百一十三篇: JS数组Array(二)数组方法 栈、队列、排序
好家伙, 在上一篇中,我们知道了, JS的数组中每个槽位可以存储任意类型的数据 那么,我们能通过数组去模仿某些数据结构吗? 答案是肯定的 1.栈方法 ECMAScript 给数组提供几个方法,让 ...
- 【Azure Redis】Redis客户端出现15分钟的超时异常
问题描述 客户端使用 Lettuce.io 连接 Azure Redis,出现了长达15分钟的Timeout异常. 问题解答 Azure Redis作为PaaS服务,由于一些平台的升级操作而引发的故障 ...
- 【Azure 应用服务】App Service for Container中配置与ACR(Azure Container Registry)的RABC权限
问题描述 在使用App Service for container时,在从ACR(Azure Container Registry)中获取应用的镜像时,需要使用对应的权限.默认情况为在ACR中启用Ad ...
- java GUI 快速入门
java 中编写 GUI 有两中工具包,分别为 AWT.Swing. Swing 是 AWT 的拓展,Swing 具有比 AWT 丰富的组件和方法. AWT 和 Swing 都能跨平台使用:AWT 会 ...
- C++ //常用算法 binary_serach //查找指定的元素 //无序序列中不可用
1 //常用算法 binary_serach 2 //查找指定的元素 3 //无序序列中不可用 4 5 6 #include<iostream> 7 #include<algorit ...
- Beckhoff 倍福 漏洞-整理(持续更新)
工控漏洞整理网站 http://ivd.winicssec.com/index.php/Home/Search/search.html?keyword=Beckhoff
- 一款开源、免费、跨平台的Redis可视化管理工具
前言 经常有小伙伴在技术群里问:有什么好用的Redis可视化管理工具推荐的吗?, 今天大姚给大家分享一款我一直在用的开源.免费(MIT License).跨平台的Redis可视化管理工具:Anothe ...
- 通过 TCPView KPKIService.exe 删掉 (原来是单点登录的中间件)
叫 统一安全中间件,就是个第三方做的key的安全检查,谁知道是哪年装的 (原来是单点登录的中间件) 资料 https://baijiahao.baidu.com/s?id=17173842191483 ...
- MySQL 双主集群搭建
搭建 MySQL 双主集群涉及多个配置步骤,以及对于可能出现的问题的理解和解决.下面将详细说明搭建过程的每个步骤. 前提条件 环境准备:准备两台服务器(物理或虚拟),并确保它们可以互相通信(例如,通过 ...