HDOJ(HDU) 2061 Treasure the new start, freshmen!(水题、)
Problem Description
background:
A new semester comes , and the HDU also meets its 50th birthday. No matter what’s your major, the only thing I want to tell you is:”Treasure the college life and seize the time.” Most people thought that the college life should be colorful, less presure.But in actual, the college life is also busy and rough. If you want to master the knowledge learned from the book, a great deal of leisure time should be spend on individual study and practise, especially on the latter one. I think the every one of you should take the learning attitude just as you have in senior school.
“No pain, No Gain”, HDU also has scholarship, who can win it? That’s mainly rely on the GPA(grade-point average) of the student had got. Now, I gonna tell you the rule, and your task is to program to caculate the GPA.
If there are K(K > 0) courses, the i-th course has the credit Ci, your score Si, then the result GPA is
GPA = (C1 * S1 + C2 * S2 +……+Ci * Si……) / (C1 + C2 + ……+ Ci……) (1 <= i <= K, Ci != 0)
If there is a 0 <= Si < 60, The GPA is always not existed.
Input
The first number N indicate that there are N test cases(N <= 50). In each case, there is a number K (the total courses number), then K lines followed, each line would obey the format: Course-Name (Length <= 30) , Credits(<= 10), Score(<= 100).
Notice: There is no blank in the Course Name. All the Inputs are legal
Output
Output the GPA of each case as discribed above, if the GPA is not existed, ouput:”Sorry!”, else just output the GPA value which is rounded to the 2 digits after the decimal point. There is a blank line between two test cases.
Sample Input
2
3
Algorithm 3 97
DataStruct 3 90
softwareProject 4 85
2
Database 4 59
English 4 81
Sample Output
90.10
Sorry!
题意:
输入:name c s
只要有一个成绩s是小于60的,输出就是“Sorry!”。
如果大于等于60,就计算GPA,公式
GPA = (C1 * S1 + C2 * S2 +……+Ci * Si……) / (C1 + C2 + ……+ Ci……) (1 <= i <= K, Ci != 0)
注意格式:输出之间有一个空行。答案保留2位小数!
(%.2f)输出是按照四舍五入的形式的。题目也是这么要求的!
import java.util.Scanner;
public class Main{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int t =sc.nextInt();
while(t-->0){
int m = sc.nextInt();
String str = "" ;
int c =0;
int s = 0;
boolean isSorry = false;
double num1=0;
double num2=0;
double a=0;
double b=0;
for(int i=0;i<m;i++){
str = sc.next();
a=sc.nextDouble();
b=sc.nextDouble();
if(b<60){
isSorry = true;
}else{
num1 = num1+a*b;
num2 = num2 +a;
}
}
if(isSorry){
System.out.println("Sorry!");
}else{
System.out.printf("%.2f",num1/num2);
System.out.println();
}
if(t!=0){
System.out.println();
}
}
}
}
HDOJ(HDU) 2061 Treasure the new start, freshmen!(水题、)的更多相关文章
- HDU 2061 Treasure the new start, freshmen!
http://acm.hdu.edu.cn/showproblem.php?pid=2061 Problem Description background:A new semester comes , ...
- HDOJ/HDU 1256 画8(绞下思维~水题)
Problem Description 谁画8画的好,画的快,今后就发的快,学业发达,事业发达,祝大家发,发,发. Input 输入的第一行为一个整数N,表示后面有N组数据. 每组数据中有一个字符和一 ...
- HDOJ(HDU) 1898 Sempr == The Best Problem Solver?(水题、、、)
Problem Description As is known to all, Sempr(Liangjing Wang) had solved more than 1400 problems on ...
- HDU 5832 A water problem(某水题)
p.MsoNormal { margin: 0pt; margin-bottom: .0001pt; text-align: justify; font-family: Calibri; font-s ...
- hdu 2393:Higher Math(计算几何,水题)
Higher Math Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total ...
- <hdu - 3999> The order of a Tree 水题 之 二叉搜索的数的先序输出
这里是杭电hdu上的链接:http://acm.hdu.edu.cn/showproblem.php?pid=3999 Problem Description: As we know,the sha ...
- HDU 1029 Ignatius and the Princess IV --- 水题
HDU 1029 题目大意:给定数字n(n <= 999999 且n为奇数 )以及n个数,找出至少出现(n+1)/2次的数 解题思路:n个数遍历过去,可以用一个map(也可以用数组)记录每个数出 ...
- HDU 5583 Kingdom of Black and White 水题
Kingdom of Black and White Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showpr ...
- HDU 1159 Common Subsequence 公共子序列 DP 水题重温
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1159 Common Subsequence Time Limit: 2000/1000 MS (Jav ...
随机推荐
- mysql @变量和变量的区别及怎么判断记录唯一性
DELIMITER// drop PROCEDURE if EXISTS test.express; create PROCEDURE test.express() BEGIN ) into @a f ...
- Linux学习方法之以始为终—Linux工作分类
/** ****************************************************************************** * @author 暴走的小 ...
- 错误记录--关于foreach,集合已修改;可能无法执行枚举操作
集合已修改,可能无法执行枚举操作.今天在使用foreach遍历的时候出现了这样的错误.查了一下,这个是使用foreach的典型的错误问题问题.foreach在遍历取数据的过程中,枚举器只允许读,不允许 ...
- #BeginLibraryItem 的疑问...
<!-- #BeginLibraryItem "/library/ur_here.lbi" --><div style="padding:3px 15p ...
- (转)Call to undefined function mb_convert_encoding()
需要先enable mbstring 扩展库 在 php.ini里将; extension=php_mbstring.dll 前面的 ; 去掉mb_convert_encoding 可以指定多种输入编 ...
- Kill Processes in Linux
Step 1: find processes to kill ps -ef | grep java Step 2: Kill the process based on process id kill ...
- 重新开始学习javase_Exception
“违例”(Exception)这个词表达的是一种“例外”情况,亦即正常情况之外的一种“异常”.在问题发生的时候,我们可能不知具体该如何解决,但肯定知道已不能不顾一切地继续下去.此时,必须坚决地停下来, ...
- [转]Java中byte与16进制字符串的互相转换
Java中byte用二进制表示占用8位,而我们知道16进制的每个字符需要用4位二进制位来表示(23 + 22 + 21 + 20 = 15),所以我们就可以把每个byte转换成两个相应的16进制字符, ...
- Direct2D 加载位图
说明: 通过WIC从文件加载位图. 可缩放后加载到内存. 源码: HRESULT LoadImageFormFile( IWICImagingFactory *pWicFactory, ID2D1Re ...
- VS2012 ActiveX控件_D接口添加方法事项
自己写的是Clock控件,所以控件的接口是_DClock 使用向导添加方法后,会在紫色区域自动生成红色代码:(添加Hello方法) dispinterface _DClock { properties ...