1792. Hamming Code

Time limit: 1.0 second

Memory limit: 64 MB
Let us consider four disks intersecting as in the figure. Each of the three shapes formed by the intersectionof three disks will be called a
petal.
Write zero or one on each of the disks. Then write on each petal the remainder in the division by two of the sumof integers on the disks that contain this petal. For example, if there were the integers 0, 1, 0, and 1 writtenon
the disks, then the integers written on the petals will be 0, 1, and 0 (the disks and petals are given in theorder shown in the figure).
This scheme is called a Hamming code. It has an interesting property: if you enemy changes secretely anyof the seven integers, you can determine uniquely which integer has been changed. Solve this problem and you willknow
how this can be done.

Input

The only line contains seven integers separated with a space, each of them being zero or one. The first fourintegers are those written on the disks in the order shown in the figure. The following three integers are thosewritten
on the petals in the order shown in the figure

Output

Output one line containing seven integers separated with a space. The integers must form a Hamming code. The setof integers may differ from the input set by one integer at most. It is guaranteed that either the input set isa
Hamming code or a Hamming code can be obtained from it by changing exactly one integer.

Samples

input output
0 1 0 1 1 0 1
0 1 0 0 1 0 1
1 1 1 1 1 1 1
1 1 1 1 1 1 1

Problem Author: Sofia Tekhazheva, prepared by Olga Soboleva

Problem Source: Ural Regional School Programming Contest 2010

解析:直接枚举哪个数字错了就可以,可是要注意错误数字最多仅仅可能是一个。!

PS:開始看到Hamming Code,还以为看到了计组的题。。。结果看了半天题目没看懂。

。。the remainder in the division by two of the sum of integers原来是数字和除以二之后的余数。

。。

URAL 1792. Hamming Code (枚举)的更多相关文章

  1. 汉明码(Hamming Code)原理及实现

    汉明码实现原理 汉明码(Hamming Code)是广泛用于内存和磁盘纠错的编码.汉明码不仅可以用来检测转移数据时发生的错误,还可以用来修正错误.(要注意的是,汉明码只能发现和修正一位错误,对于两位或 ...

  2. 汉明码(hamming code)

    hamming code用于磁盘RAID 2中, 关于汉明码的讲解可以看这篇博文,介绍的很详细.最重要是最后的结论: 汉明码属于分组奇偶校验,P4P2P1=000,说明接收方生成的校验位和收到的校验位 ...

  3. ural 1069. Prufer Code

    1069. Prufer Code Time limit: 0.25 secondMemory limit: 8 MB A tree (i.e. a connected graph without c ...

  4. URAL 1069 Prufer Code(模拟)

    Prufer Code Time limit: 0.25 secondMemory limit: 8 MB A tree (i.e. a connected graph without cycles) ...

  5. Hamming code

    Also known as (7,4) code,7 trainsmitted bits for 4 source code. TRANSMIT The transmitted procedure c ...

  6. Ural 1780 Gray Code 乱搞暴力

    原题链接:http://acm.timus.ru/problem.aspx?space=1&num=1780 1780. Gray Code Time limit: 0.5 secondMem ...

  7. URAL 1069 Prufer Code 优先队列

    记录每个节点的出度,叶子节点出度为0,每删掉一个叶子,度数-1,如果一个节点的出度变成0,那么它变成新的叶子. 先把所有叶子放到优先队列中. 从左往右遍历给定序列,对于root[i],每次取出叶子中编 ...

  8. 汉明码、海明校验码(Hamming Code)

    目录 基础知识 汉明码/海明校验码 计算 基础知识 码距:又叫海明距离,是在信息编码中,两个编码之间对应位上编码不同的位数.例如编码100110和010101,第1.2.5.6位都不相同,所以这两个编 ...

  9. SpringBoot枚举传参

    创建一个接口所有枚举继承 package com.gecko.charging.common; public interface BaseEnum { Integer getCode(); } 具体的 ...

随机推荐

  1. 【Visual C++】游戏开发五十六 浅墨DirectX教程二十三 打造游戏GUI界面(一)

    本系列文章由zhmxy555(毛星云)编写,转载请注明出处. 文章链接:http://blog.csdn.net/poem_qianmo/article/details/16384009 作者:毛星云 ...

  2. jquery日历签到控件的实现

    calendar.js var calUtil = { //当前日历显示的年份 showYear:2015, //当前日历显示的月份 showMonth:1, //当前日历显示的天数 showDays ...

  3. [LeetCode]题解(python):013-Roman to Integer

    题目来源: https://leetcode.com/problems/roman-to-integer/ 题意分析: 这道题目和上一题目相反,是将罗马数字转化成阿拉伯数字. 题目思路: 只要知道罗马 ...

  4. 升级到iis7 的web.config配置

    经典模式或集成模式都识别system.webServers节点 aspnet的isapi分32位和64位 不存在时会报404或403

  5. IT第十九天 - 继承、接口、多态、面向对象的编程思想

    IT第十九天 上午 继承 1.一般情况下,子类在继承父类时,会调用父类中的无参构造方法,即默认的构造方法:如果在父类中只写了有参的构造方法,这时如果在子类中继承时,就会出现报错,原因是子类继承父类时无 ...

  6. java.text.NumberFormat使用方法

    NumberFormat 是全部数值格式的抽象基类. 该类提供了格式化和分析数值的接口. NumberFormat 也提供了确定 哪个语言环境具有数值格式以及它们名字的方法. package com. ...

  7. 如何用 Swift 语言构建一个自定控件

    (via:破船之家,原文:How To Make a Custom Control in Swift)   用户界面控件是所有应用程序重要的组成部分之一.它们以图形组件的方式呈现给用户,用户可以通过它 ...

  8. python中的class

    尽管Python在Function Programming中有着其他语言难以企及的的优势,但是我们也不要忘了Python也是一门OO语言哦.因此我们关注Python在FP上的优势的同时,还得了解一下P ...

  9. IPython在Windows 7上的搭建步骤

    安装篇 pip install jupyter 使用篇 启动本地notebook,打开Windows命令行,键入:ipython notebook

  10. PyQt主窗体设置停靠窗口(QDockWidget)的叠加顺序

    PyQt提供了方便的停靠窗口控件,我们可以很方便的编写一个停靠窗口,代码和效果如下: # -*- coding: utf-8 -*-from PyQt4 import QtGui, QtCore cl ...