配置和创建一个hibernate简单应用

1.配置

到http://hibernate.org/orm/下载hibernate包然后解压

在eclipse中新建一个java project，如名为hibernate_test

再所建工程中新建一个文件夹libs

将\lib\required下的所有jar包，(另外数据库驱动的jar包，我使用mysql所以导入了mysql-connector-5.1.26-bin.jar,另外还有做测试用的junit包) 复制到libs文件夹下

将所有的jar包选中右键build path->add to path

再将\project\etc下的hibernate.cfg.xml和log4j.properties复制到src下

配置完成

2.

案例

<!DOCTYPE hibernate-configuration PUBLIC

"-//Hibernate/Hibernate Configuration DTD 3.0//EN"

"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">

<hibernate-configuration>

<session-factory>

<property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property>

<property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>

<property name="hibernate.connection.url">jdbc:mysql:///test</property>

<property name="hibernate.connection.username">root</property>

<property name="hibernate.connection.password">959511586</property>

<mapping resource="com/kotar/entity/Student.hbm.xml"/>

</session-factory>

</hibernate-configuration>

1）在hibernate.cfg.xml中添加如下，配置数据库（红色部分是数据库中创建好的的schema）

2）定义持久化类

package com.kotar.entity;

import java.io.Serializable;

public class Student implements Serializable {

/**

*

*/

private static final long serialVersionUID = 1L;

private int id;

private String name;

private int age;

public Student() {

// TODO Auto-generated constructor stub

}

public int getId() {

return id;

}

public void setId(int id) {

this.id = id;

}

public String getName() {

return name;

}

public void setName(String name) {

this.name = name;

}

public int getAge() {

return age;

}

public void setAge(int age) {

this.age = age;

}

}

配置对象关系映射文件（Student.hbm.xml）持久化类和数据库表的对应关系

<!DOCTYPE hibernate-mapping PUBLIC

"-//Hibernate/Hibernate Mapping DTD 3.0//EN"

"http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">

<hibernate-mapping>

<class name="com.kotar.entity.Student" table="stu_tab">

<id name="id" column="stu_id">

<generator class="native"></generator>

</id>

<property name="name" column="stu_name"></property>

<property name="age" column="stu_age"></property>

</class>

</hibernate-mapping>

3）在hibernate.cfg.xml中注册对象关系映射文件

<mapping resource="com/kotar/entity/Student.hbm.xml"/>

4）编写测试类，对数据库操作

package com.kotar.test;

import org.hibernate.Session;

import org.hibernate.SessionFactory;

import org.hibernate.boot.registry.StandardServiceRegistry;

import org.hibernate.boot.registry.StandardServiceRegistryBuilder;

import org.hibernate.cfg.Configuration;

import org.hibernate.tool.hbm2ddl.SchemaExport;

import org.junit.Test;

import com.kotar.entity.Student;

public class StudentTest {

@Test

public void createTable() {

Configuration cfg=new Configuration().configure();

SchemaExport se=new SchemaExport(cfg);

se.create(true, true);

}

@Test

public void insert(){

Configuration cfg=new Configuration().configure();

StandardServiceRegistryBuilder ssrb=new StandardServiceRegistryBuilder().applySettings(cfg.getProperties());

StandardServiceRegistry serviceRegistry= ssrb.build();

SessionFactory sessionFactory=cfg.buildSessionFactory(serviceRegistry);

//获取Session

Session session=sessionFactory.openSession();

//获取事务

org.hibernate.Transaction transaction=session.beginTransaction();

//输入数据

Student student=new Student();

student.setAge(17);

student.setName("kotar");

try {

session.save(student);

transaction.commit();

} catch (Exception e) {

try {

transaction.rollback();

} catch (IllegalStateException e1) {

// TODO Auto-generated catch block

e1.printStackTrace();

}

}finally {

session.clear();

}

}

}

先后用junit运行测试方法createTable（）和insert（）

结果如下