hdu 1342(DFS)
Lotto
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 2933 Accepted Submission(s): 1386
a Lotto I have ever played, one has to select 6 numbers from the set
{1,2,...,49}. A popular strategy to play Lotto - although it doesn't
increase your chance of winning - is to select a subset S containing k
(k>6) of these 49 numbers, and then play several games with choosing
numbers only from S. For example, for k=8 and S = {1,2,3,5,8,13,21,34}
there are 28 possible games: [1,2,3,5,8,13], [1,2,3,5,8,21],
[1,2,3,5,8,34], [1,2,3,5,13,21], ... [3,5,8,13,21,34].
Your job
is to write a program that reads in the number k and the set S and then
prints all possible games choosing numbers only from S.
input file will contain one or more test cases. Each test case consists
of one line containing several integers separated from each other by
spaces. The first integer on the line will be the number k (6 < k
< 13). Then k integers, specifying the set S, will follow in
ascending order. Input will be terminated by a value of zero (0) for k.
each test case, print all possible games, each game on one line. The
numbers of each game have to be sorted in ascending order and separated
from each other by exactly one space. The games themselves have to be
sorted lexicographically, that means sorted by the lowest number first,
then by the second lowest and so on, as demonstrated in the sample
output below. The test cases have to be separated from each other by
exactly one blank line. Do not put a blank line after the last test
case.
#include<iostream>
#include<cstdio>
#include<cmath>
#include<map>
#include<cstdlib>
#include<vector>
#include<set>
#include<queue>
#include<cstring>
#include<string.h>
#include<algorithm>
#define INF 0x3f3f3f3f
typedef long long ll;
typedef unsigned long long LL;
using namespace std;
int a[15],b[15];
int visited[15],n;
void DFS(int t,int num)
{
if(num==6)
{
for(int i=0;i<5;i++)
printf("%d ",b[i]);
printf("%d\n",b[5]);
return;
}
for(int i=t;i<n;i++)
{
if(visited[i]==0)
{
visited[i]=1;
b[num]=a[i];
DFS(i+1,num+1);
visited[i]=0;
}
}
} int main()
{
int tt=0;
while(scanf("%d",&n)!=EOF)
{
if(n==0)break;
for(int i=0;i<n;i++)
scanf("%d",&a[i]);
if(tt)cout<<endl;
tt++;
memset(visited,0,sizeof(visited));
DFS(0,0);
}
return 0;
}
hdu 1342(DFS)的更多相关文章
- F - JDG HDU - 2112 (最短路)&& E - IGNB HDU - 1242 (dfs)
经过锦囊相助,海东集团终于度过了危机,从此,HDU的发展就一直顺风顺水,到了2050年,集团已经相当规模了,据说进入了钱江肉丝经济开发区500强.这时候,XHD夫妇也退居了二线,并在风景秀美的诸暨市浬 ...
- F - Auxiliary Set HDU - 5927 (dfs判断lca)
题目链接: F - Auxiliary Set HDU - 5927 学习网址:https://blog.csdn.net/yiqzq/article/details/81952369题目大意一棵节点 ...
- hdu - 1072(dfs剪枝或bfs)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1072 思路:深搜每一个节点,并且进行剪枝,记录每一步上一次的s1,s2:如果之前走过的时间小于这一次, ...
- HDU——2647Reward(DFS或差分约束)
Reward Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Sub ...
- P - Sudoku Killer HDU - 1426(dfs + map统计数据)
P - Sudoku Killer HDU - 1426 自从2006年3月10日至11日的首届数独世界锦标赛以后,数独这项游戏越来越受到人们的喜爱和重视. 据说,在2008北京奥运会上,会将数独列为 ...
- hdu 1142(DFS+dijkstra)
#include<iostream> #include<cstdio> #include<cmath> #include<map> #include&l ...
- hdu 1015(DFS)
Safecracker Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total ...
- hdu 1181(DFS)变 形 课
变形课 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/65536 K (Java/Others)Total Submis ...
- J - Assign the task - hdu 3974(DFS建树+简单线段树)
题意:给一些节点简单额对应关系,可以组成一个树,如果树的某一个节点更新那么他的所有子节点都要更新,中间,会有一些查询 分析:题意倒也不难理解,但是但是不知道怎么建树...于是自能百度,看了kuangb ...
随机推荐
- try it, then you know . Emacs
原来Emacs能做时间管理 http://sachachua.com/blog/2012/07/transcript-emacs-chat-john-wiegley/ http://blog.csd ...
- SUID, SGID, SBIT
基本上SUID有这样的限制与功能: SUID权限仅对二进位程序(binaryprogram)有效,不能用在shellscript上面: 运行者对於该程序需要具有x的可运行权限: 本权限仅在运行该程序的 ...
- CentOS 7 安装 MySQL
转自:http://www.centoscn.com/mysql/2016/0315/6844.html 环境 CentOS 7.1 (64-bit system) MySQL 5.6.24 Cent ...
- C# 解析JSON格式数据
JSON简介 JSON(全称为JavaScript ObjectNotation) 是一种轻量级的数据交换格式.它是基于JavaScript语法标准的一个子集.JSON采用完全独立于语言的文本格式,可 ...
- taiyi_interview(Introduction To Database Refactoring)
Introduction To Database Refactoring 原文链接:by Scott W. Ambler:http://www.tdan.com/view-articles/5010/ ...
- mysql workbench
下载地址:http://dev.mysql.com/downloads/ 详情:http://baike.baidu.com/link?url=sWV3b2pWdr8cvCxEZYrB9CzLD9Bl ...
- 利用 PortableBasemapServer 发布地图服务
前段时间需要给自己的C/S系统加一个地图,但是没有数据,于是就想到了使用网上的切片地图,但是C/S系统又不能联网,于是就想本地发布切片服务来使用. 本来想用ArcGIS Server来发布从网上下载的 ...
- iOS10 的适配问题,你遇到了吗?导航栏标题和返回按钮神奇的消失了
苹果系统升级后好多应用都发了新版本来适配,今天就来分享一下我的适配历程. 首先是出现的问题: 1.push一个控制器,返回按钮和标题神奇的消失了,打开三维视图(比较坑的是有的版本老到打不开三维视图 ) ...
- Git查看、删除、重命名远程分支和tag(转)
转:http://zengrong.net/post/1746.htm 这篇文章记录我在使用git的过程中碰到远程分支和tag的相关内容,提纲: 查看远程分支 删除远程分支和tag 删除不存在对应远程 ...
- Java(类与对象)
1>对象判等 请输入并运行以下代码,得到什么结果? public class Test { public static void main(String[] args) { // TODO Au ...