Given an array that is initially stored in one stack, sort it with one additional stacks (total 2 stacks).

After sorting the original stack should contain the sorted integers and from top to bottom the integers are sorted in ascending order.

Assumptions:

  • The given stack is not null.
  • There can be duplicated numbers in the give stack.

Requirements:

  • No additional memory, time complexity = O(n ^ 2).
public class Solution {
public void sort(LinkedList<Integer> s1) {
LinkedList<Integer> s2 = new LinkedList<Integer>();
// Write your solution here.
while (!s1.isEmpty()) {
s2.offerFirst(s1.pollFirst());
} while (!s2.isEmpty()) {
Integer cur = s2.pollFirst();
while (!s1.isEmpty() && cur > s1.peekFirst()) {
s2.offerFirst(s1.pollFirst());
}
s1.offerFirst(cur);
}
}
}

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