ASP.NET XML序列化

整理一下ASP.NET里面如何序列化实体为XML，获取解析XML内容为实体。

第一步要添加程序集引用，项目-->引用-->鼠标右键-->添加引用-->选择程序集-->System.Xml

工具类代码

    /// <summary>
    /// XML序列化公共处理类
    /// </summary>
    public static class XmlSerializeHelper
    {
        /// <summary>
        /// 将实体对象转换成XML
        /// </summary>
        /// <typeparam name="T">实体类型</typeparam>
        /// <param name="obj">实体对象</param>
        public static string XmlSerialize<T>(T obj)
        {
            try
            {
                using (StringWriter sw = new StringWriter())
                {
                    Type t = obj.GetType();
                    XmlSerializer serializer = new XmlSerializer(obj.GetType());
                    XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
                    ns.Add("", "");//把命名空间设置为空
                    serializer.Serialize(sw, obj,ns);
                    sw.Close();
                    return sw.ToString();
                }
            }
            catch (Exception ex)
            {
                throw new Exception("将实体对象转换成XML异常", ex);
            }
        }

        /// <summary>
        /// 将XML转换成实体对象
        /// </summary>
        /// <typeparam name="T">实体类型</typeparam>
        /// <param name="strXML">XML</param>
        public static T DESerializer<T>(string strXML) where T : class
        {
            try
            {
                using (StringReader sr = new StringReader(strXML))
                {
                    strXML = Regex.Replace(strXML, @"<\?xml*.*?>", "", RegexOptions.IgnoreCase);
                    XmlSerializer serializer = new XmlSerializer(typeof(T));
                    return serializer.Deserialize(sr) as T;
                }
            }
            catch (Exception ex)
            {
                throw new Exception("将XML转换成实体对象异常", ex);
            }
        }
    }

文件流转成XML

            var xmlDoc = new XmlDocument();
            try
            {
                var stream = new Stream();
                xmlDoc.Load(stream); //加载XML文档
                var entryInfo = XmlSerializeHelper.DESerializer<Model>(xmlDoc.OuterXml);
                if (entryInfo != null)
                {
                    // 逻辑处理
                }
                else
                {
                    //逻辑处理
                }
            }
            catch (Exception ex)
            {
                  //异常处理
            }