EFSQLserver
1.增加一条烽据
FLYNEWQKEntities dataContext = new FLYNEWQKEntities();
Log log = new Log();
log.Data1 = "tes";
dataContext.Log.Add(log);
dataContext.SaveChanges();
2.修改
FLYNEWQKEntities dataContext = new FLYNEWQKEntities();
Log log = dataContext.Log.Where(t => t.AutoID == 1).Take(1).Single();
log.Data2 = "33";
dataContext.SaveChanges();
3.删除
FLYNEWQKEntities dataContext = new FLYNEWQKEntities();
Log log = dataContext.Log.Where(t => t.AutoID == 1).Take(1).Single();
dataContext.Log.Remove(log);
dataContext.SaveChanges();
4. 列表
FLYNEWQKEntities dataContext = new FLYNEWQKEntities();
var v2 = from t in dataContext.T2_Elderly
join t0 in dataContext.T1_Set_CareLevel on t.CareLevelID equals t0.CareLevelID.ToString() //new { CareLevelID = t.CareLevelID } equals new { CareLevelID = t0.CareLevelID.ToString() }
select t0;
this.gridControl1.DataSource = v2.ToList();
5.事务
//事务
FLYNEWQKEntities dataContext = new FLYNEWQKEntities();
try
{
using (TransactionScope scope = new TransactionScope())
{
//Do something with context1
//Do something with context2
Log log = new Log();
log.Data1 = "tes";
dataContext.Log.Add(log);
//Save and discard changes
dataContext.SaveChanges();
Log log1 = dataContext.Log.Where(t => t.AutoID == log.AutoID).Take(1).Single();
log.Data2 = "33";
//Save and discard changes
dataContext.SaveChanges();
//throw new Exception("dddd");
//if we get here things are looking good.
//scope.Complete();
}
}
catch (Exception ex) {
MessageBox.Show(ex.ToString());
}
6.事务
FLYNEWQKEntities dataContext = new FLYNEWQKEntities();
//if (dataContext.Database.Connection != null)
//{
// dataContext.Database.Connection.Open();
//}
System.Data.Entity.DbContextTransaction tran = dataContext.Database.BeginTransaction();
try
{
Log log = new Log();
log.Data1 = "tes";
dataContext.Log.Add(log);
//Save and discard changes
dataContext.SaveChanges();
Log log1 = dataContext.Log.Where(t => t.AutoID == log.AutoID).Take(1).Single();
log.Data2 = "33";
//Save and discard changes
dataContext.SaveChanges();
//throw new Exception("dddd");
tran.Commit();
MessageBox.Show("保存成功!");
base.Close();
}
catch (Exception ex)
{
tran.Rollback();
MessageBox.Show(ex.Message);
}
7. 函数
https://msdn.microsoft.com/zh-cn/library/dd456847.aspx
http://www.dotblogs.com.tw/programlin/archive/2010/12/16/20179.aspx
1.Model-Defined Functions的定義是在Conceptual Model,而UDF需定義在Storage Model.
而設定的就如同EF設計stored procedure一樣,只是在一些參數上有所不同,但不幸的VS內建的EDM tools只能設計stored procedure
而無法定義UDF,所以請依上篇文章做法手動用XML Editor開啟EDM File.開啟後在<edmx:StorageModels>區段後加上
<Function Name="MYGETYEAR" ReturnType="int" Aggregate="false" BuiltIn="false" NiladicFunction="false" IsComposable="true" ParameterTypeSemantics="AllowImplicitConversion" Schema="dbo">
<Parameter Name="time" Type="datetime" Mode="In" />
</Function>
這邊的XML跟上篇文章很像,差異點在於UDF是定義於Storage Model故所有的資料型別都是sql type,這邊就不再多加說明了,紅字以外的描述都直接套用即可.
2.修改完 EDM後一樣的如同Model-Defined Functions上篇文章中的步驟二也必須在程式端定義一個類別來供給LINQ套用唯一的差別在於EdmFunctionAttribute的第一個參數namespace
改為EDM Storage Model區段中的namespace,可以在<edmx:StorageModels>後的<Schema Namespace="TestModel.Store" ../>取得
故在程式最後修改如下
要示写到 静态类,中用静态函数的来写
public static class DbFunctions
{
//[EdmFunction("FLYNEWQKModel.Store", "fun_GetPY" )]
[DbFunction("FLYNEWQKModel.Store", "fun_GetPY")]
public static string fun_GetPY(string Str)
{
throw new NotSupportedException("Direct calls are not supported.");
}
[DbFunction("FLYNEWQKModel.Store", "fun_GetFeeCount")]
public static decimal? fun_GetFeeCount(string ElderlyID, DateTime Time1)
{
throw new NotSupportedException("Direct calls are not supported.");
}
[DbFunction("FLYNEWQKModel.Store", "fun_GetHYAmount")]
public static decimal? fun_GetHYAmount(string FZHNumber)
{
throw new NotSupportedException("Direct calls are not supported.");
}
}
在<edmx:StorageModels> 段增加对函数的定义
<Function Name="fun_GetFeeCount" Aggregate="false" BuiltIn="false" NiladicFunction="false" IsComposable="true" ParameterTypeSemantics="AllowImplicitConversion" Schema="dbo" ReturnType="money">
<Parameter Name="ElderlyID" Type="nvarchar" Mode="In" />
<Parameter Name="Time1" Type="datetime" Mode="In" />
</Function>
<Function Name="fun_GetHYAmount" Aggregate="false" BuiltIn="false" NiladicFunction="false" IsComposable="true" ParameterTypeSemantics="AllowImplicitConversion" Schema="dbo" ReturnType="money">
<Parameter Name="FZHNumber" Type="nvarchar" Mode="In" />
</Function>
<Function Name="fun_GetPY" ReturnType="varchar" Aggregate="false" BuiltIn="false" Schema="dbo" NiladicFunction="false" IsComposable="true" ParameterTypeSemantics="AllowImplicitConversion" >
<Parameter Name="Str" Type="varchar" Mode="In" />
</Function>
var v1 = from c in dataContext.T2_Elderly select new { c.ElderlyName, a = SqlFunctions.GetDate(), b = DbFunctions.fun_GetPY(c.ElderlyName), c = DbFunctions.fun_GetFeeCount(c.ElderlyID, SqlFunctions.GetDate().Value), d = DbFunctions.fun_GetHYAmount(c.ElderlyID) };
EFSQLserver的更多相关文章
- 使用.net core abp framework
abp是一个有用的框架,包含许多功能,可以用来作为脚手架. 直接在官方网站上输入相应的工程名称,选择对应的版本就会下载对应的版本..net core 版本的可以使用后端框架部分来做api,包含了常用框 ...
随机推荐
- Android开发环境的安装 Eclipse
Android开发环境的安装 1 IDE Android可以使用开发的IDE有Eclipse 或者 Android Studio.Android Studio还处于v 0.1.x版本,是early a ...
- Android 代码监控apk安装,卸载,替换
public class GetBroadcast extends BroadcastReceiver { private static GetBroadcast mReceiver = new Ge ...
- poj - 2431 Expedition (优先队列)
http://poj.org/problem?id=2431 你需要驾驶一辆卡车做一次长途旅行,但是卡车每走一单位就会消耗掉一单位的油,如果没有油就走不了,为了修复卡车,卡车需要被开到距离最近的城镇, ...
- Volley HTTP库系列教程(4)Volley内置的几种请求介绍及示例,StringRequest,ImageRequest,JsonObjectRequest
Making a Standard Request Previous Next This lesson teaches you to Request a String 返回String Requ ...
- [HIHO1174]拓扑排序·一(拓扑排序)
题目链接:http://hihocoder.com/problemset/problem/1174 题意:判断一个有向图是否有环,用拓扑排序,结论就是每次取出点的时候统计一下现在剩下几个点,最后没有剩 ...
- SQL[连载3]sql的一些高级用法
SQL[连载3]sql的一些高级用法 SQL 高级教程 SQL SELECT TOP SQL SELECT TOP 子句 SELECT TOP 子句用于规定要返回的记录的数目. SELECT TOP ...
- Evaluate Reverse Polish Notation(堆栈)
Evaluate the value of an arithmetic expression in Reverse Polish Notation. Valid operators are +, -, ...
- 启用ntp服务
1. 主服务器 修改配置vi /etc/ntp.conf restrict 192.168.2.0 mask 255.255.255.0 nomodify notrap #允许别的服务器同步 serv ...
- npm使用过程中的一些错误解决办法及npm常用命令
node,npm在前端开发流程中提供了非常完善的自动化工具链,但是同样由于其复杂性导致有很多奇奇怪怪的问题.本文将记录使用过程中出现的一些问题及其解决方法备案. 国内由于gfw问题,导致很多国外的网站 ...
- HDU 2512 一卡通大冒险
我感觉这更像个数学问题. dp[i][j]表示将i件物品分成j组的方案数. 状态转移方程: dp[i][j] = dp[i-1][j-1] + j * dp[i-1][j]; 将i张卡分成j组可以有之 ...