python--for循环

1.循环输出1-10

 for i in range(1,11):
     print(i)

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 5
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 7
 8
 9
 10

2.break用法，break为跳出整个当前循环层，只跳一层。当i=5的时候退出

 for i in range(1,11):
     print(i)
     if i == 5:
         break

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 3
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 5

3.for+else用法，如果for循环正常结束，则执行else

 for i in range(1,11):
     print(i)
     # if i == 5:
     #     break
 else:
     print("循环正常退出")

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10
循环正常退出

4.for嵌套for

 for i in range(10):
     for j in range(10):
         print(i,j)

0 0
0 1
0 2
0 3
0 4
0 5
0 6
0 7
0 8
0 9
1 0
1 1
1 2
1 3
1 4
1 5
1 6
1 7
1 8
1 9
2 0
2 1
2 2
2 3
2 4
2 5
2 6
2 7
2 8
2 9
3 0
3 1
3 2
3 3
3 4
3 5
3 6
3 7
3 8
3 9
4 0
4 1
4 2
4 3
4 4
4 5
4 6
4 7
4 8
4 9
5 0
5 1
5 2
5 3
5 4
5 5
5 6
5 7
5 8
5 9
6 0
6 1
6 2
6 3
6 4
6 5
6 6
6 7
6 8
6 9
7 0
7 1
7 2
7 3
7 4
7 5
7 6
7 7
7 8
7 9
8 0
8 1
8 2
8 3
8 4
8 5
8 6
8 7
8 8
8 9
9 0
9 1
9 2
9 3
9 4
9 5
9 6
9 7
9 8
9 9

5.接4，输出i，j  且j的最大值为5

 for i in range(10):
     for j in range(10):
         if j>5:
             break
         print(i,j)

0 0
0 1
0 2
0 3
0 4
0 5
1 0
1 1
1 2
1 3
1 4
1 5
2 0
2 1
2 2
2 3
2 4
2 5
3 0
3 1
3 2
3 3
3 4
3 5
4 0
4 1
4 2
4 3
4 4
4 5
5 0
5 1
5 2
5 3
5 4
5 5
6 0
6 1
6 2
6 3
6 4
6 5
7 0
7 1
7 2
7 3
7 4
7 5
8 0
8 1
8 2
8 3
8 4
8 5
9 0
9 1
9 2
9 3
9 4
9 5

6.continue用法，continue为跳出当前循环，继续下次循环。输出i，j  且j的最小值为6

 for i in range(10):
     for j in range(10):
         if j<5:
             continue
         print(i,j)

0 5
0 6
0 7
0 8
0 9
1 5
1 6
1 7
1 8
1 9
2 5
2 6
2 7
2 8
2 9
3 5
3 6
3 7
3 8
3 9
4 5
4 6
4 7
4 8
4 9
5 5
5 6
5 7
5 8
5 9
6 5
6 6
6 7
6 8
6 9
7 5
7 6
7 7
7 8
7 9
8 5
8 6
8 7
8 8
8 9
9 5
9 6
9 7
9 8
9 9