产生指定时间区间序列、按指定单位变化时间 python实现

示例1：给定起始日期和结束日期，如何得到中间的时间序列

import datetime
def dateRange(beginDate, endDate):
    dates = []
    dt = datetime.datetime.strptime(beginDate, "%Y%m%d%H")
    date = beginDate[:]
    while date <= endDate:
        dates.append(date)
        dt = dt + datetime.timedelta(hours=1)
        date = dt.strftime("%Y%m%d%H")
    return dates

if __name__ == '__main__':
    print dateRange("", "")

具体日期格式可以自己定义;

示例2：比当前时间多加1天

import datetime
def dateRange(beginDate, endDate):
    dates = []
    dt = datetime.datetime.strptime(beginDate, "%Y%m%d%H")
    date = beginDate[:]
    while date <= endDate:
        dates.append(date)
        dt = dt + datetime.timedelta(1)  #注意这里的变化
        date = dt.strftime("%Y%m%d%H")
    return dates

if __name__ == '__main__':
    print dateRange("", "")

示例3：比当前时间多加1小时

import datetime
def dateRange(beginDate, endDate):
    dates = []
    dt = datetime.datetime.strptime(beginDate, "%Y%m%d%H")
    date = beginDate[:]
    while date <= endDate:
        dates.append(date)
        dt = dt + datetime.timedelta(hours=1) #注意这里的变化
        date = dt.strftime("%Y%m%d%H")
    return dates

if __name__ == '__main__':
    print dateRange("", "")

示例4：比当前时间多加1分钟

import datetime

def dateRange(beginDate, endDate):
    dates = []
    dt = datetime.datetime.strptime(beginDate, "%Y-%m-%d %H:%M:%S")
    date = beginDate[:]
    while date <= endDate:
        dates.append(date)
        dt = dt + datetime.timedelta(minutes=30)
        date = dt.strftime("%Y-%m-%d %H:%M:%S")
    return dates

if __name__ == '__main__': 

date=dateRange("2007-02-20 00:00:00", "2007-02-20 23:59:15")
print(date)