java.util.zip - Recreating directory structure(转)
include my own version for your reference.
We use this one to zip up photos to download so it works with various unzip programs. It preserves the directory structure and timestamps.
public static void createZipFile(File srcDir, OutputStream out,
boolean verbose) throws IOException { List<String> fileList = listDirectory(srcDir);
ZipOutputStream zout = new ZipOutputStream(out); zout.setLevel(9);
zout.setComment("Zipper v1.2"); for (String fileName : fileList) {
File file = new File(srcDir.getParent(), fileName);
if (verbose)
System.out.println(" adding: " + fileName); // Zip always use / as separator
String zipName = fileName;
if (File.separatorChar != '/')
zipName = fileName.replace(File.separatorChar, '/');
ZipEntry ze;
if (file.isFile()) {
ze = new ZipEntry(zipName);
ze.setTime(file.lastModified());
zout.putNextEntry(ze);
FileInputStream fin = new FileInputStream(file);
byte[] buffer = new byte[4096];
for (int n; (n = fin.read(buffer)) > 0;)
zout.write(buffer, 0, n);
fin.close();
} else {
ze = new ZipEntry(zipName + '/');
ze.setTime(file.lastModified());
zout.putNextEntry(ze);
}
}
zout.close();
} public static List<String> listDirectory(File directory)
throws IOException { Stack<String> stack = new Stack<String>();
List<String> list = new ArrayList<String>(); // If it's a file, just return itself
if (directory.isFile()) {
if (directory.canRead())
list.add(directory.getName());
return list;
} // Traverse the directory in width-first manner, no-recursively
String root = directory.getParent();
stack.push(directory.getName());
while (!stack.empty()) {
String current = (String) stack.pop();
File curDir = new File(root, current);
String[] fileList = curDir.list();
if (fileList != null) {
for (String entry : fileList) {
File f = new File(curDir, entry);
if (f.isFile()) {
if (f.canRead()) {
list.add(current + File.separator + entry);
} else {
System.err.println("File " + f.getPath()
+ " is unreadable");
throw new IOException("Can't read file: "
+ f.getPath());
}
} else if (f.isDirectory()) {
list.add(current + File.separator + entry);
stack.push(current + File.separator + f.getName());
} else {
throw new IOException("Unknown entry: " + f.getPath());
}
}
}
}
return list;
}
}
SEPARATOR constant is initialised with the System.getProperty("file.separator") which will give me the OS default file separator.
I would never hardcode a separator since that assumes that your code will only be deployed on a given OS
Don't use File.separator in ZIP. The separator must be "/" according to the spec. If you are on Windows, you must open file as "D:\dir\subdir\file" but ZIP entry must be "dir/subdir/file"
Just go through the source of java.util.zip.ZipEntry. It treats a ZipEntry as directory if its name ends with "/" characters. Just suffix the directory name with "/". Also you need to remove the drive prefix to make it relative.
Here is another example (recursive) which also lets you include/exclude the containing folder form the zip:
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream; public class ZipUtil { private static final int DEFAULT_BUFFER_SIZE = 1024 * 4; public static void main(String[] args) throws Exception {
zipFile("C:/tmp/demo", "C:/tmp/demo.zip", true);
} public static void zipFile(String fileToZip, String zipFile, boolean excludeContainingFolder)
throws IOException {
ZipOutputStream zipOut = new ZipOutputStream(new FileOutputStream(zipFile)); File srcFile = new File(fileToZip);
if(excludeContainingFolder && srcFile.isDirectory()) {
for(String fileName : srcFile.list()) {
addToZip("", fileToZip + "/" + fileName, zipOut);
}
} else {
addToZip("", fileToZip, zipOut);
} zipOut.flush();
zipOut.close(); System.out.println("Successfully created " + zipFile);
} private static void addToZip(String path, String srcFile, ZipOutputStream zipOut)
throws IOException {
File file = new File(srcFile);
String filePath = "".equals(path) ? file.getName() : path + "/" + file.getName();
if (file.isDirectory()) {
for (String fileName : file.list()) {
addToZip(filePath, srcFile + "/" + fileName, zipOut);
}
} else {
zipOut.putNextEntry(new ZipEntry(filePath));
FileInputStream in = new FileInputStream(srcFile); byte[] buffer = new byte[DEFAULT_BUFFER_SIZE];
int len;
while ((len = in.read(buffer)) != -1) {
zipOut.write(buffer, 0, len);
} in.close();
}
}
}
http://stackoverflow.com/questions/1399126/java-util-zip-recreating-directory-structure
java.util.zip - Recreating directory structure(转)的更多相关文章
- Java.util.zip adding a new file overwrites entire jar?(转)
ZIP and TAR fomats (and the old AR format) allow file append without a full rewrite. However: The Ja ...
- java.util.zip.ZipException: invalid entry size 解决办法
启动maven项目时报java.util.zip.ZipException: invalid entry size (expected 7612 but got 5955 bytes) 可能是mave ...
- [Java 基础] 使用java.util.zip包压缩和解压缩文件
reference : http://www.open-open.com/lib/view/open1381641653833.html Java API中的import java.util.zip ...
- 启动TOMCAT报错 java.util.zip.ZipException: invalid LOC header (bad signature)
报错信息大致如下所示: at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect. ...
- java.util.zip.ZipOutputStream压缩无乱码(原创)
package io; import java.io.BufferedOutputStream; import java.io.BufferedReader; import java.io.FileI ...
- [java bug记录] java.util.zip.ZipException: invalid code lengths set
1. 描述:将代码迁移到maven工程,其中用ZipInputStream读取/src/main/resources下的zip文件时报错:“java.util.zip.ZipException: in ...
- java.util.zip压缩打包文件总结二: ZIP解压技术
一.简述 解压技术和压缩技术正好相反,解压技术要用到的类:由ZipInputStream通过read方法对数据解压,同时需要通过CheckedInputStream设置冗余校验码,如: Checked ...
- java.util.zip压缩打包文件总结一:压缩文件及文件下面的文件夹
一.简述 zip用于压缩和解压文件.使用到的类有:ZipEntry ZipOutputStream 二.具体实现代码 package com.joyplus.test; import java.io ...
- java.util.zip.GZIPInputStream.readUByte,Not in GZIP format错误处理
问题一: 使用webclient抓取网页时报错:(GZIPInputStream.java:207) atjava.util.zip.GZIPInputStream.readUShort(GZIPIn ...
随机推荐
- android开发过程中遇到的小问题
转自:http://www.sctarena.com/Article/Article.asp?nid=50701.在编写xml布局的时候,总是提示[Accessibility] Missing ...
- 演练5-5:Contoso大学校园管理系统5
Contoso University示例网站演示如何使用Entity Framework 5创建ASP.NET MVC 4应用程序. Entity Framework有三种处理数据的方式: Data ...
- Android4.2以及最新SDK的尝鲜使用
谷歌已经公布了Android4.2,而且也对应的更新了SDK到4.2.事实上最基本的是谷歌这次帮开发人员把eclipse.ADT.SDK整合 到了一起,我们仅仅须要下载一个ADT Boundle,就能 ...
- [译]TCP和UDP的区别
译者:华科小涛:http://www.cnblogs.com/hust-ghtao/ 最近开始学习计算机网络的知识,找了些英文的资料,翻译过来,一是为了深入学习网络,也是为了锻炼自己看英文文档的能力. ...
- C语言,题目:函数调用,内存,malloc找错
malloc int* p = (int *) malloc (sizeof(int)*128); //分配128个(可根据实际需要替换该数值)整型存储单元,并将这128个连续的整型存储单元的首地址存 ...
- Cloud Foundry 中国群英会【上海站、成都站】资料宣传
关注云计算和PaaS层的童鞋可以了解下: http://www.cloudfoundry-heroes-summit.com/shanghai http://www.cloudfoundry-hero ...
- 京JS 2013 - A two-day conference in Beijing for the JavaScript and Node.js community
京JS 2013 - A two-day conference in Beijing for the JavaScript and Node.js community 关于技术大会 京JS 2013 ...
- CodeForces 446B DZY Loves Modification
题意: k次操作 每次选择一行或一列 得到所选数字的和 并将所选数字同一时候减去p 问最多得到多少 思路: 重点在消除行列间的相互影响 因为每选一行全部列所相应的和都会-p 那么假设选了i次 ...
- SEO分享:我为什么会有这么多的优质外链资源?
前面小浪发了一篇文章" [完整版]我是怎样3个月把800指数的词做上首页的.",非常多人看了之后都表示非常佩服.顽强的运行力.确实SEO就是要顽强的运行力,也有人说吹牛吧,一天50 ...
- Python Challenge 第四题
这一题没有显示提示语,仅仅有一幅图片,图片也看不出什么名堂,于是直接查看源代码,源代码例如以下: <html> <head> <title>follow the c ...