Codeforces 505A Mr. Kitayuta's Gift 暴力
1 second
256 megabytes
standard input
standard output
Mr. Kitayuta has kindly given you a string s consisting of lowercase English letters. You are asked to insert exactly one lowercase English letter into s to make it a palindrome. A palindrome is a string that reads the same forward and backward. For example, "noon", "testset" and "a" are all palindromes, while "test" and "kitayuta" are not.
You can choose any lowercase English letter, and insert it to any position of s, possibly to the beginning or the end of s. You have to insert a letter even if the given string is already a palindrome.
If it is possible to insert one lowercase English letter into s so that the resulting string will be a palindrome, print the string after the insertion. Otherwise, print "NA" (without quotes, case-sensitive). In case there is more than one palindrome that can be obtained, you are allowed to print any of them.
The only line of the input contains a string s (1 ≤ |s| ≤ 10). Each character in s is a lowercase English letter.
If it is possible to turn s into a palindrome by inserting one lowercase English letter, print the resulting string in a single line. Otherwise, print "NA" (without quotes, case-sensitive). In case there is more than one solution, any of them will be accepted.
revive
reviver
ee
eye
kitayuta
NA
For the first sample, insert 'r' to the end of "revive" to obtain a palindrome "reviver".
For the second sample, there is more than one solution. For example, "eve" will also be accepted.
For the third sample, it is not possible to turn "kitayuta" into a palindrome by just inserting one letter.
#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
#define maxn 100001
const int inf=0x7fffffff; //无限大
int check(string s)
{
for(int i=;i<s.size();i++)
{
if(s[i]!=s[s.size()--i])
return ;
}
return ;
}
int main()
{
string s;
cin>>s ;
for(char c='a';c<='z';c++)
{
for(int i=;i<=s.size();i++)
{
string a = s;
string b=" ";
b[] = c;
a.insert(i,b);
if (check(a))
{
cout<<a<<endl;
return ;
}
}
}
cout<<"NA"<<endl;
return ;
}
Codeforces 505A Mr. Kitayuta's Gift 暴力的更多相关文章
- codeforces 505A. Mr. Kitayuta's Gift 解题报告
题目链接:http://codeforces.com/problemset/problem/505/A 题目意思:给出一个长度不大于10的小写英文字符串 s,问是否能通过在字符串的某个位置插入一个字母 ...
- Codeforces Round #286 (Div. 2)A. Mr. Kitayuta's Gift(暴力,string的应用)
由于字符串的长度很短,所以就暴力枚举每一个空每一个字母,出现行的就输出.这么简单的思路我居然没想到,临场想了很多,以为有什么技巧,越想越迷...是思维方式有问题,遇到问题先分析最简单粗暴的办法,然后一 ...
- Codeforces 506E - Mr. Kitayuta's Gift(神仙矩阵乘法)
Codeforces 题目传送门 & 洛谷题目传送门 神仙题 %%%%%%%%%%%%% u1s1 感觉这道题风格很省选( 下记 \(m=|s|\),首先探讨 \(n+m\) 为偶数的情形. ...
- Codeforces 506E Mr. Kitayuta's Gift (矩阵乘法,动态规划)
描述: 给出一个单词,在单词中插入若干字符使其为回文串,求回文串的个数(|s|<=200,n<=10^9) 这道题超神奇,不可多得的一道好题 首先可以搞出一个dp[l][r][i]表示回文 ...
- 水题 Codeforces Round #286 (Div. 2) A Mr. Kitayuta's Gift
题目传送门 /* 水题:vector容器实现插入操作,暴力进行判断是否为回文串 */ #include <cstdio> #include <iostream> #includ ...
- 【CF506E】Mr. Kitayuta's Gift dp转有限状态自动机+矩阵乘法
[CF506E]Mr. Kitayuta's Gift 题意:给你一个字符串s,你需要在s中插入n个字符(小写字母),每个字符可以被插在任意位置.问可以得到多少种本质不同的字符串,使得这个串是回文的. ...
- codeforces Round 286# problem A. Mr. Kitayuta's Gift
Mr. Kitayuta has kindly given you a string s consisting of lowercase English letters. You are asked ...
- CodeForces 505B Mr. Kitayuta's Colorful Graph
Mr. Kitayuta's Colorful Graph Time Limit:1000MS Memory Limit:262144KB 64bit IO Format:%I64d ...
- codeforces 505B Mr. Kitayuta's Colorful Graph(水题)
转载请注明出处: http://www.cnblogs.com/fraud/ ——by fraud Mr. Kitayuta's Colorful Graph Mr. Kitayut ...
随机推荐
- spin_lock & mutex_lock的区别? 【转】
转自:http://blog.csdn.net/wilsonboliu/article/details/19190861 本文由该问题引入到内核锁的讨论,归纳如下 为什么需要内核锁? 多核处理器下 ...
- aarch64_g1
GAPDoc-1.5.1-12.fc26.noarch.rpm 2017-02-14 07:37 1.0M fedora Mirroring Project GAPDoc-latex-1.5.1-12 ...
- vs2010,vs2012注释快捷键
注释:VS2010是(Ctrl+E,C),VS2012是(Ctrl+K, Ctrl+C) 反注释:VS2010是(Ctrl+E,U),VS2012是(Ctrl+K, Ctrl+U)
- IntelliJ IDEA 把Json字符串 增加到IDE里 用windows记事本 能自动转换(自动增加转义字符)
- SonarQube的安装、配置与使用(windows)
onarQube是管理代码质量一个开放平台,可以快速的定位代码中潜在的或者明显的错误,下面将会介绍一下这个工具的安装.配置以及使用. 准备工作: 1.jdk(不再介绍) 2.sonarqube:htt ...
- 20155225 2016-2017-2 《Java程序设计》第六周学习总结
20155225 2016-2017-2 <Java程序设计>第六周学习总结 教材学习内容总结 java的输入输出系统 在重新指定标准输入输出时不同: 重新指定标准输入为文档输入时,是这样 ...
- js对象的属性:数据(data)属性和访问器(accessor)属性
此文为转载,原文: 深入理解对象的数据属性与访问器属性 创建对象的方式有两种:第一种,通过new操作符后面跟Object构造函数,第二种,对象字面量方式.如下 var person = new Obj ...
- Dos.ORM - 目录、介绍
引言: Dos.ORM(原Hxj.Data)于2009年发布.2015年正式开源,该组件已在数百个成熟项目中应用,是目前国内用户量最大.最活跃.最完善的国产ORM.初期开发过程中参考了NBear与My ...
- 【51nod】1709 复杂度分析
题解 考虑朴素的暴力,相当于枚举u点的每个祖先f,然后统计一下这个点f除了某个儿子里有u的那个子树之外的节点个数,乘上f到u距离的二进制1的个数 那么我们用倍增来实现这个东西,每次枚举二进制的最高位j ...
- LoadRunner脚本篇
LoadRunner脚本篇 1概述 2脚本录制 3脚本编写 4脚本调试 关 键 词:LoadRunner 性能测试脚本 摘 要:编写一个准确无误的脚本对性能测试有至关重要的意 ...