Code Signal_练习题_isLucky

Ticket numbers usually consist of an even number of digits. A ticket number is considered lucky if the sum of the first half of the digits is equal to the sum of the second half.

Given a ticket number n, determine if it's lucky or not.

Example

• For n = 1230, the output should be
  isLucky(n) = true;
• For n = 239017, the output should be
  isLucky(n) = false.

我的解答：

 def isLucky(n):
     n = str(n)
     li = []
     for i in n:
         li.append(i)
     f = int(len(li)/2)
     sum_l = 0
     sum_r = 0
     for x in li[:f]:
        sum_l += int(x)
     for y in li[f:]:
        sum_r += int(y)
     print(sum_l,sum_r)
     return sum_l == sum_r

 最后一句本来想这样写的：
 if sum_l == sum_r:
     return True
 else:
     return False
 做了几道题发现其他人都一句话完事，于是也学到了...

膜拜大佬：

def isLucky(n):
    s = str(n)
    pivot = len(s)//2
    left, right = s[:pivot], s[pivot:]
    return sum(map(int, left)) == sum(map(int, right))

刚学了map，也知道怎么回事，就是想不起来用..还是得多练练关于map的