[LintCode] Copy Books 复印书籍
Given an array A of integer with size of n( means n books and number of pages of each book) and k people to copy the book. You must distribute the continuous id books to one people to copy. (You can give book A[1],A[2] to one people, but you cannot give book A[1], A[3] to one people, because book A[1] and A[3] is not continuous.) Each person have can copy one page per minute. Return the number of smallest minutes need to copy all the books.
Given array A = [3,2,4], k = 2.
Return 5( First person spends 5 minutes to copy book 1 and book 2 and second person spends 4 minutes to copy book 3. )
Could you do this in O(n*k) time ?
[LintCode] Copy Books 复印书籍的更多相关文章
- LintCode "Copy Books"
Classic DP. The initial intuitive O(k*n^2) solution is like this: class Solution { public: /** * @pa ...
- LintCode - Copy List with Random Pointer
LintCode - Copy List with Random Pointer LintCode - Copy List with Random Pointer Web Link Descripti ...
- Copy Books
Description Given n books and the i-th book has pages[i] pages. There are k persons to copy these bo ...
- Copy Books II
Description Given n books and each book has the same number of pages. There are k persons to copy th ...
- 九章lintcode作业题
1 - 从strStr谈面试技巧与代码风格 必做题: 13.字符串查找 要求:如题 思路:(自写AC)双重循环,内循环读完则成功 还可以用Rabin,KMP算法等 public int strStr( ...
- [LintCode]——目录
Yet Another Source Code for LintCode Current Status : 232AC / 289ALL in Language C++, Up to date (20 ...
- C++图书馆管理系统项目中部分功能代码实现(书籍推荐)
bool UserServiceImpl::Compare1(Book b1,Book b2)//按照借阅次数比较{ if(b1.GetCnt() > b2.GetCnt()) { return ...
- 极简SpringBoot指南-Chapter04-基于SpringBoot的书籍管理Web服务
仓库地址 w4ngzhen/springboot-simple-guide: This is a project that guides SpringBoot users to get started ...
- 【逆向知识】GitHub:Awesome-Hacking(黑客技能列表-逆向)
0 初衷 GitHub这一份黑客技能列表很不错,包含了多个方向的安全.但目前我关注只有逆向工程与恶意代码,所以其他的被暂时略过. 虽然很感谢作者的辛勤付出,但并不打算复制粘贴全套转载.逐条整理是为了从 ...
随机推荐
- QQ互联登录 微博登录问题
qq 需要用开放平台的扣扣测试 审核通过后 开放所有用户 微博 出现获取token 个人信息失败 需要在微博里添加测试账号 审核通过后 开放所有用户
- 浅谈JSON.parse()、JSON.stringify()和eval()的作用
(1)JSON.parse 函数 var json = '{"name":"GDT","age":23,"University&q ...
- Linux内核装载和启动一个可执行程序
“平安的祝福 + 原创作品转载请注明出处 + <Linux内核分析>MOOC课程http://mooc.study.163.com/course/USTC-1000029000 ” 理解编 ...
- Loadrunner中参数化实战(1)-Sequential+Each iteration
参数化数据30条: 脚本如下,演示登录,投资,退出操作是,打印手机号: 首先验证Vugen中迭代: Sequential+Each iteration 设置迭代4次Action 结果如下:
- loadrunner通过C语言实现自定义字符出现次数截取对应字符串
void lr_custom_string_delim_save(char inputStr[500], char* outputStr, char *delim, int occrNo, int s ...
- hdu1503 最长公共子序列变形
题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=1503 题意:给出两个字符串 要求输出包含两个字符串的所有字母的最短序列.注意输出的顺序不能 ...
- Swift3.0语言教程获得一个公共的前缀
Swift3.0语言教程获得一个公共的前缀 Swift3.0语言教程获得一个公共的前缀,当在一个程序中有多个字符串时,我们需要判断是否有两个字符串有公共的前缀时,是很困难的.在NSString中的co ...
- 使用maven 如何生成源代码的jar包
http://hw1287789687.iteye.com/blog/1943157
- Codeforces 552C Vanya and Scales(思路)
题目大概说有101个质量w0.w1.w2.....w100的砝码,和一个质量m的物品,问能否在天平两边放物品和砝码使其平衡. 哎,怎么没想到..注意到w0.w1.w2.....w100—— 把m转化成 ...
- C#调用本机摄像头
这段时间一个小项目中需要调用本机的摄像头进行拍照,网上搜集了一些资料以及解决的一些小问题,在此记录以便后续使用. 硬件环境:联想C360一体机,自带摄像头 编写环境:vs2010 语言:C# WPF ...