Demo:

package com.qhong;

public class Main {
public static void main(String[] args) throws Exception {
new Thread(new Runnable(){
@Override
public void run(){
System.out.println("Before Java8");
}
}).start(); new Thread(()->System.out.println("In Java8")).start();
}
}
Before Java8
In Java8

循环:

package com.qhong;

import java.util.Arrays;
import java.util.List; public class Main {
public static void main(String[] args) throws Exception {
List<String> list= Arrays.asList("a","b","c");
for(String str:list){
System.out.println(str);
}
System.out.println("----------------");
list.forEach(x->System.out.println(x));
System.out.println("----------------");
list.forEach(System.out::println);
}
}
a
b
c
----------------
a
b
c
----------------
a
b
c

Predicate用法:

package com.qhong;

import java.util.Arrays;
import java.util.List;
import java.util.function.*;
import java.lang.*; public class Main {
public static void main(String[] args) throws Exception {
List<String> languages = Arrays.asList("Java", "Scala", "C++", "Haskell", "Lisp"); System.out.println("Languages which starts with J :");
filter(languages, (str)->str.startsWith("J")); System.out.println("Languages which ends with a ");
filter(languages, ( String str)->str.endsWith("a")); System.out.println("Print all languages :");
filter(languages, (str)->true); System.out.println("Print no language : ");
filter(languages, (str)->false); System.out.println("Print language whose length greater than 4:");
filter(languages, (str)->str.length() > 4);
} public static void filter(List<String> names, Predicate<String> condition) {
names.stream().filter((name) -> (condition.test(name)))
.forEach((name) -> {
System.out.println(name + " ");
});
}
}
Languages which starts with J :
Java
Languages which ends with a
Java
Scala
Print all languages :
Java
Scala
C++
Haskell
Lisp
Print no language :
Print language whose length greater than 4:
Scala
Haskell

code:

package com.qhong;

/**
* Created by qhong on 2017/3/14.
*/
public class Employee {
public Integer getId() {
return id;
} public void setId(Integer id) {
this.id = id;
} public String getFirstName() {
return firstName;
} public void setFirstName(String firstName) {
this.firstName = firstName;
} public String getLastName() {
return lastName;
} public void setLastName(String lastName) {
this.lastName = lastName;
} public Integer getAge() {
return age;
} public void setAge(Integer age) {
this.age = age;
} private Integer id;
private String firstName;
private String lastName;
private Integer age; public Employee(Integer id, String firstName, String lastName, Integer age){
this.id = id;
this.firstName = firstName;
this.lastName = lastName;
this.age = age;
} @Override
public String toString() {
return "\n["+this.id+","+this.firstName+","+this.lastName+","+this.age+"]";
}
}
package com.qhong;

import java.util.ArrayList;
import java.util.Arrays;
import java.util.Comparator;
import java.util.List; public class Main {
public static void main(String[] args) throws Exception {
List<Employee> employees = getEmployees(); //Sort all employees by first name
employees.sort(Comparator.comparing(e -> e.getFirstName())); //OR you can use below
//employees.sort(Comparator.comparing(Employee::getFirstName)); //Let's print the sorted list
System.out.println(employees);
System.out.println("======================"); Comparator<Employee> comparator = Comparator.comparing(e -> e.getFirstName());
employees.sort(comparator.reversed());
System.out.println(employees);
System.out.println("======================");
//Sorting on multiple fields; Group by.
Comparator<Employee> groupByComparator = Comparator.comparing(Employee::getFirstName)
.thenComparing(Employee::getLastName);
//下面这种方式不行,不知道问题
// Comparator<Employee> groupByComparator=Comparator.comparing(e->e.getFirstName())
// .thenComparing(x->x.getLastName);
employees.sort(groupByComparator);
System.out.println(employees); System.out.println("======================"); //Parallel Sorting 并行排序
Employee[] employeesArray = employees.toArray(new Employee[employees.size()]);
System.out.println(employeesArray);
//Parallel sorting
Arrays.parallelSort(employeesArray, groupByComparator); System.out.println(employeesArray);
} private static List<Employee> getEmployees(){
List<Employee> employees = new ArrayList<>();
employees.add(new Employee(1,"Lokesh", "Gupta", 32));
employees.add(new Employee(2,"Aman", "Sharma", 28));
employees.add(new Employee(3,"Aakash", "Yaadav", 52));
employees.add(new Employee(4,"James", "Hedge", 72));
employees.add(new Employee(5,"David", "Kameron", 19));
employees.add(new Employee(6,"Yash", "Chopra", 25));
employees.add(new Employee(7,"Karan", "Johar", 59));
employees.add(new Employee(8,"Balaji", "Subbu", 88));
employees.add(new Employee(9,"Vishu", "Bissi", 33));
employees.add(new Employee(10,"Lokesh", "Ramachandran", 60));
return employees;
}
}

Output:

[
[3,Aakash,Yaadav,52],
[2,Aman,Sharma,28],
[8,Balaji,Subbu,88],
[5,David,Kameron,19],
[4,James,Hedge,72],
[7,Karan,Johar,59],
[1,Lokesh,Gupta,32],
[10,Lokesh,Ramachandran,60],
[9,Vishu,Bissi,33],
[6,Yash,Chopra,25]]
======================
[
[6,Yash,Chopra,25],
[9,Vishu,Bissi,33],
[1,Lokesh,Gupta,32],
[10,Lokesh,Ramachandran,60],
[7,Karan,Johar,59],
[4,James,Hedge,72],
[5,David,Kameron,19],
[8,Balaji,Subbu,88],
[2,Aman,Sharma,28],
[3,Aakash,Yaadav,52]]
======================
[
[3,Aakash,Yaadav,52],
[2,Aman,Sharma,28],
[8,Balaji,Subbu,88],
[5,David,Kameron,19],
[4,James,Hedge,72],
[7,Karan,Johar,59],
[1,Lokesh,Gupta,32],
[10,Lokesh,Ramachandran,60],
[9,Vishu,Bissi,33],
[6,Yash,Chopra,25]]
======================
[Lcom.qhong.Employee;@7530d0a
[Lcom.qhong.Employee;@7530d0a

http://www.importnew.com/16436.html

http://www.cnblogs.com/figure9/archive/2014/10/24/4048421.html

https://wizardforcel.gitbooks.io/java8-tutorials/content/Java%208%20lambda%20%E6%9C%80%E4%BD%B3%E5%AE%9E%E8%B7%B5.html

http://www.codeceo.com/article/learn-java-lambda.html

http://58coding.com/article/detail/24656434620795220

http://www.ezlippi.com/blog/2015/06/java-lambda-expression.html

http://zh.lucida.me/blog/java-8-lambdas-insideout-language-features/

http://howtodoinjava.com/java-8/using-comparator-becomes-easier-with-lambda-expressions-java-8/

Java8 Lambda的更多相关文章

  1. java8 Lambda表达式的新手上车指南(1)

    背景 java9的一再推迟发布,似乎让我们恍然想起离发布java8已经过去了三年之久,java8应该算的上java语言在历代版本中变化最大的一个版本了,最大的新特性应该算得上是增加了lambda表达式 ...

  2. 【Java学习笔记之三十一】详解Java8 lambda表达式

    Java 8 发布日期是2014年3月18日,这次开创性的发布在Java社区引发了不少讨论,并让大家感到激动.特性之一便是随同发布的lambda表达式,它将允许我们将行为传到函数里.在Java 8之前 ...

  3. java8 Lambda表达式的新手上车指南(1)--基础语法和函数式接口

    背景 java9的一再推迟发布,似乎让我们恍然想起离发布java8已经过去了三年之久,java8应该算的上java语言在历代版本中变化最大的一个版本了,最大的新特性应该算得上是增加了lambda表达式 ...

  4. java8 快速入门 lambda表达式 Java8 lambda表达式10个示例

    本文由 ImportNew - lemeilleur 翻译自 javarevisited.欢迎加入翻译小组.转载请见文末要求. Java 8 刚于几周前发布,日期是2014年3月18日,这次开创性的发 ...

  5. JAVA8 Lambda初体验

    import java.util.ArrayList; import java.util.Collections; import java.util.Comparator; import java.u ...

  6. Java8 lambda表达式10个示例

    Java 8 刚于几周前发布,日期是2014年3月18日,这次开创性的发布在Java社区引发了不少讨论,并让大家感到激动.特性之一便是随同发布的lambda表达式,它将允许我们将行为传到函数里.在Ja ...

  7. java8 Lambda表达式的10个例子(转)

    原文:http://jobar.iteye.com/blog/2023477 Java8中Lambda表达式的10个例子 例1 用Lambda表达式实现Runnable接口 Java代码 收藏代码// ...

  8. Java8 Lambda表达式详解手册及实例

    先贩卖一下焦虑,Java8发于2014年3月18日,距离现在已经快6年了,如果你对Java8的新特性还没有应用,甚至还一无所知,那你真得关注公众号"程序新视界",好好系列的学习一下 ...

  9. Java8 lambda表达式10个示例<转>

    例1.用lambda表达式实现Runnable 我开始使用Java 8时,首先做的就是使用lambda表达式替换匿名类,而实现Runnable接口是匿名类的最好示例.看一下Java 8之前的runna ...

  10. java8 lambda表达式应用

    1.用lambda表达式实现Runnable非常简单// Java 8之前: new Thread(new Runnable() { @Override public void run() { Sys ...

随机推荐

  1. MQTT-SN协议乱翻之小结篇

    前言 这里简单做一些小结和对比,针对前面的协议翻译部分,一阶段的学习完结. MQTT-SN VS MQTT MQTT-SN基于MQTT原有语义,但做了很多的调整.比如: 一个CONNECT消息被拆分为 ...

  2. 卸载vue-cli

    全局安装:npm install vue-cli -g; 全局卸载:npm uninstall vue-cli -g; 查看vue版本,vue -V 回车,查看vue最新的版本.

  3. PHP内存缓存功能memcached

    PHP内存缓存功能memcached: http://blog.csdn.net/fangaoxin/article/details/6223383

  4. Resin任意文件读取漏洞

    Resin是什么 虽然看不上但是还是原因下百度百科: Resin是CAUCHO公司的产品,是一个非常流行的支持servlets和jsp的引擎,速度非常快.Resin本身包含了一个支持HTTP/1.1的 ...

  5. Jenkins反序列化漏洞cve-2017-1000353

    一.漏洞原理: 本地没有环境:参考:https://blogs.securiteam.com/index.php/archives/3171    进行学习理解记录. 首先这是一个java反序列化漏洞 ...

  6. 【BZOJ2118】墨墨的等式 最短路

    [BZOJ2118]墨墨的等式 Description 墨墨突然对等式很感兴趣,他正在研究a1x1+a2y2+…+anxn=B存在非负整数解的条件,他要求你编写一个程序,给定N.{an}.以及B的取值 ...

  7. Linux系列-Xshell连接本地VMware安装的Linux虚拟机

    一.安装VMwareWorkstation并安装RedHat虚拟机,这里安装步骤省略,网络的资料很多,大侠们不如百度或者谷歌一下,大把的资料. 二.打开本地电脑的“网络连接”,你会发现多出了2个网络适 ...

  8. PAT 1040

    字符串APPAPT中包含了两个单词"PAT",其中第一个PAT是第2位(P),第4位(A),第6位(T):第二个PAT是第3位(P),第4位(A),第6位(T). 现给定字符串,问 ...

  9. 各大互联网企业Java面试题汇总,看我如何成功拿到百度的offer

    前言 本人Java开发,5年经验,7月初来到帝都,开启面试经历,前后20天左右,主面互联网公司,一二线大公司或者是融资中的创业公司都面试过,拿了一些offer,其中包括奇虎360,最后综合决定还是去百 ...

  10. shell 变量定义技巧总结

    可以多学习和模仿操作系统自带的/etc/init.d/functions函数库脚本的定义思路,多学习Linux系统脚本中的定义,有经验的读者最终应形成一套适合自己的规范和习惯. (1)变量名及变量内容 ...