Given a nested list of integers, implement an iterator to flatten it.

Each element is either an integer, or a list -- whose elements may also be integers or other lists.

Example 1:
Given the list [[1,1],2,[1,1]], By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,1,2,1,1]. Example 2:
Given the list [1,[4,[6]]], By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,4,6].

非常精巧地使用stack。push all the nestedList into the stack from back to front,so when we pop the stack, it returns the very first element

执行hasNext()的时候,如果peek()是integer, return true;否则是一个List<NestedInteger>, 则flatten这个list,同样的,把list里的NestedInteger倒序push入栈

 /**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
*
* // @return true if this NestedInteger holds a single integer, rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds, if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // @return the nested list that this NestedInteger holds, if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
public class NestedIterator implements Iterator<Integer> {
Stack<NestedInteger> st; public NestedIterator(List<NestedInteger> nestedList) {
st = new Stack<NestedInteger>();
for (int i=nestedList.size()-1; i>=0; i--) {
st.push(nestedList.get(i));
}
} @Override
public Integer next() {
return st.pop().getInteger();
} @Override
public boolean hasNext() {
while (!st.isEmpty()) {
if (st.peek().isInteger()) return true;
List<NestedInteger> cur = st.pop().getList();
for (int i=cur.size()-1; i>=0; i--) {
st.push(cur.get(i));
}
}
return false;
}
} /**
* Your NestedIterator object will be instantiated and called as such:
* NestedIterator i = new NestedIterator(nestedList);
* while (i.hasNext()) v[f()] = i.next();
*/

Leetcode: Flatten Nested List Iterator的更多相关文章

  1. [LeetCode] Flatten Nested List Iterator 压平嵌套链表迭代器

    Given a nested list of integers, implement an iterator to flatten it. Each element is either an inte ...

  2. [LintCode] Flatten Nested List Iterator 压平嵌套链表迭代器

    Given a nested list of integers, implement an iterator to flatten it. Each element is either an inte ...

  3. [LeetCode] 341. Flatten Nested List Iterator 压平嵌套链表迭代器

    Given a nested list of integers, implement an iterator to flatten it. Each element is either an inte ...

  4. 【LeetCode】341. Flatten Nested List Iterator 解题报告(Python&C++)

    作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归+队列 栈 日期 题目地址:https://lee ...

  5. [leetcode]341. Flatten Nested List Iterator展开嵌套列表的迭代器

    Given a nested list of integers, implement an iterator to flatten it. Each element is either an inte ...

  6. 【leetcode】341. Flatten Nested List Iterator

    题目如下: Given a nested list of integers, implement an iterator to flatten it. Each element is either a ...

  7. LeetCode 341. Flatten Nested List Iterator

    https://leetcode.com/problems/flatten-nested-list-iterator/

  8. [Swift]LeetCode341. 压平嵌套链表迭代器 | Flatten Nested List Iterator

    Given a nested list of integers, implement an iterator to flatten it. Each element is either an inte ...

  9. Flatten Nested List Iterator

    Given a nested list of integers, implement an iterator to flatten it. Each element is either an inte ...

随机推荐

  1. java获取类路径

    String file = MessageTask3.class.getResource("").getFile(); File: public static final Stri ...

  2. 【转】Mysql中的排序规则utf8_unicode_ci、utf8_general_ci的区别总结

    Mysql中utf8_general_ci与utf8_unicode_ci有什么区别呢?在编程语言中,通常用unicode对中文字符做处理,防止出现乱码,那么在MySQL里,为什么大家都使用utf8_ ...

  3. 在serviceImpl里使用自身的方法

    @Service("tbLeaveRegisterService")@Transactionalpublic class TbLeaveRegisterServiceImpl ex ...

  4. Google物联网操作系统协同框架Weave深度解析

    1.       Google Weave框架 在2015年的Google I/O大会上,负责Android业务的桑达.皮查伊(SundarPichai)宣布了Google最新的物联网战略.这包括一个 ...

  5. Compiling Inkscape on Windows

    http://wiki.inkscape.org/wiki/index.php/Compiling_Inkscape_on_Windows http://www.oschina.net/news/80 ...

  6. The Simplified Project Management Process

    One of the challenges of explaining project management to people who are unfamiliar with the approac ...

  7. Using Change Management and Change Control Within a Project

    In any project, change is inevitable whether it comes from within the project or from external sourc ...

  8. JQuery 方法简写

    <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <m ...

  9. TCP/IP和HTTP的举例理解

    闲暇中逛博客园,看到TCP/IP和HTTP关键词,就突然想深刻理解他们(以前真的是只知皮毛),于是看了关于TCP/IP和HTTP的博文,就有了此文. 首先要引出开放系统互连参考模型(OSI:Open ...

  10. imx6 KEY_ROW4 power output high fail

    imx6 KEY_ROW4的pin设置成gpio之后,不能够输出高电平.解决方法记录于此. 参考链接: https://lists.yoctoproject.org/pipermail/meta-fr ...