B. Testing Robots
time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

The Cybernetics Failures (CF) organisation made a prototype of a bomb technician robot. To find the possible problems it was decided to carry out a series of tests. At the beginning of each test the robot prototype will be placed in cell (x0, y0) of a rectangular squared field of size x × y, after that a mine will be installed into one of the squares of the field. It is supposed to conduct exactly x·y tests, each time a mine is installed into a square that has never been used before. The starting cell of the robot always remains the same.

After placing the objects on the field the robot will have to run a sequence of commands given by string s, consisting only of characters 'L', 'R', 'U', 'D'. These commands tell the robot to move one square to the left, to the right, up or down, or stay idle if moving in the given direction is impossible. As soon as the robot fulfills all the sequence of commands, it will blow up due to a bug in the code. But if at some moment of time the robot is at the same square with the mine, it will also blow up, but not due to a bug in the code.

Moving to the left decreases coordinate y, and moving to the right increases it. Similarly, moving up decreases the x coordinate, and moving down increases it.

The tests can go on for very long, so your task is to predict their results. For each k from 0 to length(s) your task is to find in how many tests the robot will run exactly k commands before it blows up.

Input

The first line of the input contains four integers x, y, x0, y0 (1 ≤ x, y ≤ 500, 1 ≤ x0 ≤ x, 1 ≤ y0 ≤ y) — the sizes of the field and the starting coordinates of the robot. The coordinate axis X is directed downwards and axis Y is directed to the right.

The second line contains a sequence of commands s, which should be fulfilled by the robot. It has length from 1 to 100 000 characters and only consists of characters 'L', 'R', 'U', 'D'.

Output

Print the sequence consisting of (length(s) + 1) numbers. On the k-th position, starting with zero, print the number of tests where the robot will run exactly k commands before it blows up.

Sample test(s)
Input
3 4 2 2
UURDRDRL
Output
1 1 0 1 1 1 1 0 6
Input
2 2 2 2
ULD
Output
1 1 1 1
Note

In the first sample, if we exclude the probable impact of the mines, the robot's route will look like that: .

对于这题笔者认为就是简单的模拟题:

但是在这千万不能用数组和循环结构的形式来解决实现这个问题,因为有可能会导致RuntimeError;

下面就贴出笔者的代码:

#include<iostream>
#include<stdio.h>
#include<stdlib.h>
#include<memory.h>
#include<string.h>
#include<algorithm>
#include<cmath>
const int N = 30;
const int inf=-100000;
using namespace std;

int g[510][510];
int num;
int X,Y,X0,Y0,xx,yy;
int fun(char c)
{
int flag=0;
switch(c)
{
case'R':
if(yy<Y)
yy++;
break;
case'L':
if(yy>1)
yy--;
break;
case'U':
if(xx>1)
xx--;
break;
case'D':
if(xx<X)
xx++;
break;
}
if(g[xx][yy]==0)
{
flag=1;
num--;
}
g[xx][yy]=1;
return flag;
}
int main()
{
//int x,y,x0,y0;
char str[100010];
scanf("%d%d%d%d",&X,&Y,&X0,&Y0);
scanf("%s",str);
memset(g,0,sizeof(g));
num=X*Y;
num--;
xx=X0,yy=Y0;
g[X0][Y0]=1;
cout<<"1 ";
for(int i=0;i<strlen(str)-1;i++)
{
cout<<fun(str[i])<<" ";
}
if(fun(str[strlen(str)-1]))
{
num++;
cout<<num<<endl;
}
else
{
cout<<num<<endl;
}
return 0;
}

Codeforces Round #335 (Div. 2)B. Testing Robots解题报告的更多相关文章

  1. Codeforces Round #335 (Div. 2) B. Testing Robots 水题

    B. Testing Robots Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://www.codeforces.com/contest/606 ...

  2. Codeforces Round #335 (Div. 2) 606B Testing Robots(模拟)

    B. Testing Robots time limit per test 2 seconds memory limit per test 256 megabytes input standard i ...

  3. Codeforces Round #335 (Div. 2)

    水 A - Magic Spheres 这题也卡了很久很久,关键是“至少”,所以只要判断多出来的是否比需要的多就行了. #include <bits/stdc++.h> using nam ...

  4. Codeforces Round #335 (Div. 2) B

    B. Testing Robots time limit per test 2 seconds memory limit per test 256 megabytes input standard i ...

  5. Codeforces Round #335 (Div. 1) C. Freelancer's Dreams 计算几何

    C. Freelancer's Dreams Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://www.codeforces.com/contes ...

  6. Codeforces Round #335 (Div. 2) D. Lazy Student 构造

    D. Lazy Student Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/606/probl ...

  7. Codeforces Round #335 (Div. 2) C. Sorting Railway Cars 动态规划

    C. Sorting Railway Cars Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://www.codeforces.com/conte ...

  8. Codeforces Round #335 (Div. 2) A. Magic Spheres 水题

    A. Magic Spheres Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://www.codeforces.com/contest/606/ ...

  9. Codeforces Round #335 (Div. 2) D. Lazy Student 贪心+构造

    题目链接: http://codeforces.com/contest/606/problem/D D. Lazy Student time limit per test2 secondsmemory ...

随机推荐

  1. scroll

    var fScrollTopHeight = function(){ return document.documentElement&&document.documentElement ...

  2. css中>,+,~的用法

    1.>的用法 A>B选择A的所有子元素B(只选择一代) 2.+的用法 A+B选择紧随着A的兄弟元素B 3.~的用法 A~B选择位置处于A后面的所有兄弟元素B(不包含兄弟元素的子元素)

  3. STM32F407移植contiki2.6后使用LWIP库实现tcp client

    最近在做智能家居,物联网项目,用到了C下的contiki移植 经过一阵调试,终于在 STM32F407移植contiki2.6后使用LWIP库实现tcp client. 一路艰辛谁人知道....唯有留 ...

  4. jquery div拖动效果示例代码

    div拖动效果想必大家都有见到过吧,实现的方法也是有很多的,下面为大家将介绍使用jquery是如何实现的,感兴趣的朋友不要错过 复制代码代码如下: <%@ page language=" ...

  5. PYTHON代码摘录

    文件处理 #典型的读取文件代码 row_data = {} with open('PaceData.csv') as paces: column_heading = paces.readline(). ...

  6. poj 2104 K-th Number 划分树,主席树讲解

    K-th Number Input The first line of the input file contains n --- the size of the array, and m --- t ...

  7. Linux下STM32开发环境的搭建

    目录 一.概述 1.目的 2.开发环境描述 3.Eclipse构建的STM32集成开发环境结构 4.GDB / GDB Server 调试模型 二.搭建步骤 三.详细的搭建过程 1.安装eclipse ...

  8. CODEVS 1069关押罪犯

    题目描述 Description S 城现有两座监狱,一共关押着N 名罪犯,编号分别为1~N.他们之间的关系自然也极 不和谐.很多罪犯之间甚至积怨已久,如果客观条件具备则随时可能爆发冲突.我们用“怨 ...

  9. Linux系统调用列表

    转自Linux系统调用列表 一.进程控制: fork 创建一个新进程 clone 按指定条件创建子进程 execve 运行可执行文件 exit 中止进程 _exit 立即中止当前进程 getdtabl ...

  10. 安卓接入ShareSDK问题

    平台图标错乱原因  导出的jar包 包括了 style.class R$attr.class MainActivity.class R$color.class R$drawable.class R$s ...