C++ 穷举算法 鸡兔同笼

 #include "stdio.h"
 int qiongju(int head, int foot, int *chicken, int *rabbit)
 {
     int re, i, j;
     re = ;
     for (i = ; i <= head; i++)
     {
         j = head - i;
         if (i *  + j *  == foot)
         {
             re = ;
             *chicken = i;
             *rabbit = j;
         }
     }
     return re;
 }

 void main()
 {
     int chicken, rabbit, head, foot;
     int re;

     re = qiongju(head,foot,&chicken,&rabbit);

     if (re == )
     {
         printf("鸡有：%d 只，兔子有：%d 只。\n",chicken,rabbit);
     }
     else
     {
         printf("无法求解！\n");
     }
 }

注意变量 re !!!