PAT A1155 Heap Paths (30 分)——完全二叉树,层序遍历,特定dfs遍历
In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))
One thing for sure is that all the keys along any path from the root to a leaf in a max/min heap must be in non-increasing/non-decreasing order.
Your job is to check every path in a given complete binary tree, in order to tell if it is a heap or not.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (1<N≤1,000), the number of keys in the tree. Then the next line contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
Output Specification:
For each given tree, first print all the paths from the root to the leaves. Each path occupies a line, with all the numbers separated by a space, and no extra space at the beginning or the end of the line. The paths must be printed in the following order: for each node in the tree, all the paths in its right subtree must be printed before those in its left subtree.
Finally print in a line Max Heap if it is a max heap, or Min Heap for a min heap, or Not Heap if it is not a heap at all.
Sample Input 1:
8
98 72 86 60 65 12 23 50
Sample Output 1:
98 86 23
98 86 12
98 72 65
98 72 60 50
Max Heap
Sample Input 2:
8
8 38 25 58 52 82 70 60
Sample Output 2:
8 25 70
8 25 82
8 38 52
8 38 58 60
Min Heap
Sample Input 3:
8
10 28 15 12 34 9 8 56
Sample Output 3:
10 15 8
10 15 9
10 28 34
10 28 12 56
Not Heap
#include <stdio.h>
#include <algorithm>
#include <set>
#include <vector>
#include <string>
#include <iostream>
#include <queue>
using namespace std;
const int maxn=;
int tree[maxn] ;
int n;
vector<int> v;
void dfs(int st){
v.push_back(tree[st]);
if(st*>n){
if(st<=n){
for(int i=;i<v.size();i++){
printf("%d%s",v[i],i!=v.size()-?" ":"\n");
}
}
}
else{
//v.push_back(tree[st*2+1]);
dfs(st*+);
//v.pop_back();
//v.push_back(tree[st*2]);
dfs(st*); }
v.pop_back();
}
int main(){
scanf("%d",&n);
int ismax=,ismin=;
for(int i=;i<=n;i++){
scanf("%d",&tree[i]);
}
dfs();
for(int i=;i<=n;i++){
if(tree[i/]>tree[i])ismin=;
if(tree[i/]<tree[i])ismax=;
}
if(ismin==)printf("Min Heap\n");
else{
printf("%s\n",ismax==?"Max Heap":"Not Heap");
} }
注意点:完全二叉树可以直接用数组存储,根节点下标为1,左子节点为2*root,右子节点2*root+1,当当前节点的左子节点编号大于n时,该节点即为叶节点。当节点下标大于n时,这个节点为空节点。
路径遍历用dfs实现,用一个vector控制路径上的值,每递归一次记得弹出
PAT A1155 Heap Paths (30 分)——完全二叉树,层序遍历,特定dfs遍历的更多相关文章
- PAT甲级 1155 Heap Paths (30分) 堆模拟
题意分析: 给出一个1000以内的整数N,以及N个整数,并且这N个数是按照完全二叉树的层序遍历输出的序列,输出所有的整条的先序遍历的序列(根 右 左),以及判断整棵树是否是符合堆排序的规则(判断是大顶 ...
- PAT Advanced 1155 Heap Paths (30 分)
In computer science, a heap is a specialized tree-based data structure that satisfies the heap prope ...
- PAT 甲级 1147 Heaps (30 分) (层序遍历,如何建树,后序输出,还有更简单的方法~)
1147 Heaps (30 分) In computer science, a heap is a specialized tree-based data structure that sati ...
- PAT Advanced 1155 Heap Paths (30) [DFS, 深搜回溯,堆]
题目 In computer science, a heap is a specialized tree-based data structure that satisfies the heap pr ...
- [PAT] 1147 Heaps(30 分)
1147 Heaps(30 分) In computer science, a heap is a specialized tree-based data structure that satisfi ...
- PAT 甲级1057 Stack (30 分)(不会,树状数组+二分)*****
1057 Stack (30 分) Stack is one of the most fundamental data structures, which is based on the prin ...
- PAT 1004 Counting Leaves (30分)
1004 Counting Leaves (30分) A family hierarchy is usually presented by a pedigree tree. Your job is t ...
- PAT A1147 Heaps (30 分)——完全二叉树,层序遍历,后序遍历
In computer science, a heap is a specialized tree-based data structure that satisfies the heap prope ...
- PAT 垃圾箱分布(30分)dijstra
垃圾箱分布 时间限制 200 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 陈越 大家倒垃圾的时候,都希望垃圾箱距离自己比较近,但是谁都不愿意守着垃圾 ...
随机推荐
- 【高并发解决方案】7、一致性hash解读
一致性哈希算法在1997年由麻省理工学院提出的一种分布式哈希(DHT)实现算法,设计目标是为了解决因特网中的热点(Hot spot)问题,初衷和CARP十分类似.一致性哈希修正了CARP使用的简 ...
- 在C语言结构体中添加成员函数
我们在使用C语言的结构体时,经常都是只定义几个成员变量,而学过面向对象的人应该知道,我们定义类时,不只是定义了成员变量,还定义了成员方法,而类的结构和结构体非常的相似,所以,为什么不想想如何在C语言结 ...
- vue VNode如何使用,是什么东西?
前言:element ui 中有些 demo 使用了 vue 的 VNode,但是 demo 毕竟不全,所以想要了解 VNode 到底是什么,如何写出符合自己业务的代码. vue 官网介绍:渲染函数 ...
- Docker compose 与 Docker swarm
安装 docker :https://www.cnblogs.com/klvchen/p/8468855.html 安装 docker-compose : https://www.cnblogs.co ...
- BZOJ2564: 集合的面积(闵可夫斯基和 凸包)
题意 题目链接 Sol 这个东西的学名应该叫"闵可夫斯基和".就是合并两个凸包 首先我们先分别求出给出的两个多边形的凸包.合并的时候直接拿个双指针扫一下,每次选最凸的点就行了. 复 ...
- ajax请求完之前的loading加载
很多时候我们需要引入框架来开发项目,这时我们可能会遇到页面还没加载完源码出来了的问题,给用户一种不好的视觉体验,这是便需要loading加载了,来完善用户体验! /*loading.js*/ // 加 ...
- 【代码笔记】Web-HTML-颜色
一,效果图. 二,代码. <!DOCTYPE html> <html> <head> <meta charset="utf-8"> ...
- LaTeX:图形的填充(生成阴影图形)
将内网和外网看到的综合整理. 韦恩图Venn \documentclass{standalone} \usepackage{tikz} %导出为图片需要安装imagemagick %https://t ...
- Android View体系(四)从源码解析Scroller
在Android View体系(二)实现View滑动的六种方法这篇文章中我们讲到了用Scroller来实现View的滑动,所以这篇文章我们就不介绍Scroller是如何使用的了,本篇就从源码来分析下S ...
- 你不可不知的Java引用类型之——强引用
定义 强引用是使用最普遍的引用.如果一个对象具有强引用,那垃圾回收器宁愿抛出OOM(OutOfMemoryError)也不会回收它. 说明 不要被这个强字吓到,以为这个引用就很厉害,其实强引用就是程序 ...