用python3破解wingIDE
值得注意的是,python2的整除/在python3中变成了//,sha方法细化成了sha1和sha256,所以破解文件需要更改加密方式和整除部分的编码方式,经过修改后,这个文件可以完美演算出破解码,你懂得
import hashlib
import string
BASE2 = ''
BASE10 = ''
BASE16 = '0123456789ABCDEF'
BASE30 = '123456789ABCDEFGHJKLMNPQRTVWXY'
BASE36 = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ'
BASE62 = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz'
BASEMAX = string.printable
def BaseConvert(number, fromdigits, todigits, ignore_negative = True):
""" converts a "number" between two bases of arbitrary digits The input number is assumed to be a string of digits from the
fromdigits string (which is in order of smallest to largest
digit). The return value is a string of elements from todigits
(ordered in the same way). The input and output bases are
determined from the lengths of the digit strings. Negative
signs are passed through. decimal to binary
>>> baseconvert(555,BASE10,BASE2)
'1000101011' binary to decimal
>>> baseconvert('1000101011',BASE2,BASE10)
'555' integer interpreted as binary and converted to decimal (!)
>>> baseconvert(1000101011,BASE2,BASE10)
'555' base10 to base4
>>> baseconvert(99,BASE10,"0123")
'1203' base4 to base5 (with alphabetic digits)
>>> baseconvert(1203,"0123","abcde")
'dee' base5, alpha digits back to base 10
>>> baseconvert('dee',"abcde",BASE10)
'99' decimal to a base that uses A-Z0-9a-z for its digits
>>> baseconvert(257938572394L,BASE10,BASE62)
'E78Lxik' ..convert back
>>> baseconvert('E78Lxik',BASE62,BASE10)
'257938572394' binary to a base with words for digits (the function cannot convert this back)
>>> baseconvert('1101',BASE2,('Zero','One'))
'OneOneZeroOne' """
if not ignore_negative and str(number)[0] == '-':
number = str(number)[1:]
neg = 1
else:
neg = 0
x = 0
for digit in str(number):
x = x * len(fromdigits) + fromdigits.index(digit) res = ''
while x > 0:
digit = x % len(todigits)
res = todigits[int(digit)] + res
x //= len(todigits) if neg:
res = '-' + res
return res def SHAToBase30(digest):
"""Convert from a hexdigest form SHA hash into a more compact and
ergonomic BASE30 representation. This results in a 17 'digit'
number."""
tdigest = ''.join([ c for i, c in enumerate(str(digest)) if int(i) // 2 * 2 == int(i) ])
result = BaseConvert(tdigest, BASE16, BASE30)
while len(result) < 17:
result = '' + result return result
def AddHyphens(code):
"""Insert hyphens into given license id or activation request to
make it easier to read"""
return code[:5] + '-' + code[5:10] + '-' + code[10:15] + '-' + code[15:] LicenseID='CN123-12345-12345-12345'
LicenseID='ENX27-HWM6G-XYVFA-165PG'
#Copy the Request Code from the dialog
RequestCode='RW52X-G93T8-R2927-YJYFX'
hasher = hashlib.sha1()
hasher.update(bytes(RequestCode, 'ascii'))
hasher.update(bytes(LicenseID, 'ascii'))
digest = hasher.hexdigest().upper()
lichash = RequestCode[:3] + SHAToBase30(digest)
lichash=AddHyphens(lichash)
#Calculate the Activation Code
data=[7,123,23,87]
tmp=0
realcode=''
for i in data:
for j in lichash:
tmp=(tmp*i+ord(j))&0xFFFFF
realcode+=format(tmp,'=05X')
tmp=0 act30=BaseConvert(realcode,BASE16,BASE30)
while len(act30) < 17:
act30 = '' + act30
act30='AXX'+act30
act30=AddHyphens(act30)
print ("The Activation Code is: "+act30)
作为比较,把python2的破解代码放在下方:
import sha
import string
BASE2 = ''
BASE10 = ''
BASE16 = '0123456789ABCDEF'
BASE30 = '123456789ABCDEFGHJKLMNPQRTVWXY'
BASE36 = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ'
BASE62 = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz'
BASEMAX = string.printable
def BaseConvert(number, fromdigits, todigits, ignore_negative = True):
""" converts a "number" between two bases of arbitrary digits The input number is assumed to be a string of digits from the
fromdigits string (which is in order of smallest to largest
digit). The return value is a string of elements from todigits
(ordered in the same way). The input and output bases are
determined from the lengths of the digit strings. Negative
signs are passed through. decimal to binary
>>> baseconvert(555,BASE10,BASE2)
'1000101011' binary to decimal
>>> baseconvert('1000101011',BASE2,BASE10)
'555' integer interpreted as binary and converted to decimal (!)
>>> baseconvert(1000101011,BASE2,BASE10)
'555' base10 to base4
>>> baseconvert(99,BASE10,"0123")
'1203' base4 to base5 (with alphabetic digits)
>>> baseconvert(1203,"0123","abcde")
'dee' base5, alpha digits back to base 10
>>> baseconvert('dee',"abcde",BASE10)
'99' decimal to a base that uses A-Z0-9a-z for its digits
>>> baseconvert(257938572394L,BASE10,BASE62)
'E78Lxik' ..convert back
>>> baseconvert('E78Lxik',BASE62,BASE10)
'257938572394' binary to a base with words for digits (the function cannot convert this back)
>>> baseconvert('1101',BASE2,('Zero','One'))
'OneOneZeroOne' """
if not ignore_negative and str(number)[0] == '-':
number = str(number)[1:]
neg = 1
else:
neg = 0
x = long(0)
for digit in str(number):
x = x * len(fromdigits) + fromdigits.index(digit) res = ''
while x > 0:
digit = x % len(todigits)
res = todigits[digit] + res
x /= len(todigits) if neg:
res = '-' + res
return res def SHAToBase30(digest):
"""Convert from a hexdigest form SHA hash into a more compact and
ergonomic BASE30 representation. This results in a 17 'digit'
number."""
tdigest = ''.join([ c for i, c in enumerate(digest) if i / 2 * 2 == i ])
print 'tdigest',tdigest
result = BaseConvert(tdigest, BASE16, BASE30)
while len(result) < 17:
result = '' + result return result
def AddHyphens(code):
"""Insert hyphens into given license id or activation request to
make it easier to read"""
return code[:5] + '-' + code[5:10] + '-' + code[10:15] + '-' + code[15:] LicenseID='CN123-12345-12345-12345' LicenseID='ENX27-HWM6G-XYVFA-165PG'
#Copy the Request Code from the dialog
RequestCode='RW52X-G93T8-R2927-YJYFX'
hasher = sha.new() hasher.update(RequestCode)
hasher.update(LicenseID)
digest = hasher.hexdigest().upper()
lichash = RequestCode[:3] + SHAToBase30(digest)
#print RequestCode[:3] ,SHAToBase30(digest)
lichash=AddHyphens(lichash)
#Calculate the Activation Code
data=[7,123,23,87]
tmp=0
realcode=''
for i in data:
for j in lichash:
tmp=(tmp*i+ord(j))&0xFFFFF
realcode+=format(tmp,'=05X')
tmp=0 act30=BaseConvert(realcode,BASE16,BASE30)
while len(act30) < 17:
act30 = '' + act30
act30='AXX'+act30
act30=AddHyphens(act30)
print ("The Activation Code is: "+act30)
用python3破解wingIDE的更多相关文章
- python3 破解 geetest(极验)的滑块验证码
Kernel_wu 快速学习的实践者 python3 破解 geetest(极验)的滑块验证码 from selenium import webdriver from selenium.webdriv ...
- 破解wingide编辑器
先到官网下载最新版的wingide(我下载的是5.1.11-1),然后安装,打开,出现下面的界面时选第三个,然后输入“ENX27-HWM6G-XYVFA-165PG”,如下图所示: 接下来你软件会给你 ...
- python开发环境搭建(python3.3.2+wing IDE4.1)
1.下载python http://www.wingide.com/downloads下载最新版python 2.下载Wing IDE http://wingware.com/downloads/wi ...
- wing IDE破解方法
WingIDE是我接触到最好的一款Python编译器了.但其属于商业软件,注册需要一笔不小的费用.因此,这篇简短的文章主要介绍了破解WingIDE的方法.破解软件仅供学习或者教学使用,如果您是商业使用 ...
- 【Python】Part I 设置Python环境
01 设置Python环境 02 破解WingIDE (1)下载专业版wingide http://wingware.com/downloads/wing-pro/6.0.11-1/binaries& ...
- 使用uncompyle2直接反编译python字节码文件pyo/pyc
update:在Mac OS X版的September 10, 2014版(5.0.9-1)中发现安装目录中的src.zip已更换位置至WingIDE.app/Contents/Resources/b ...
- python3.6下安装wingIDE破解方法
1.wingIDE的下载: 在电脑配置好的python环境情况下,去官网下载wingIDE6,按照一般方式安装好.安装好它会自动提示你是否激活,你点击激活.然后到下一步. 2.脚本的制作: impor ...
- 最新WingIDE注册破解方法 【转】
WingIDE是Python程序语言设计的集成开发环境,具有语法标签高亮显示,命令自动完成和函数跳转列表等非常强大的功能.本文主要介绍WingIDE 5安装及注册破解方法. 注:本教程在python ...
- WingIDE注册破解方法
WingIDE是Python程序语言设计的集成开发环境,具有语法标签高亮显示,命令自动完成和函数跳转列表等非常强大的功能.本文主要介绍WingIDE 5安装及注册破解方法. 1. WingIDE 5下 ...
随机推荐
- 转载网页博客:ie7bug:div容器下的img与div存在间隙
1.代码及在浏览器上的显示 ie7: ie8+: Firefox: Chrome: 可以看出ie7上在div容器下添加img,div与img中有间隙,而在ie8+和其他浏览器上均显示正常 网页源代码如 ...
- 293. Flip Game
题目: You are playing the following Flip Game with your friend: Given a string that contains only thes ...
- Android 获取屏幕高度,宽度,状态栏高度
背景介绍: 到目前为止,android已经从1.5发展到目前的3.2,我们在写一个应用的时候,最常用到得就是获取屏幕高度,宽度,以及status bar的高度. 然而android系统变化太快了,从开 ...
- URL重写的优缺点分析
如何增强您网站地址的可读性.如何让搜索引擎快速收录到您的站点,这就需要优化您的Url,即Url的重写技术,大家熟悉的可能有很多服务器都提供Url重写技术,以前我们用的最多的就是Apache,Jboss ...
- BZOJ 2351 Matrix(哈希)
题目链接:http://61.187.179.132/JudgeOnline/problem.php?id=2351 题意:给出一个n*m的01矩阵.再给出10个A*B的小01矩阵.判断这些小的矩阵是 ...
- 收藏一些python的小技能
例子1:For .. else 语法 foo=[2,1] for i in foo: if i == 0: break else: print("i was never 0") 例 ...
- 基于Flume的美团日志收集系统(一)架构和设计
美团的日志收集系统负责美团的所有业务日志的收集,并分别给Hadoop平台提供离线数据和Storm平台提供实时数据流.美团的日志收集系统基于Flume设计和搭建而成. <基于Flume的美团日志收 ...
- codeforces 430 A Points and Segments (easy)
题意:给出n个点,m个区间,需要给这些点涂上蓝色或者红色,使得每个区间里面的点的红色的点的个数与蓝色的点的个数的差值小于1 唉,题目的标题就标注了一个easy= = 最开始做的时候对点还有区间都排序了 ...
- jquery 连写注释;siblings() 方法;jQuery 的3种滑动方法;slideUp()向上滑动;slideDown()向下滑动;slideToggle()来回滑动
首先我们看两个连写注释 第一个: /* 点击头像,显示基本资料 */ $(".f-chatTit a.avatar").click(function(){ $(this).hi ...
- hadoop NameNode 实现分析
在hadoop 整体分析中,说过nameNode主要是实现一个 blockID 到对应 dataNode的对应关系映射. 现在分析一下腰实现这个映射,nameNode还需要哪些模块. 1 为了方便用户 ...