用python3破解wingIDE
值得注意的是,python2的整除/在python3中变成了//,sha方法细化成了sha1和sha256,所以破解文件需要更改加密方式和整除部分的编码方式,经过修改后,这个文件可以完美演算出破解码,你懂得
import hashlib
import string
BASE2 = ''
BASE10 = ''
BASE16 = '0123456789ABCDEF'
BASE30 = '123456789ABCDEFGHJKLMNPQRTVWXY'
BASE36 = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ'
BASE62 = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz'
BASEMAX = string.printable
def BaseConvert(number, fromdigits, todigits, ignore_negative = True):
""" converts a "number" between two bases of arbitrary digits The input number is assumed to be a string of digits from the
fromdigits string (which is in order of smallest to largest
digit). The return value is a string of elements from todigits
(ordered in the same way). The input and output bases are
determined from the lengths of the digit strings. Negative
signs are passed through. decimal to binary
>>> baseconvert(555,BASE10,BASE2)
'1000101011' binary to decimal
>>> baseconvert('1000101011',BASE2,BASE10)
'555' integer interpreted as binary and converted to decimal (!)
>>> baseconvert(1000101011,BASE2,BASE10)
'555' base10 to base4
>>> baseconvert(99,BASE10,"0123")
'1203' base4 to base5 (with alphabetic digits)
>>> baseconvert(1203,"0123","abcde")
'dee' base5, alpha digits back to base 10
>>> baseconvert('dee',"abcde",BASE10)
'99' decimal to a base that uses A-Z0-9a-z for its digits
>>> baseconvert(257938572394L,BASE10,BASE62)
'E78Lxik' ..convert back
>>> baseconvert('E78Lxik',BASE62,BASE10)
'257938572394' binary to a base with words for digits (the function cannot convert this back)
>>> baseconvert('1101',BASE2,('Zero','One'))
'OneOneZeroOne' """
if not ignore_negative and str(number)[0] == '-':
number = str(number)[1:]
neg = 1
else:
neg = 0
x = 0
for digit in str(number):
x = x * len(fromdigits) + fromdigits.index(digit) res = ''
while x > 0:
digit = x % len(todigits)
res = todigits[int(digit)] + res
x //= len(todigits) if neg:
res = '-' + res
return res def SHAToBase30(digest):
"""Convert from a hexdigest form SHA hash into a more compact and
ergonomic BASE30 representation. This results in a 17 'digit'
number."""
tdigest = ''.join([ c for i, c in enumerate(str(digest)) if int(i) // 2 * 2 == int(i) ])
result = BaseConvert(tdigest, BASE16, BASE30)
while len(result) < 17:
result = '' + result return result
def AddHyphens(code):
"""Insert hyphens into given license id or activation request to
make it easier to read"""
return code[:5] + '-' + code[5:10] + '-' + code[10:15] + '-' + code[15:] LicenseID='CN123-12345-12345-12345'
LicenseID='ENX27-HWM6G-XYVFA-165PG'
#Copy the Request Code from the dialog
RequestCode='RW52X-G93T8-R2927-YJYFX'
hasher = hashlib.sha1()
hasher.update(bytes(RequestCode, 'ascii'))
hasher.update(bytes(LicenseID, 'ascii'))
digest = hasher.hexdigest().upper()
lichash = RequestCode[:3] + SHAToBase30(digest)
lichash=AddHyphens(lichash)
#Calculate the Activation Code
data=[7,123,23,87]
tmp=0
realcode=''
for i in data:
for j in lichash:
tmp=(tmp*i+ord(j))&0xFFFFF
realcode+=format(tmp,'=05X')
tmp=0 act30=BaseConvert(realcode,BASE16,BASE30)
while len(act30) < 17:
act30 = '' + act30
act30='AXX'+act30
act30=AddHyphens(act30)
print ("The Activation Code is: "+act30)
作为比较,把python2的破解代码放在下方:
import sha
import string
BASE2 = ''
BASE10 = ''
BASE16 = '0123456789ABCDEF'
BASE30 = '123456789ABCDEFGHJKLMNPQRTVWXY'
BASE36 = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ'
BASE62 = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz'
BASEMAX = string.printable
def BaseConvert(number, fromdigits, todigits, ignore_negative = True):
""" converts a "number" between two bases of arbitrary digits The input number is assumed to be a string of digits from the
fromdigits string (which is in order of smallest to largest
digit). The return value is a string of elements from todigits
(ordered in the same way). The input and output bases are
determined from the lengths of the digit strings. Negative
signs are passed through. decimal to binary
>>> baseconvert(555,BASE10,BASE2)
'1000101011' binary to decimal
>>> baseconvert('1000101011',BASE2,BASE10)
'555' integer interpreted as binary and converted to decimal (!)
>>> baseconvert(1000101011,BASE2,BASE10)
'555' base10 to base4
>>> baseconvert(99,BASE10,"0123")
'1203' base4 to base5 (with alphabetic digits)
>>> baseconvert(1203,"0123","abcde")
'dee' base5, alpha digits back to base 10
>>> baseconvert('dee',"abcde",BASE10)
'99' decimal to a base that uses A-Z0-9a-z for its digits
>>> baseconvert(257938572394L,BASE10,BASE62)
'E78Lxik' ..convert back
>>> baseconvert('E78Lxik',BASE62,BASE10)
'257938572394' binary to a base with words for digits (the function cannot convert this back)
>>> baseconvert('1101',BASE2,('Zero','One'))
'OneOneZeroOne' """
if not ignore_negative and str(number)[0] == '-':
number = str(number)[1:]
neg = 1
else:
neg = 0
x = long(0)
for digit in str(number):
x = x * len(fromdigits) + fromdigits.index(digit) res = ''
while x > 0:
digit = x % len(todigits)
res = todigits[digit] + res
x /= len(todigits) if neg:
res = '-' + res
return res def SHAToBase30(digest):
"""Convert from a hexdigest form SHA hash into a more compact and
ergonomic BASE30 representation. This results in a 17 'digit'
number."""
tdigest = ''.join([ c for i, c in enumerate(digest) if i / 2 * 2 == i ])
print 'tdigest',tdigest
result = BaseConvert(tdigest, BASE16, BASE30)
while len(result) < 17:
result = '' + result return result
def AddHyphens(code):
"""Insert hyphens into given license id or activation request to
make it easier to read"""
return code[:5] + '-' + code[5:10] + '-' + code[10:15] + '-' + code[15:] LicenseID='CN123-12345-12345-12345' LicenseID='ENX27-HWM6G-XYVFA-165PG'
#Copy the Request Code from the dialog
RequestCode='RW52X-G93T8-R2927-YJYFX'
hasher = sha.new() hasher.update(RequestCode)
hasher.update(LicenseID)
digest = hasher.hexdigest().upper()
lichash = RequestCode[:3] + SHAToBase30(digest)
#print RequestCode[:3] ,SHAToBase30(digest)
lichash=AddHyphens(lichash)
#Calculate the Activation Code
data=[7,123,23,87]
tmp=0
realcode=''
for i in data:
for j in lichash:
tmp=(tmp*i+ord(j))&0xFFFFF
realcode+=format(tmp,'=05X')
tmp=0 act30=BaseConvert(realcode,BASE16,BASE30)
while len(act30) < 17:
act30 = '' + act30
act30='AXX'+act30
act30=AddHyphens(act30)
print ("The Activation Code is: "+act30)
用python3破解wingIDE的更多相关文章
- python3 破解 geetest(极验)的滑块验证码
Kernel_wu 快速学习的实践者 python3 破解 geetest(极验)的滑块验证码 from selenium import webdriver from selenium.webdriv ...
- 破解wingide编辑器
先到官网下载最新版的wingide(我下载的是5.1.11-1),然后安装,打开,出现下面的界面时选第三个,然后输入“ENX27-HWM6G-XYVFA-165PG”,如下图所示: 接下来你软件会给你 ...
- python开发环境搭建(python3.3.2+wing IDE4.1)
1.下载python http://www.wingide.com/downloads下载最新版python 2.下载Wing IDE http://wingware.com/downloads/wi ...
- wing IDE破解方法
WingIDE是我接触到最好的一款Python编译器了.但其属于商业软件,注册需要一笔不小的费用.因此,这篇简短的文章主要介绍了破解WingIDE的方法.破解软件仅供学习或者教学使用,如果您是商业使用 ...
- 【Python】Part I 设置Python环境
01 设置Python环境 02 破解WingIDE (1)下载专业版wingide http://wingware.com/downloads/wing-pro/6.0.11-1/binaries& ...
- 使用uncompyle2直接反编译python字节码文件pyo/pyc
update:在Mac OS X版的September 10, 2014版(5.0.9-1)中发现安装目录中的src.zip已更换位置至WingIDE.app/Contents/Resources/b ...
- python3.6下安装wingIDE破解方法
1.wingIDE的下载: 在电脑配置好的python环境情况下,去官网下载wingIDE6,按照一般方式安装好.安装好它会自动提示你是否激活,你点击激活.然后到下一步. 2.脚本的制作: impor ...
- 最新WingIDE注册破解方法 【转】
WingIDE是Python程序语言设计的集成开发环境,具有语法标签高亮显示,命令自动完成和函数跳转列表等非常强大的功能.本文主要介绍WingIDE 5安装及注册破解方法. 注:本教程在python ...
- WingIDE注册破解方法
WingIDE是Python程序语言设计的集成开发环境,具有语法标签高亮显示,命令自动完成和函数跳转列表等非常强大的功能.本文主要介绍WingIDE 5安装及注册破解方法. 1. WingIDE 5下 ...
随机推荐
- 【重走Android之路】【Java面向对象基础(二)】细说String、StringBuffer和StringBuilder
[重走Android之路][基础篇(二)][Java面向对象基础]细说String.StringBuffer和StringBuilder 1.String String是Java中的一个final ...
- mars android视频学习笔记一:Activity生命周期
(1)创建:onCreate->onStart->onResume;(2)失去焦点:onPause->onStop:(3)重新获得焦点:onRestart->onStart-& ...
- 模糊查询的like '%$name$%'的sql注入避免
Ibatis like 查询防止SQL注入的方法 Ibatis like 查询防止SQL注入的方法 mysql: select * from tbl_school where school_name ...
- Web Server tomcat配置网站
tomcat配置网站 环境变量: 变量名:CATALINA_HOME 变量值:安装路径 1.在tomcat文件夹的conf"catalina"localhost(对于Tomcat6 ...
- dojo 一 require 路径问题
dojo.baseUrl baseUrl用来存储dojo.js存放 的跟目录,例如dojo.js的路径是“/web/scripts/dojo-1.3/dojo/dojo.js”则baseUrl为“/w ...
- IE JS编程需注意的内存释放问题
1.给DOM对象添加的属性是一个对象的引用.范例:var MyObject = {};document.getElementById('myDiv').myProp = MyObject;解决方法:在 ...
- 编程时 对 用途这个字段定义时 不要用using 这个英文
编程时 对 用途这个字段定义时 不要用using 这个英文
- git plumbing 更加底层命令解析-深入理解GIT
原文: http://rypress.com/tutorials/git/plumbing 本文详细介绍GIT Plumbing--更加底层的git命令,你将会对git在内部是如何管理和呈现一个项目r ...
- HDU 3573 Buy Sticks (逻辑)
题意:a,b,c三种棍子长度分别为20,28,32,现需要这三种棍子数根,欲买长为75的棍子来剪成这三种(不够长的就废弃) ,问需要买多少根. 思路:将所有棍子尽可能和其他搭配起来,使得数量减到最少. ...
- 10个实用的PHP正则表达式 (转)
http://www.iteye.com/news/23231 1. 验证E-mail地址 这是一个用于验证电子邮件的正则表达式.但它并不是高效.完美的解决方案.在此不推荐使用. $email = & ...