Description

The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:

Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…

Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.

So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A''B''C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.

Input

The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:

  • One line with the word W, a string over {'A''B''C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
  • One line with the text T, a string over {'A''B''C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.

Output

For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.

Sample Input

3
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN

Sample Output

1
3
0 给两个字符串,求第一个字符串在第二个中出现的次数
KMP最精华即next数组
参考博客:http://blog.csdn.net/zz_ylolita/article/details/50650391
 #include<cstdio>
#include<iostream>
#include<cstring>
#include<string.h>
using namespace std; char p[];
char s[];
int next[];
int lenp,lens; void getnext()
{
next[]=-;
int j=-;
for (int i=;i<lenp;i++)
{
while (j>- && p[j+]!=p[i]) j=next[j];
if (p[j+]==p[i]) j++;
next[i]=j;
}
}
int kmp()
{
int j=-,count=;
for (int i=;i<lens;i++)
{
while (j>- && p[j+]!=s[i]) j=next[j];
if (p[j+]==s[i]) j++;
if (j==lenp-)
{
count++;
j=next[j];
}
}
return count;
} int main()
{
int T;
scanf("%d",&T);
while(T--)
{
cin>>p>>s;
lenp=strlen(p);
lens=strlen(s);
getnext();
printf("%d\n",kmp());
}
return true;
}

 

POJ 3461 Oulipo(KMP裸题)的更多相关文章

  1. POJ 3641 Oulipo KMP 水题

    http://poj.org/problem?id=3461 直接KMP就好.水题 #include<cstdio> #include<cstring> const int M ...

  2. POJ 3080 Blue Jeans、POJ 3461 Oulipo——KMP应用

    题目:POJ3080 http://poj.org/problem?id=3080 题意:对于输入的文本串,输出最长的公共子串,如果长度相同,输出字典序最小的. 这题数据量很小,用暴力也是16ms,用 ...

  3. [POJ] 3461 Oulipo [KMP算法]

    Oulipo Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 23667   Accepted: 9492 Descripti ...

  4. POJ 3461 Oulipo KMP

    题意:统计其中一个子串的出现次数 题解:即KMP算法中j==m的次数 //作者:1085422276 #include <cstdio> #include <cmath> #i ...

  5. POJ 3461 Oulipo KMP算法题解

    本题就是给出非常多对字符串,然后问一个字符串在另外一个字符串出现的次数. 就是所谓的Strstr函数啦. Leetcode有这道差点儿一模一样的题目. 使用KMP算法加速.算法高手必会的算法了. 另外 ...

  6. POJ 3461 Oulipo KMP算法(模板)

    题意: 给两组字符串a和b,求a在b中出现的次数 关于KMP: 马拉车算法是处理回文串,而KMP是处理前后缀的相同字符串的最长长度. a | a | b | a | a | f | a | a 数组 ...

  7. HDU 1686 Oulipo kmp裸题

    kmp算法可参考 kmp算法 汇总 #include <bits/stdc++.h> using namespace std; const int maxn=1000000+5; cons ...

  8. POJ 3461 Oulipo(KMP,模式串在主串中出现次数 可重叠)

    题意:给你两个字符串p和s,求出p在s中出现的次数. 显然,我们要先把模式串放到前面,之后主串放后面,中间隔开,这样就可以根据前缀数组的性质来求了. 我先想直接把p接到s前面,之后求Next数组对st ...

  9. HDU 1686 Oulipo / POJ 3461 Oulipo / SCU 2652 Oulipo (字符串匹配,KMP)

    HDU 1686 Oulipo / POJ 3461 Oulipo / SCU 2652 Oulipo (字符串匹配,KMP) Description The French author George ...

  10. POJ 3461 Oulipo(乌力波)

    POJ 3461 Oulipo(乌力波) Time Limit: 1000MS   Memory Limit: 65536K [Description] [题目描述] The French autho ...

随机推荐

  1. 【Java】【5】List随机取值

    //shuffle 打乱顺序 Collections.shuffle(list); //随机抽取1个值 System.out.println(list.get(0)); //随机抽取N个值 Syste ...

  2. Div和Span

    Div ——层级元素,这一行不允许有其他元素(用来布局) Span ——用来修饰文本

  3. Cassandra的commitLog、memtable、 SStable

    和关系数据库一样,Cassandra在写数据之前,也需要先记录日志,称之为commitlog,然后数据才会写入到Column Family对应的Memtable中,并且Memtable中的内容是按照k ...

  4. 洛谷P1075 质因数分解

    题目描述 已知正整数n是两个不同的质数的乘积,试求出两者中较大的那个质数. 输入输出格式 输入格式: 一个正整数n. 输出格式: 一个正整数p,即较大的那个质数. 输入输出样例 输入样例#1: 复制 ...

  5. Python3红楼梦人名出现次数统计分析

    一.程序说明 本程序流程是读取红楼梦txt文件----使用jieba进行分词----借助Counter读取各人名出现次数并排序----使用matplotlib将结果可视化 这里的统计除了将“熙凤”出现 ...

  6. 使用JdbcTemplate操作数据库(二十九)

    使用JdbcTemplate操作数据库 Spring的JdbcTemplate是自动配置的,你可以直接使用@Autowired来注入到你自己的bean中来使用. 举例:我们在创建User表,包含属性n ...

  7. 命令创建Vue

    创建vue+webpack vue init webpack projectName 基础 Vue+webpack+Vux 新建文件命令 # install vue-cli npm install - ...

  8. 方便好用的 Idea mybatis 插件 MyBatisCodeHelper

    优点: 1.mapper文件(即表对应的dao)与xml文件自由切换,方便代码评审: 2.自动代码生成功能提高开发效率,mysql数据库创建好表结构,写完 pojo(注意字段类型要统一用对象类型!), ...

  9. Python中os与sys模块的区别

    os与sys模块的官方解释如下: os: This module provides a portable way of using operating system dependent functio ...

  10. Spring、SpringMVC、Hibernate详细整合实例,包含所有步骤

    Eclipse完整工程如下 Jar包如下 CSDN下载地址:https://download.csdn.net/download/zhutouaizhuwxd/9721062 其中,整个工程主要可以分 ...