PAT Advanced 1108 Finding Average (20 分)
The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A legal input is a real number in [−] and is accurate up to no more than 2 decimal places. When you calculate the average, those illegal numbers must not be counted in.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤). Then N numbers are given in the next line, separated by one space.
Output Specification:
For each illegal input number, print in a line ERROR: X is not a legal number where X is the input. Then finally print in a line the result: The average of K numbers is Y where K is the number of legal inputs and Y is their average, accurate to 2 decimal places. In case the average cannot be calculated, output Undefined instead of Y. In case K is only 1, output The average of 1 number is Y instead.
Sample Input 1:
7
5 -3.2 aaa 9999 2.3.4 7.123 2.35
Sample Output 1:
ERROR: aaa is not a legal number
ERROR: 9999 is not a legal number
ERROR: 2.3.4 is not a legal number
ERROR: 7.123 is not a legal number
The average of 3 numbers is 1.38
Sample Input 2:
2
aaa -9999
Sample Output 2:
ERROR: aaa is not a legal number
ERROR: -9999 is not a legal number
The average of 0 numbers is Undefined
乙级真题
#include <iostream>
#include <cstring>
using namespace std;
int main()
{
int N;cin>>N;
double avg=;
int val,coun=;
double a;
while(N--){
bool right=true;
char tmp[],tmp2[];
scanf("%s",tmp);
sscanf(tmp,"%lf",&a);
sprintf(tmp2,"%.2f",a);
for(int i=;i<strlen(tmp);i++)
if(tmp[i]!=tmp2[i]) right=false;
if(right&&a<=&&a>=-) {
avg+=a;
coun++;
}
else printf("ERROR: %s is not a legal number\n",tmp);
}
if(coun!=) {
if(coun>){
avg/=coun;
printf("The average of %d numbers is %.2f",coun,avg);
}else printf("The average of 1 number is %.2f",avg);
}else printf("The average of 0 numbers is Undefined"); system("pause");
return ;
}
PAT Advanced 1108 Finding Average (20 分)的更多相关文章
- PAT甲级——1108.Finding Average (20分)
The basic task is simple: given N real numbers, you are supposed to calculate their average. But wha ...
- Day 007:PAT训练--1108 Finding Average (20 分)
话不多说: 该题要求将给定的所有数分为两类,其中这两类的个数差距最小,且这两类分别的和差距最大. 可以发现,针对第一个要求,个数差距最小,当给定个数为偶数时,二分即差距为0,最小:若给定个数为奇数时, ...
- 【PAT甲级】1108 Finding Average (20分)
题意: 输入一个正整数N(<=100),接着输入一行N组字符串,表示一个数字,如果这个数字大于1000或者小于1000或者小数点后超过两位或者压根不是数字均为非法,计算合法数字的平均数. tri ...
- PAT (Advanced Level) 1108. Finding Average (20)
简单模拟. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #i ...
- PAT甲题题解-1108. Finding Average (20)-字符串处理
求给出数的平均数,当然有些是不符合格式的,要输出该数不是合法的. 这里我写了函数来判断是否符合题目要求的数字,有点麻烦. #include <iostream> #include < ...
- PAT Advanced 1152 Google Recruitment (20 分)
In July 2004, Google posted on a giant billboard along Highway 101 in Silicon Valley (shown in the p ...
- PAT Advanced 1042 Shuffling Machine (20 分)(知识点:利用sstream进行转换int和string)
Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techn ...
- PAT Advanced 1140 Look-and-say Sequence (20 分)
Look-and-say sequence is a sequence of integers as the following: D, D1, D111, D113, D11231, D112213 ...
- PAT Advanced 1073 Scientific Notation (20 分)
Scientific notation is the way that scientists easily handle very large numbers or very small number ...
随机推荐
- ubuntu16.04 TLS安装java
apt-get install software-properties-commonadd-apt-repository ppa:webupd8team/javaapt-get updateapt-g ...
- Windows服务操作帮助类
/// <summary> /// 打开系统服务 /// </summary> /// <param name="serviceName">系统 ...
- 乐字节Java编程之方法、调用、重载、递归
一.概述 方法是指人们在实践过程中为达到一定目的和效果所采取的办法.手段和解决方案. 所谓方法,就是解决一类问题的代码的有序组合,是一个功能模块.编程语言中的方法是组合在一起来执行操作语句的集合.例如 ...
- mssql sqlserver时间戳与时间格式互相转换的方法分享
转自: http://www.maomao365.com/?p=9336 摘要: 下文讲述mssql中时间戳和时间格式的转换方法,如下所示: 实验环境:sql server 2008 R2 时间戳简介 ...
- Verilog整理
1.两种实例化 2.运算符//逻辑运算+按位运算//拼接运算符 3.reg默认为1位 4.{16{1}}与{16{1'b1}}不同 5.[1023:0] in ha[3:0]=(in>>( ...
- python面向对象基础-01
面向对象(OOP)基本概念 前言 话说三国时期曹军于官渡大败袁绍,酒席之间,曹操诗兴大发,吟道:喝酒唱歌,人生真爽! 众将直呼:"丞相好诗",于是命印刷工匠刻板印刷以流传天下; 待 ...
- MongoDB writeConcern原理解析--转载
MongoDB支持客户端灵活配置写入策略(writeConcern),以满足不同场景的需求. db.collection.insert({x: 1}, {writeConcern: {w: 1}}) ...
- PHP7有没有你们说的那么牛逼
男人不能快,但程序一定要快.PHP7到底快不快,我们拭目以待. PHP7来一发 PHP7正式发布到现在已经一年半了,刚出道就号称比旧版本快了几倍,各种开源框架或系统运行在PHP7上速度效率提高了几倍, ...
- Scratch—实现一个按钮的动画效果
上次介绍了利用克隆体操作生成菜单按钮,今天讲一讲如何让一个按钮具有动画的效果:当鼠标移到某个按钮上面时,显示动画效果 让菜单按钮有虚像效果 让菜单具有逐渐变大的效果 改变菜单按钮的颜色 其他的特效都是 ...
- SAS学习笔记18 length、lengthn、lengthc函数