The 3n + 1 problem
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 50513   Accepted: 15986

Description

Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs. 
Consider the following algorithm:


		1. 		 input n

		2. 		 print n

		3. 		 if n = 1 then STOP

		4. 		 		 if n is odd then   n <-- 3n+1

		5. 		 		 else   n <-- n/2

		6. 		 GOTO 2

Given the input 22, the following sequence of numbers will be printed 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1

It is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1,000,000 (and, in fact, for many more numbers than this.)

Given an input n, it is possible to determine the number of numbers printed before the 1 is printed. For a given n this is called the cycle-length of n. In the example above, the cycle length of 22 is 16.

For any two numbers i and j you are to determine the maximum cycle length over all numbers between i and j.

Input

The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 10,000 and greater than 0.

You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j.

Output

For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).

Sample Input

1 10
100 200
201 210
900 1000

Sample Output

1 10 20
100 200 125
201 210 89
900 1000 174

Source

Duke Internet Programming Contest 1990,uva 100
简单直述式模拟,水题,主要注意输出时n,m必须按照输入时候的顺序输出,我们在程序操作时调换了大小了

poj1207的更多相关文章

  1. poj-1207 THE 3n+1 problem

    Description Problems in Computer Science are often classified as belonging to a certain class of pro ...

  2. poj1207 3n+1 problem

    The 3n + 1 problem Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 60496   Accepted: 19 ...

  3. Poj1207 The 3n + 1 problem(水题(数据)+陷阱)

    一.Description Problems in Computer Science are often classified as belonging to a certain class of p ...

  4. ACM训练计划建议(写给本校acmer,欢迎围观和指正)

    ACM训练计划建议 From:freecode#  Date:2015/5/20 前言: 老师要我们整理一份训练计划给下一届的学弟学妹们,整理出来了,费了不少笔墨,就也将它放到博客园上供大家参考. 菜 ...

  5. 【POJ水题完成表】

    题目 完成情况 poj1000:A+B problem 完成 poj1002:电话上按键对应着数字.现在给n个电话,求排序.相同的归一类 完成 poj1003:求最小的n让1+1/2+1/3+...+ ...

  6. poj 算法 分类

    转载请注明出处:優YoU http://blog.csdn.net/lyy289065406/article/details/6642573 最近AC题:2528   更新时间:2011.09.22  ...

  7. POJ1008 1013 1207 2105 2499(全部水题)

    做了一天水题,挑几个还算凑合的发上来. POJ1008 Maya Calendar 分析: #include <iostream> #include <cstdio> #inc ...

  8. POJ 水题(刷题)进阶

    转载请注明出处:優YoU http://blog.csdn.net/lyy289065406/article/details/6642573 部分解题报告添加新内容,除了原有的"大致题意&q ...

  9. ACM训练计划建议(转)

    ACM训练计划建议 From:freecode#  Date:2015/5/20 前言: 老师要我们整理一份训练计划给下一届的学弟学妹们,整理出来了,费了不少笔墨,就也将它放到博客园上供大家参考. 菜 ...

随机推荐

  1. PHPExcel导出

    第一,先查出数据库里面要生成Excel的数据,如: $data= M('User')->findAll();   //查出数据 $name='Excelfile';    //生成的Excel文 ...

  2. Nginx 配置指令的执行顺序(二)

    我们前面已经知道,当 set 指令用在 location 配置块中时,都是在当前请求的 rewrite 阶段运行的.事实上,在此上下文中,ngx_rewrite 模块中的几乎全部指令,都运行在 rew ...

  3. SAR数据下载网站

    1] http://citeseerx.ist.psu.edu/viewdoc/download?doi=10.1.1.144.2153&rep=rep1&type=pdf[2] ht ...

  4. 时间TDateTime相当于是Double,即双精度数64位,终于查到它用11位表示e,53位表示精度(整数小数一起),最前面一位表示正负

    http://docwiki.embarcadero.com/RADStudio/Seattle/en/Internal_Data_Formats 关于Double的RTL函数,好像就一个:TrySt ...

  5. TCP连接状态详解及TIME_WAIT过多的解决方法

    上图对排除和定位网络或系统故障时大有帮助,但是怎样牢牢地将这张图刻在脑中呢?那么你就一定要对这张图的每一个状态,及转换的过程有深刻地认识,不能只停留在一知半解之中.下面对这张图的11种状态详细解释一下 ...

  6. linux上应用随机启动

    这是个go项目,其他的可以参考. 首先要有个脚本比如demo #!/bin/bash # # etcd This shell script takes care of starting and sto ...

  7. flex——将Sprite控件添加到FLEX UI中

    在Flex的帮助文档里,有很多例子都是扩展Sprite类的.如果想把这些实例添加到你的s:Application中,如:addChild(DisplayObject ),肯定会出错.错误的大致意思是: ...

  8. DEDE列表页调用TAG标签

    [field:id function=GetTags(@me)/] 标签就可以调用出来了 只不过不带连接的,如果需要连接,请注释include\helpers\archive.helper.php文件 ...

  9. HttpContext详解【转】

    HttpContext 类:封装有关个别 HTTP 请求的所有 HTTP 特定的信息. 在处理请求执行链的各个阶段中,会有一个对象在各个对象之间进行传递,也即会保存请求的上下文信息,这个对象就是Htt ...

  10. 滚动栏范围位置函数(SetScrollRange、SetScrollPos、GetScrollRange、GetScrollPos)

    滚动栏的范围是一对整数,默认情况下,滚动栏的范围是0~100. SetScrollRange(hwnd,iBar,iMin,iMax,bRedraw)这里的iBar參数要么是SB_VERT,要么是SB ...