并查集模板题(The Suspects )HZNU寒假集训
The Suspects
Time Limit: 1000MS Memory Limit: 20000K
Total Submissions: 36817 Accepted: 17860
Description
Severe acute respiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, was recognized as a global threat in mid-March 2003. To minimize transmission to others, the best strategy is to separate the suspects from others.
In the Not-Spreading-Your-Sickness University (NSYSU), there are many student groups. Students in the same group intercommunicate with each other frequently, and a student may join several groups. To prevent the possible transmissions of SARS, the NSYSU collects the member lists of all student groups, and makes the following rule in their standard operation procedure (SOP).
Once a member in a group is a suspect, all members in the group are suspects.
However, they find that it is not easy to identify all the suspects when a student is recognized as a suspect. Your job is to write a program which finds all the suspects.
Input
The input file contains several cases. Each test case begins with two integers n and m in a line, where n is the number of students, and m is the number of groups. You may assume that 0 < n <= 30000 and 0 <= m <= 500. Every student is numbered by a unique integer between 0 and n−1, and initially student 0 is recognized as a suspect in all the cases. This line is followed by m member lists of the groups, one line per group. Each line begins with an integer k by itself representing the number of members in the group. Following the number of members, there are k integers representing the students in this group. All the integers in a line are separated by at least one space.
A case with n = 0 and m = 0 indicates the end of the input, and need not be processed.
Output
For each case, output the number of suspects in one line.
Sample Input
100 4
2 1 2
5 10 13 11 12 14
2 0 1
2 99 2
200 2
1 5
5 1 2 3 4 5
1 0
0 0
Sample Output
4
1
1
Source
Asia Kaohsiung 2003
题意:非典传染给出n个人,m组人,规定0号人为非典的携带者,与他一组的人都将感染
m组人中输入第一个数为k,表示这组的人数
#include<iostream>
#include<cstdlib>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<vector>
using namespace std;
int fa[];
int find(int x)
{
return x == fa[x] ? x : find(fa[x]);
} void mix(int x, int y)
{
int fx = find(x), fy = find(y);
fa[fx] = fy;
}
int main()
{
int n,m,k,a,b;
while(scanf("%d %d",&n,&m),n||m)
{
int ans=;
for(int i=;i<n;i++)
{
fa[i]=i;
}
for(int i=;i<m;i++)
{
scanf("%d",&k);
scanf("%d",&a);
for(int i=;i<k-;i++)
{
scanf("%d",&b);
mix(a,b);
}
}
int temp=find();
for(int i=;i<n;i++)
{
if(find(i)==temp)
ans++;
}
printf("%d\n",ans);
} system("pause");
return ;
}
并查集模板题(The Suspects )HZNU寒假集训的更多相关文章
- PAT题解-1118. Birds in Forest (25)-(并查集模板题)
如题... #include <iostream> #include <cstdio> #include <algorithm> #include <stri ...
- POJ1611 The Suspects 并查集模板题
题目大意:中文题不多说了 题目思路:将每一个可能患病的人纳入同一个集合,然后遍历查找每个点,如果改点点的根节点和0号学生的根节点相同,则该点可能是病人. 模板题并没有思路上的困难,只不过在遍历时需要额 ...
- HDU 1213 - How Many Tables - [并查集模板题]
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 Today is Ignatius' birthday. He invites a lot of ...
- 并查集模板题----P3367 【模板】并查集
题目描述 如题,现在有一个并查集,你需要完成合并和查询操作. 输入格式 第一行包含两个整数N.M,表示共有N个元素和M个操作. 接下来M行,每行包含三个整数Zi.Xi.Yi 当Zi=1时,将Xi与Yi ...
- 种族并查集模板题分析 -----P2024 [NOI2001]食物链
本文参考了:洛谷p2024题解 题目描述 动物王国中有三类动物 A,B,C,这三类动物的食物链构成了有趣的环形.A 吃 B,B 吃 C,C 吃 A. 现有 N 个动物,以 1 - N 编号.每个动物都 ...
- 杭电ACM省赛集训队选拔赛之热身赛-How Many Tables,并查集模板题~~
How Many Tables Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) ...
- PAT甲题题解-1114. Family Property (25)-(并查集模板题)
题意:给出每个人的家庭成员信息和自己的房产个数与房产总面积,让你统计出每个家庭的人口数.人均房产个数和人均房产面积.第一行输出家庭个数,随后每行输出家庭成员的最小编号.家庭人口数.人均房产个数.人均房 ...
- HDU-1232/NYOJ-608畅通工程,并查集模板题,,水过~~~
畅通工程 Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) http://acm. ...
- HDU1232 畅通工程 (并查集模板题)
畅通工程 Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submis ...
随机推荐
- qualcomm memory dump 抓取方法
Memory dump是系统出现crash时常用的分析故障原因的方法,qualcomm 各子系统运行时,为方便debug,都会开辟ram log和debug variable用于保存各系统运行信息及健 ...
- 【翻译】在Ext JS 6通用应用程序中使用既共享又特定于视图的代码
原文:Using Both Shared and View-Specific Code in an Ext JS 6 Universal App 在本文,在展示如何编写Ext JS 6通用应用程序代码 ...
- 竞价拍卖理论的介绍(RTB模型中使用第二竞价模型,为的是纳什平衡,保护所有多方利益)
英式拍卖 是最普通的拍卖方式,其形式是拍卖过程中,竞价按阶梯,从低到高,依次递增.最终由出价最高者获得拍卖物品(竞买人变成买受人). The first price auction: a form o ...
- 使用LogKit进行日志操作
1. 概述 任何一个系统中,日志都是不可缺少的,现在Apache提供了两套日志工具,一个就是Log4j,另一个是本文要给出例子的LogKit. Log4j和LogKit有很多相似的地方.比如 ...
- OC学习之道:关于Block的初级学习
[objc] view plaincopy "code" class="OC"> // // main.m // Copyright (c) 2015 ...
- shell sed过滤器详解
1. Sed简介sed 是一种在线编辑器,它一次处理一行内容.处理时,把当前处理的行存储在临时缓冲区中,称为"模式空间"(pattern space),接着用sed命令处理缓冲区中 ...
- Android高级控件(五)——如何打造一个企业级应用对话列表,以QQ,微信为例
Android高级控件(五)--如何打造一个企业级应用对话列表,以QQ,微信为例 看标题这么高大上,实际上,还是运用我么拿到listview去扩展,我们讲什么呢,就是研究一下QQ,微信的这种对话列表, ...
- 简单说说Android自定义view学习推荐的方式
这几天比较受关注,挺开心的,嘿嘿. 这里给大家总结一下学习自定义view的一些技巧. 以后写自定义view可能不会写博客了,但是可以开源的我会把源码丢到github上我的地址:https://git ...
- Cocos2D场景中对象引用为nil时的判断
如果该对象在SpriteBuilder中属性中设置了name,则检查是否 [self.scene getChildByName:@"theNameOfTheNode" recurs ...
- 【一天一道LeetCode】#22. Generate Parentheses
一天一道LeetCode (一)题目 Given n pairs of parentheses, write a function to generate all combinations of we ...