Leetcode 之Binary Tree Preorder Traversal(42)

树的先序遍历。定义一个栈,先压入中间结点并访问,然后依次压入右、左结点并访问。
vector<int> preorderTraversal(TreeNode *root)
{
vector<int> result;
stack<TreeNode *>s;
TreeNode *p;
p = root;
s.push(p);
while (!s.empty())
{
p = s.top();
result.push_back(p->val);
if (p->right != nullptr)s.push(p->right);
if (p->left != nullptr)s.push(p->left);
} return result;
}
Leetcode 之Binary Tree Preorder Traversal(42)的更多相关文章
- C++版 - LeetCode 144. Binary Tree Preorder Traversal (二叉树先根序遍历,非递归)
144. Binary Tree Preorder Traversal Difficulty: Medium Given a binary tree, return the preorder trav ...
- [LeetCode] 144. Binary Tree Preorder Traversal 二叉树的先序遍历
Given a binary tree, return the preorder traversal of its nodes' values. For example:Given binary tr ...
- 【LeetCode】Binary Tree Preorder Traversal
Binary Tree Preorder Traversal Given a binary tree, return the preorder traversal of its nodes' valu ...
- [LeetCode 题解]: Binary Tree Preorder Traversal
前言 [LeetCode 题解]系列传送门: http://www.cnblogs.com/double-win/category/573499.html 1.题目描述 Given a bi ...
- 【leetcode】Binary Tree Preorder Traversal (middle)★
Given a binary tree, return the preorder traversal of its nodes' values. For example:Given binary tr ...
- Java for LeetCode 144 Binary Tree Preorder Traversal
Given a binary tree, return the preorder traversal of its nodes' values. For example: Given binary t ...
- leetcode 144. Binary Tree Preorder Traversal ----- java
Given a binary tree, return the preorder traversal of its nodes' values. For example:Given binary tr ...
- leetcode 题解:Binary Tree Preorder Traversal (二叉树的先序遍历)
题目: Given a binary tree, return the preorder traversal of its nodes' values. For example:Given binar ...
- Java [Leetcode 144]Binary Tree Preorder Traversal
题目描述: Given a binary tree, return the preorder traversal of its nodes' values. For example:Given bin ...
- (二叉树 递归) leetcode 144. Binary Tree Preorder Traversal
Given a binary tree, return the preorder traversal of its nodes' values. Example: Input: [1,null,2,3 ...
随机推荐
- BZOJ2724:[Violet 6]蒲公英——题解
http://www.lydsy.com/JudgeOnline/problem.php?id=2724 输入格式 第一行两个整数n,m,表示有n株蒲公英,m次询问. 接下来一行 n 个空格分隔的整数 ...
- VS 2013 with update安装失败(kb2829760)解决方案
update过程中遇到kb2829760补丁无法更新而导致vs安装失败的解决方法: 1.安装KB2829760: 2.安装KB2829760中文语言包: 3.安装VS2013 with update. ...
- [linux]ubuntu限速软件
wondersharper 1 安装wondershaper:sudo apt-get install wondershaper2 限制下载,上传速度(1500是限制下载速度(实际限速150k左右), ...
- win下删除oracle
关掉oralce服务. 具体方式有两种: 1.命令行下使用命令关闭服务:net stop OracleServiceORCL ,ORCL是我的实例名字,换成你的) 2.运行services.msc到系 ...
- c# string 转 GUID
提供两种方法 1.try...catch... /* * string TO guid */ private static bool ToGuid(string str) { Guid gv = ne ...
- tcp/ip 学习-通过视频学习
视频下载地址:http://down.51cto.com/zt/5518/ http://www.icoolxue.com/album/show/328 每天可以拿两个番茄钟看视频,主要目的还是了解, ...
- 【CodeForces】788E New task
[题意]n个数,每个数有附加属性0或1,初始全为1.m个操作,每个操作可以改变一个数字的属性为0或1.对于每次操作后的序列求有多少子序列满足要求:5个数字,中间3个数相等且属性为1,左右两个数小于等于 ...
- JAVA Frame 响应窗口关闭事件
/* * To change this license header, choose License Headers in Project Properties. * To change this t ...
- hdu 2717 Catch That Cow(广搜bfs)
题目链接:http://i.cnblogs.com/EditPosts.aspx?opt=1 Catch That Cow Time Limit: 5000/2000 MS (Java/Others) ...
- MapperScannerConfigurer不 property-placeholder
关于org.mybatis.spring.mapper.MapperScannerConfigurer不支持 property-placeholder 参考了http://www.oschina.ne ...