python处理dict转json，字符串中存在空格问题，导致url编码时，存在多余字符

在进行urlencode转换请求的参数时，一直多出一个空格，导致请求参数不正确，多了一个空格，解决方法一种是将dict中key-value键值对的value直接定义为字符串，另一种是value仍然为字典，增加一部转为json字符，之后再进行编码，dict转为json字符串也要注意空格问题，默认转成的json字符串还是有多余的空格

 # -*- coding: utf-8 -*-
 import json
 from urllib import parse

 """
 @version: v1.0
 @author: monleylu
 @time: 2018/2/24 10:35
 """
 urlParam = {
     "c": {
         "cc": 3402,
         "ct": 10,
         "p": 14588,
         "ov": 20,
         "dt": 0,
         "v": "9.32.1"
     }
 }
 ####
 # 正常编码结果应该为：
 # c=%7B%22cc%22%3A3402%2C%22ct%22%3A10%2C%22p%22%3A14588%2C%22ov%22%3A20%2C%22dt%22%3A0%2C%22v%22%3A%229.32.1%22%7D
 # 可以看到多了个+ 加号
 ###
 print("直接对字典进行编码后结果:\r\n" + parse.urlencode(urlParam))

 b = {"cc":3402,"ct":10,"p":14588,"ov":20,"dt":0,"v":"9.32.1"}
 # 可以看到默认格式参数化时，会多出一个空格
 print("使用默认参数转换dict到json字符串：\r\n" + json.dumps(b))

 print("非默认参数转换dict到json字符串：\r\n" + json.dumps(b, separators=(',', ':')))
 a = {"c": json.dumps(b, separators=(',', ':'))}
 print(parse.urlencode(a))

 #一种解决方法
 urlParam["c"]=json.dumps((urlParam["c"]),separators=(',', ':'))
 print("进行编码后结果:\r\n" + parse.urlencode(urlParam))

 #另一种解决方法,这种方法仍然要注意字符串中间的空格，不是太推荐这种方法
 urlParam = { "c": '{"cc":3402,"ct":10,"p":14588,"ov":20,"dt":0,"v":"9.32.1"}'}
 print("进行编码后结果2:\r\n" + parse.urlencode(urlParam))

输出结果
直接对字典进行编码后结果:
c=%7B%27cc%27%3A+3402%2C+%27ct%27%3A+10%2C+%27p%27%3A+14588%2C+%27ov%27%3A+20%2C+%27dt%27%3A+0%2C+%27v%27%3A+%279.32.1%27%7D
使用默认参数转换dict到json字符串：
{"cc": 3402, "ct": 10, "p": 14588, "ov": 20, "dt": 0, "v": "9.32.1"}
非默认参数转换dict到json字符串：
{"cc":3402,"ct":10,"p":14588,"ov":20,"dt":0,"v":"9.32.1"}
c=%7B%22cc%22%3A3402%2C%22ct%22%3A10%2C%22p%22%3A14588%2C%22ov%22%3A20%2C%22dt%22%3A0%2C%22v%22%3A%229.32.1%22%7D
进行编码后结果:
c=%7B%22cc%22%3A3402%2C%22ct%22%3A10%2C%22p%22%3A14588%2C%22ov%22%3A20%2C%22dt%22%3A0%2C%22v%22%3A%229.32.1%22%7D
进行编码后结果2:
c=%7B%22cc%22%3A3402%2C%22ct%22%3A10%2C%22p%22%3A14588%2C%22ov%22%3A20%2C%22dt%22%3A0%2C%22v%22%3A%229.32.1%22%7D