Codeforces Round #423 A Restaurant Tables(模拟)
1 second
256 megabytes
standard input
standard output
In a small restaurant there are a tables for one person and b tables for two persons.
It it known that n groups of people come today, each consisting of one or two people.
If a group consist of one person, it is seated at a vacant one-seater table. If there are none of them, it is seated at a vacant two-seater table. If there are none of them, it is seated at a two-seater table occupied by single person. If there are still none of them, the restaurant denies service to this group.
If a group consist of two people, it is seated at a vacant two-seater table. If there are none of them, the restaurant denies service to this group.
You are given a chronological order of groups coming. You are to determine the total number of people the restaurant denies service to.
The first line contains three integers n, a and b (1 ≤ n ≤ 2·105, 1 ≤ a, b ≤ 2·105) — the number of groups coming to the restaurant, the number of one-seater and the number of two-seater tables.
The second line contains a sequence of integers t1, t2, ..., tn (1 ≤ ti ≤ 2) — the description of clients in chronological order. If ti is equal to one, then the i-th group consists of one person, otherwise the i-th group consists of two people.
Print the total number of people the restaurant denies service to.
4 1 2
1 2 1 1
0
4 1 1
1 1 2 1
2
In the first example the first group consists of one person, it is seated at a vacant one-seater table. The next group occupies a whole two-seater table. The third group consists of one person, it occupies one place at the remaining two-seater table. The fourth group consists of one person, he is seated at the remaining seat at the two-seater table. Thus, all clients are served.
In the second example the first group consists of one person, it is seated at the vacant one-seater table. The next group consists of one person, it occupies one place at the two-seater table. It's impossible to seat the next group of two people, so the restaurant denies service to them. The fourth group consists of one person, he is seated at the remaining seat at the two-seater table. Thus, the restaurant denies service to 2 clients.
有一家店里面有两种桌子,a个一个坐的桌子和b个两人坐的桌子,他们的店会进来n个团体,n个团体里面都只有1人或2人。安排座位的顺序是这样的,从团体来的时间从前往后依次安排,比如第二组样例,有1个一个人坐的桌子和2个两个坐的桌子,那么先进来第一个人,安排到那一个桌子上,又进来1个人,安排在两个人的桌子上,又进来两个人,那么坐不下了,就请出去,又来一个人,坐在两个人桌子上剩余的那个位置。
#include <bits/stdc++.h>
int n, a, b, k;
int main(){
scanf("%d%d%d", &n, &a, &b);
int restb = b*;
int deny = ;
for(int i = ; i < n; i++){
scanf("%d", &k);
if(k == ){
if(a > ) a--;
else if((a == ) && b){
b--;
restb--;
}
else if(restb){
restb--;
}
else deny++;
}
else{
if(b){
b--;
restb-=;
}
else deny+=;
}
}
printf("%d\n", deny);
}
//使用额外变量half记录双人座的单个位子
#include <iostream>
using namespace std; int main() { int n,a,b,half=,value=;
cin>>n>>a>>b; for(int x=;x<n;x++)
{
int m;
cin>>m; if(m==)
{
if(a>)
{
a--;
}
else if(b>)
{
b--;
half++;
}
else if(half>)
{
half--;
}
else
value++;
}
else if(m==)
{
if(b>)
b--;
else
value+=;
}
}
cout<<value<<endl;
return ;
}
Codeforces Round #423 A Restaurant Tables(模拟)的更多相关文章
- Codeforces Round #423 (Div. 2)
codeforces 423 A. Restaurant Tables [水题] //注意,一个人选座位的顺序,先去单人桌,没有则去空的双人桌,再没有则去有一个人坐着的双人桌.读清题意. #inclu ...
- Codeforces Round #423 (Div. 1, rated, based on VK Cup Finals)
Codeforces Round #423 (Div. 1, rated, based on VK Cup Finals) A.String Reconstruction B. High Load C ...
- Codeforces Round #423 (Div. 2, rated, based on VK Cup Finals)
题目链接:http://codeforces.com/contest/828 A. Restaurant Tables time limit per test 1 second memory limi ...
- 【Codeforces Round #423 (Div. 2) A】Restaurant Tables
[Link]:http://codeforces.com/contest/828/problem/A [Description] 有n个组按照时间顺序来餐馆; 每个组由一个人或两个人组成; 每当有一个 ...
- Codeforces Round #423 (Div. 2, rated, based on VK Cup Finals) Problem A - B
Pronlem A In a small restaurant there are a tables for one person and b tables for two persons. It i ...
- Codeforces Round #304 C(Div. 2)(模拟)
题目链接: http://codeforces.com/problemset/problem/546/C 题意: 总共有n张牌,1手中有k1张分别为:x1, x2, x3, ..xk1,2手中有k2张 ...
- Educational Codeforces Round 2 A. Extract Numbers 模拟题
A. Extract Numbers Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/600/pr ...
- Codeforces Round #423 (Div. 2, rated, based on VK Cup Finals) A,B,C
A.题目链接:http://codeforces.com/contest/828/problem/A 解题思路: 直接暴力模拟 #include<bits/stdc++.h> using ...
- Educational Codeforces Round 11B. Seating On Bus 模拟
地址:http://codeforces.com/contest/660/problem/B 题目: B. Seating On Bus time limit per test 1 second me ...
随机推荐
- aos.js让页面滚动变得丰富
(转)<script src="js/jquery-2.1.1.min.js" type="text/javascript"></script ...
- 数学:BSGS
先来稍微回顾一下,我们已经会求模线性方程(包括其特殊情况乘法逆元) 我们还会进行幂取模的快速算法(模是质数用费马小定理,模一般情况用欧拉定理) 对于幂中指数特别大的情况,我们还延伸出了拓展欧拉定理来解 ...
- MyBatis框架的使用及源码分析(二) 配置篇 SqlSessionFactoryBuilder,XMLConfigBuilder
在 <MyBatis框架中Mapper映射配置的使用及原理解析(一) 配置与使用> 的demo中看到了SessionFactory的创建过程: SqlSessionFactory sess ...
- Large Class--过大的类--要重构的信号
如果想利用单个类做太多事情,其内往往就会出现太多实例变量.一旦如此,Duplicated Code也就接踵而至. 解决方法: 1.将类内彼此相关的变量,将它们放在一起.使用Extrac ...
- python学习笔记(七)之列表
列表:是一个加强版的数组,什么东西都可以往里面放. 创建列表 创建一个普通列表: >>> member = ['operating system', 'data structure' ...
- jq_从右向右的滑入滑出效果
<!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title> ...
- c语言中网络字节序和主机字节序的转换
函数说明 相关函数:htonl, htons, ntohl 头文件:#include <netinet/in.h> 定义函数:unsigned short int ntohs(unsi ...
- 【Windows使用笔记】使Onedrive同步任意文件夹
因为度盘实在是有点垃圾,经常看的剧之类的或者其他软件资源啥的动不动就被封. 所以跑去某宝买了一个5T的企业子账号,安全性不清楚,重要的隐私数据反正都用移动硬盘备份了.主要就是存一些资源性的文件吧.而且 ...
- 函数导出在kvm_intel.ko,kvm.ko不共享
KVM一共包含了三个内核模块,kvm_intel.ko,kvm_amd.ko,kvm.ko.其中两个重要文件x86.c和vmx.c在编译后分别会生成kvm_intel.ko和kvm.ko两个内核模块, ...
- Exploring Qualcomm's TrustZone Implementation
转自 http://bits-please.blogspot.com/2015/08 (需要FQ, 狗日的墙) In this blog post, we'll be exploring Qua ...