问题描述:

ind the contiguous subarray within an array (containing at least one number) which has the largest sum.

For example, given the array [−2,1,−3,4,−1,2,1,−5,4],
the contiguous subarray [4,−1,2,1] has the largest sum = 6.

public class MaxSubarray
{
public int maxSubArray(int[] nums)
{
int sum = nums[0];
int max = nums[0];
for(int i = 1; i < nums.length; i ++)
{
if(sum < 0)
{
sum = 0;
}
sum += nums[i];
if(max < sum)
{
max = sum;
}
}
return max;
}
//穷举法O(n^3)
public int maxSubArray1(int[] nums)
{
int max = 0;
for(int i = 0; i < nums.length; i ++)
{
for(int j = i; j < nums.length; j ++)
{
int sum = 0;
for(int k = i; k < j; k ++)
{
sum += nums[k];
}
if(sum > max)
{
max = sum;
}
}
}
return max;
}
//O(n^2)
public int maxSubArray2(int[] nums)
{
int max = 0;
for(int i = 0; i < nums.length; i ++)
{
int sum = 0;
for(int j = i; j < nums.length; j ++)
{
sum += nums[j];
if(sum > max)
{
max = sum;
}
}
}
return max;
}
}

最大字串和问题(Maximum Subarray)的更多相关文章

  1. leetCode 53.Maximum Subarray (子数组的最大和) 解题思路方法

    Maximum Subarray  Find the contiguous subarray within an array (containing at least one number) whic ...

  2. [LintCode] Maximum Subarray 最大子数组

    Given an array of integers, find a contiguous subarray which has the largest sum. Notice The subarra ...

  3. 【leetcode】Maximum Subarray (53)

    1.   Maximum Subarray (#53) Find the contiguous subarray within an array (containing at least one nu ...

  4. 算法:寻找maximum subarray

    <算法导论>一书中演示分治算法的第二个例子,第一个例子是递归排序,较为简单.寻找maximum subarray稍微复杂点. 题目是这样的:给定序列x = [1, -4, 4, 4, 5, ...

  5. LEETCODE —— Maximum Subarray [一维DP]

    Maximum Subarray Find the contiguous subarray within an array (containing at least one number) which ...

  6. 【leetcode】Maximum Subarray

    Maximum Subarray Find the contiguous subarray within an array (containing at least one number) which ...

  7. maximum subarray problem

    In computer science, the maximum subarray problem is the task of finding the contiguous subarray wit ...

  8. (转)Maximum subarray problem--Kadane’s Algorithm

    转自:http://kartikkukreja.wordpress.com/2013/06/17/kadanes-algorithm/ 本来打算自己写的,后来看到上述链接的博客已经说得很清楚了,就不重 ...

  9. 3月7日 Maximum Subarray

    间隔2天,继续开始写LeetCodeOj. 原题: Maximum Subarray 其实这题很早就看了,也知道怎么做,在<编程珠玑>中有提到,求最大连续子序列,其实只需要O(n)的复杂度 ...

随机推荐

  1. flex组合流动布局实例---利用css的order属性改变盒子排列顺序

    flex弹性盒子 <div class="container"> <div class="box yellow"></div> ...

  2. jquery 轮播图实例

    实现效果:1.图片每2秒钟切换1次. 2.当鼠标停留在整个页面上时,图片不进行轮播. 3.当点击右下角的小球时,出现该选项的对应图片,而且切换页选项的背景颜色发生相应的变化. 4.当图片发生轮播切换时 ...

  3. Spring Context及ApplicationContext

    web.xml 这是声明了一个父工厂 <context-param> <param-name>contextConfigLocation</param-name> ...

  4. SQL架构信息读取

    --架构: select * from information_schema.SCHEMATA --表: select table_name from information_schema.table ...

  5. 短URL DH 密钥交换算法

    w  追问:0-短URL 的时效性,(比如微信个人账户的永久二维码和群的约7天时效二维码):1-0中的时效性对于算法选择的影响,比如简单的HAS映射.sha1.md5......   https:// ...

  6. 用jq实现鼠标移入按钮背景渐变其他的背景效果

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/ ...

  7. 线程池ThreadPoolExecutor参数设置

    线程池ThreadPoolExecutor参数设置 JDK1.5中引入了强大的concurrent包,其中最常用的莫过了线程池的实现ThreadPoolExecutor,它给我们带来了极大的方便,但同 ...

  8. golang 实现并发计算文件数量

    package main import ( "fmt" "io/ioutil" "os" ) func listDir(path strin ...

  9. Redis四(Set操作)

    1.Set操作 Set集合就是不允许重复的列表 集合操作(无序) sadd(name,values) 1 # name对应的集合中添加元素 scard(name) 1 获取name对应的集合中元素个数 ...

  10. beego——高级查询

    ORM以QuerySeter来组织查询,每个返回QuerySeter的方法都会获得一个新的QuerySeter对象. 基本使用方法: o := orm.NewOrm() // 获取 QuerySete ...