【BZOJ3314】 [Usaco2013 Nov]Crowded Cows 单调队列
第一次写单调队列太垃圾。。。
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#define N 50010
using namespace std;
struct data
{
int x,h;
}a[N],q[N];
int n,m,l,r;
int ok1[N],ok2[N];
inline int read()
{
int f=,ans=;
char c;
while (!isdigit(c=getchar())) if (c=='-') f=-;
ans=c-'';
while (isdigit(c=getchar())) ans=ans*+c-'';
return ans*f;
}
bool cmp(data a,data b) {return a.x<b.x;}
int main()
{
n=read(); m=read();
for (int i=;i<=n;i++) a[i].x=read(),a[i].h=read();
sort(a+,a+n+,cmp);
l=; r=;
for (int i=;i<=n;i++)
{
while (l<=r && q[r].h<a[i].h) r--;
q[++r]=a[i];
while (l<=r && q[l].x<a[i].x-m) l++;
if (q[l].h>=*a[i].h) ok1[i]=;
}
l=; r=;
for (int i=n;i>=;i--)
{
while (l<=r && q[r].h<a[i].h) r--;
q[++r]=a[i];
while (l<=r && q[l].x>a[i].x+m) l++;
if (q[l].h>=*a[i].h) ok2[i]=;
}
int ans=;
for (int i=;i<=n;i++)
if (ok1[i]&&ok2[i]) ans++;
printf("%d\n",ans);
return ;
}
Description
Farmer John's N cows (1 <= N <= 50,000) are grazing along a one-dimensional fence. Cow i is standing at location x(i) and has height h(i) (1 <= x(i),h(i) <= 1,000,000,000). A cow feels "crowded" if there is another cow at least twice her height within distance D on her left, and also another cow at least twice her height within distance D on her right (1 <= D <= 1,000,000,000). Since crowded cows produce less milk, Farmer John would like to count the number of such cows. Please help him.
N头牛在一个坐标轴上,每头牛有个高度。现给出一个距离值D。
如果某头牛在它的左边,在距离D的范围内,如果找到某个牛的高度至少是它的两倍,且在右边也能找到这样的牛的话。则此牛会感觉到不舒服。
问有多少头会感到不舒服。
Input
* Line 1: Two integers, N and D.
* Lines 2..1+N: Line i+1 contains the integers x(i) and h(i). The locations of all N cows are distinct.
Output
* Line 1: The number of crowded cows.
Sample Input
10 3
6 2
5 3
9 7
3 6
11 2
INPUT DETAILS: There are 6 cows, with a distance threshold of 4 for feeling crowded. Cow #1 lives at position x=10 and has height h=3, and so on.
Sample Output
OUTPUT DETAILS: The cows at positions x=5 and x=6 are both crowded.
HINT
Source
【BZOJ3314】 [Usaco2013 Nov]Crowded Cows 单调队列的更多相关文章
- BZOJ 3314: [Usaco2013 Nov]Crowded Cows( 单调队列 )
从左到右扫一遍, 维护一个单调不递减队列. 然后再从右往左重复一遍然后就可以统计答案了. ------------------------------------------------------- ...
- BZOJ3314: [Usaco2013 Nov]Crowded Cows
3314: [Usaco2013 Nov]Crowded Cows Time Limit: 1 Sec Memory Limit: 128 MBSubmit: 86 Solved: 61[Subm ...
- 3314: [Usaco2013 Nov]Crowded Cows
3314: [Usaco2013 Nov]Crowded Cows Time Limit: 1 Sec Memory Limit: 128 MBSubmit: 111 Solved: 79[Sub ...
- 【BZOJ】3314: [Usaco2013 Nov]Crowded Cows(单调队列)
http://www.lydsy.com/JudgeOnline/problem.php?id=3314 一眼就是维护一个距离为d的单调递减队列... 第一次写.....看了下别人的代码... 这一题 ...
- BZOJ 3314 [Usaco2013 Nov]Crowded Cows:单调队列
题目链接:http://www.lydsy.com/JudgeOnline/problem.php?id=3314 题意: N头牛在一个坐标轴上,每头牛有个高度.现给出一个距离值D. 如果某头牛在它的 ...
- BZOJ : [Usaco2013 Nov]Crowded 单调队列
正反两遍个来一次单调队列 DP 即可. Code: #include<cstdio> #include<deque> #include<algorithm> usi ...
- [bzoj3126][USACO2013]Photo_动态规划_单调队列
Photo bzoj-3126 题目大意:给你一个n长度的数轴和m个区间,每个区间里有且仅有一个点,问最多能有多少个点. 注释:$1\le n \le 2\cdot 10^5$,$1\le m\le1 ...
- [USACO16JAN]愤怒的奶牛Angry Cows (单调队列优化dp)
题目链接 Solution 应该可以用二分拿部分分,时间 \(O(n^2logn)\) . 然后可以考虑 \(n^2\) \(dp\) ,令 \(f_i\) 代表 \(i\) 点被激活,然后激活 \( ...
- 小结:单调栈 & 单调队列
概要: 对于维护信息具有单调性的性质或者问题可以转化为具有单调性质的模型的题,我们可以考虑用单调栈或单调队列. 技巧及注意: 技巧很多,只要能将问题转化为单调性问题,就好解决了. 当维护固定长度的单调 ...
随机推荐
- Visual Studio的背景插件
分享一个Visual Studio的背景插件,让堆码更富情趣..哈哈 忘记一件重要的事情,我使用的是VS 2012版,其他更高版本应该是可以找到的,以下版本就不清楚了.有可能找不到,见谅,也不是我 ...
- Java图片处理 Thumbnails框架
一.设置图片的缩放比例或者图片的质量比 第一步:导入maven的jar包 <dependency> <groupId>net.coobird</groupId ...
- dell md3200i mdss (企业管理) 安装的那点事儿
首先获取安装包,解压后如图: 我是在windows 机上安装,所以执行windows 文件夹下的可执行程序: 双击红箭头文件,进行安装,步骤截图如下: 出现最后这个界面,就说明安装成功,直接重启系统就 ...
- highcharts使用笔记
1.legend取消点击事件: 饼图:plotOptions.pie.point.events.legendItemClick = function() {return false;} 其他,如:pl ...
- Battleships in a Board
Given an 2D board, count how many different battleships are in it. The battleships are represented w ...
- Selenium使用
定位 1.普通 by id, name,class_name,link_text 2.加强 xpath css
- java 简单使用redis
1.配置文件 <bean id="jedisPoolConfig" class="redis.clients.jedis.JedisPoolConfig" ...
- gulp整理
gulp基于node 1.全局安装gulp: $ npm install --global gulp 2.前往项目目录,然后安装作为项目的开发依赖(devDependencies): $ npm in ...
- 安装yum
RedHat 安装配置 YUM 删除 1 . 查询系统是否安装 yum : rpm – qa|grep yum 2删除原有 yum rpm -qa|grep yum|xargs rpm -e – no ...
- jquery遍历不同色彩的li
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/ ...