HDU 2018 Multi-University Training Contest 1 Triangle Partition 【YY】
传送门:http://acm.hdu.edu.cn/showproblem.php?pid=6300
Triangle Partition
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 132768/132768 K (Java/Others)
Total Submission(s): 2964 Accepted Submission(s): 1474
Special Judge
Chiaki would like to construct n disjoint triangles where each vertex comes from the 3n points.
The first line contains an integer n (1≤n≤1000) -- the number of triangle to construct.
Each of the next 3n lines contains two integers xi and yi (−109≤xi,yi≤109).
It is guaranteed that the sum of all n does not exceed 10000.
1
1 2
2 3
3 5
题意概括:
给出 3*N 个点的坐标(保证点不共线);
用这 3*N 个点构造出 N 个不相交的三角形;
每一行输出一个三角形的坐标编号。
解题思路:
因为点都不共线,所以按横坐标排个序,三个三个点构造的三角形不相交。
AC code:
#include <queue>
#include <cstdio>
#include <vector>
#include <cstring>
#include <iostream>
#include <algorithm>
#define INF 0x3f3f3f3f
#define LL long long
using namespace std;
const int MAXN = 3e3+; struct data
{
int x, y;
int no;
}node[MAXN]; bool cmp(data a, data b)
{
return a.x < b.x;
} int main()
{
int N;
int T_case;
while(~scanf("%d", &T_case)){
while(T_case--){
scanf("%d", &N);
int maxx = *N;
for(int i = ; i < maxx; i++){
scanf("%d %d", &node[i].x, &node[i].y);
node[i].no = i+;
}
sort(node, node+maxx, cmp); for(int i = ; i+ < maxx; i+=){
printf("%d %d %d\n", node[i].no, node[i+].no, node[i+].no);
}
}
}
return ;
}
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