Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Example 1:

Input: [1,3,5,6], 5
Output: 2

Example 2:

Input: [1,3,5,6], 2
Output: 1

Example 3:

Input: [1,3,5,6], 7
Output: 4

Example 4:

Input: [1,3,5,6], 0
Output: 0

原题地址: Search Insert Position

思路:

二分查找

代码:

class Solution(object):
def searchInsert(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: int
"""
l, r = 0, len(nums)-1
while l <= r:
mid = (l + r) / 2
if nums[mid] >= target:
r = mid - 1
else:
l = mid + 1
return l

时间复杂度: O(log(n))

空间复杂度: O(1)

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