p1459 Sorting a Three-Valued Sequence

如果将1和3都放到正确的位置，2自然也在正确的位置。那么统计1,2,3的数量num1,num2,num3。再看前num1个数有几个（设x个）不是1，那么x个1肯定要移。设前num1个数有y个3，最后num3个数有z个1，那么这个过程中，最多能将min(y,z)个3移到正确位置。剩下num3-min(y,z)个3也必须移到最后num3个位置

#include <iostream>
#include <cstdio>
#include <cmath>
#include <algorithm>
#include <vector>
#include <iomanip>
#include <cstring>
#include <map>
#include <queue>
#include <set>
#include <cassert>
#include <stack>
#define mkp make_pair
using namespace std;
const double EPS=1e-;
typedef long long lon;
const lon SZ=,INF=0x7FFFFFFF;
int arr[SZ];

int main()
{
    std::ios::sync_with_stdio();
    //freopen("d:\\1.txt","r",stdin);
    lon casenum;
    //cin>>casenum;
    //for(lon time=1;time<=casenum;++time)
    {
        int n;
        cin>>n;
        for(int i=;i<=n;++i)cin>>arr[i];
        int num1=count(arr+,arr++n,);
        int num2=count(arr+,arr++n,);
        int num3=count(arr+,arr++n,);
        int x=,y=,z=,w=;
        for(int i=;i<=num1;++i)
        {
            if(arr[i]!=)++x;
            if(arr[i]==)++z;
        }
        for(int i=num1+num2+;i<=n;++i)
        {
            if(arr[i]!=)++y;
            if(arr[i]==)++w;
        }
        //cout<<num1<<" "<<num2<<" "<<num3<<endl;
        //cout<<x<<" "<<y<<" "<<z<<endl;
        cout<<(x+y-min(z,w))<<endl;
    }
    return ;
}