The beatles-Yesterday
轉載自https://www.youtube.com/watch?v=XNnaxGFO18o
Yesterday
Lyrics:Paul Mccartney Music:Paul Mccartney Artist:Paul Mccartney
Yesterday, all my troubles seemed so far away
Now it looks as though they're here to stay
Oh, I believe in yesterday.
Suddenly, I'm not half the man I used to be,
There's a shadow hanging over me.
Oh, yesterday came suddenly.
Why she had to go I don't know she wouldn't say.
I said something wrong, now I long for yesterday.
Yesterday, love was such an easy game to play.
Now I need a place to hide away.
Oh, I believe in yesterday.
Lyrics:Paul Mccartney Music:Paul Mccartney Artist:Paul Mccartney
Yesterday, all my troubles seemed so far away
Now it looks as though they're here to stay
Oh, I believe in yesterday.
Suddenly, I'm not half the man I used to be,
There's a shadow hanging over me.
Oh, yesterday came suddenly.
Why she had to go I don't know she wouldn't say.
I said something wrong, now I long for yesterday.
Yesterday, love was such an easy game to play.
Now I need a place to hide away.
Oh, I believe in yesterday.
The beatles-Yesterday的更多相关文章
- [ Codeforces Round #549 (Div. 2)][D. The Beatles][exgcd]
https://codeforces.com/contest/1143/problem/D D. The Beatles time limit per test 1 second memory lim ...
- CF1143D/1142A The Beatles
CF1143D/1142A The Beatles 将题目中所给条件用同余方程表示,可得 \(s-1\equiv \pm a,s+l-1\equiv \pm b\mod k\). 于是可得 \(l\e ...
- Let It Be - The Beatles - Lyrics
轉載自 https://www.youtube.com/watch?v=0714IbwC3HA When I find myself in times of trouble, Mother Mary ...
- D. The Beatles
链接 [https://codeforces.com/contest/1143/problem/D] 题意 就是有nkcity,n个面包店 第一个面包店在1city,第x个在(x-1)k+1city ...
- CodeForces #549 Div.2 D. The Beatles
题目 解题思路 关键是要 ,找出L 的组合,然后遍历L的组合,用最大公约数就可以算出来当前L的值要停多少次 怎么找出L的组合呢?饭店是每隔K 有一个,是重复的,我们只需要算出第一个饭店两侧,起点和停顿 ...
- A-the Beatles
传送门: 题意:题目给出n,k分别代表在这个环中饭店的个数和两个饭店相离的距离.然后再给出一组a,b分别代表在某一点s里最近饭店的距离和在这个s点走一步之后到达的点离最近饭店的距离. 然后问这个人再次 ...
- CF1142A The Beatles
思路: 令p表示步数,l表示步长.由于p是使(l * p) % (n * k) == 0的最小的p,所以p = (n * k) / gcd(n * k, l). 设l = k * x + r,则由题意 ...
- CF-1143D. The Beatles
题意:有间隔为k的n个点在数轴上,下标为 \(1,k+1, 2*k+1,\cdots (n-1)*k+1\) 首尾相接.设起点为s,步长为L,而现在只知道s距离最近的点的距离为a,和(s+L)距离最近 ...
- 『题解』Codeforces1142A The Beatles
更好的阅读体验 Portal Portal1: Codeforces Portal2: Luogu Description Recently a Golden Circle of Beetlovers ...
- Entity Framework 6 Recipes 2nd Edition(13-10)译 -> 显式创建代理
问题 你有一个POCO实体,原本在执行一个查询时动态创建代理,现在你不想EF延迟创建代理带来的代价. 解决方案 假设你有一个如图Figure13-15的模型 Figure 13-15. A model ...
随机推荐
- linux应用程序地址布局,王明学learn
linux应用程序地址布局 在学习Linux应用程序开发时,经常会遇到如下概念:代码段.数据段.BSS段(Block Started by Symbol,又名:未初始化数据段).堆(heap)和栈(s ...
- 基于socket、多线程的客户端服务器端聊天程序
服务器端: using System; using System.Windows.Forms; using System.Net.Sockets; using System.Net;//IPAddre ...
- Bag-of-words模型
Bag-of-words模型是信息检索领域常用的文档表示方法.在信息检索中,BOW模型假定对于一个文档,忽略它的单词顺序和语法.句法等要素,将其仅仅看作是若干个词汇的集合,文档中每个单词的出现都是独立 ...
- WINDOWS系统Eclipse+NDK+Android + OpenCv
WINDOWS系统Eclipse+NDK+Android + OpenCv 参考文档博客 1 NDK环境搭建 http://jingyan.baidu.com/article/5d6edee22d90 ...
- X64下MmIsAddressValid的逆向及内存寻址解析
标 题: [原创]X64下MmIsAddressValid的逆向及内存寻址解析 作 者: 普通朋友 时 间: 2015-10-21,20:03:52 链 接: http://bbs.pediy.com ...
- CDN网络的原理
来源:http://blog.csdn.net/coolmeme/article/details/9468743 版权声明:本文为博主原创文章,未经博主允许不得转载. 1.用户向浏览器输入www.we ...
- Nginx日志定时切割脚本
nginx的日志文件如果你不处理,将变得越来越大,我们可以写一个nginx日志切割脚本来自动切割日志文件. 第一步就是重命名日志文件,不用担心重命名后nginx找不到日志文件而丢失日志.在你未重新打开 ...
- python中的变量和数据类型
一.变量定义:变量是计算机内存中的一块区域,存储规定范围内的值,值 可以改变,通俗的说变量就是给数据起个名字. 二.变量命名规则: 1. 变量名由字母.数字.下划线组成 2. 数字不能开头 3. 不可 ...
- APK瘦身实践
首发地址:http://www.jayfeng.com/2015/12/29/APK%E7%98%A6%E8%BA%AB%E5%AE%9E%E8%B7%B5/ 因为推广的需要,公司需要把APK的大小再 ...
- [xsd学习]xsd实例
以下为一个表示学校的xml文件,学校内有若干学生,每个学生都有基本信息,电脑信息,选课信息 <?xml version="1.0" encoding="UTF-8& ...