1:A+B Problem

总时间限制: 

1000ms 

内存限制: 

65536kB

描述

Calculate a + b

输入

Two integer a,,b (0 ≤ a,b ≤ 10)

输出

Output a + b

样例输入

1 2

样例输出

3

提示

Q: Where are the input and the output?

A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout.

You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer".

User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer" if you try to do so.

Here is a sample solution for problem 1000 using C++/G++:

1. #include <iostream>
2. using namespace std;
3. int  main()
4. {
5. int a,b;
6. cin >> a >> b;
7. cout << a+b << endl;
8. return 0;
9. }

It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error.

Here is a sample solution for problem 1000 using C/GCC:

1. #include <stdio.h>
2. int main()
3. {
4. int a,b;
5. scanf("%d %d",&a, &b);
6. printf("%d\n",a+b);
7. return 0;
8. }

Here is a sample solution for problem 1000 using PASCAL:

1. program p1000(Input,Output);
2. var
3. a,b:Integer;
4. begin
5. Readln(a,b);
6. Writeln(a+b);
7. end.

Here is a sample solution for problem 1000 using JAVA:

Now java compiler is jdk 1.5, next is program for 1000

1. import java.io.*;
2. import java.util.*;
3. public class Main
4. {
5. public static void main(String args[]) throws Exception
6. {
7. Scanner cin=new Scanner(System.in);
8. int a=cin.nextInt(),b=cin.nextInt();
9. System.out.println(a+b);
10. }
11. }

Old program for jdk 1.4

1. import java.io.*;
2. import java.util.*;
3. public class Main
4. {
5. public static void main (String args[]) throws Exception
6. {
7. BufferedReader stdin =
8. new BufferedReader(
9. new InputStreamReader(System.in));
10. String line = stdin.readLine();
11. StringTokenizer st = new StringTokenizer(line);
12. int a = Integer.parseInt(st.nextToken());
13. int b = Integer.parseInt(st.nextToken());
14. System.out.println(a+b);
15. }
16. }

源代码：

1. <pre name="code" class="cpp">int main(void)
2. {
3. int a, b;
4. scanf("%d%d", &a, &b);
5. printf("%d", a+b);
6. return 0;
7. }