Given a C++ program, remove comments from it. The program source is an array where source[i] is the i-th line of the source code. This represents the result of splitting the original source code string by the newline character \n.

In C++, there are two types of comments, line comments, and block comments.

The string // denotes a line comment, which represents that it and rest of the characters to the right of it in the same line should be ignored.

The string /* denotes a block comment, which represents that all characters until the next (non-overlapping) occurrence of */ should be ignored. (Here, occurrences happen in reading order: line by line from left to right.) To be clear, the string /*/ does not yet end the block comment, as the ending would be overlapping the beginning.

The first effective comment takes precedence over others: if the string // occurs in a block comment, it is ignored. Similarly, if the string /* occurs in a line or block comment, it is also ignored.

If a certain line of code is empty after removing comments, you must not output that line: each string in the answer list will be non-empty.

There will be no control characters, single quote, or double quote characters. For example, source = "string s = "/* Not a comment. */";" will not be a test case. (Also, nothing else such as defines or macros will interfere with the comments.)

It is guaranteed that every open block comment will eventually be closed, so /* outside of a line or block comment always starts a new comment.

Finally, implicit newline characters can be deleted by block comments. Please see the examples below for details.

After removing the comments from the source code, return the source code in the same format.

Example 1:

Input:
source = ["/*Test program */", "int main()", "{ ", " // variable declaration ", "int a, b, c;", "/* This is a test", " multiline ", " comment for ", " testing */", "a = b + c;", "}"] The line by line code is visualized as below:
/*Test program */
int main()
{
// variable declaration
int a, b, c;
/* This is a test
multiline
comment for
testing */
a = b + c;
} Output: ["int main()","{ "," ","int a, b, c;","a = b + c;","}"] The line by line code is visualized as below:
int main()
{ int a, b, c;
a = b + c;
} Explanation:
The string /* denotes a block comment, including line 1 and lines 6-9. The string // denotes line 4 as comments.

Example 2:

Input:
source = ["a/*comment", "line", "more_comment*/b"]
Output: ["ab"]
Explanation: The original source string is "a/*comment\nline\nmore_comment*/b", where we have bolded the newline characters. After deletion, the implicit newline characters are deleted, leaving the string "ab", which when delimited by newline characters becomes ["ab"].

Note:

  • The length of source is in the range [1, 100].
  • The length of source[i] is in the range [0, 80].
  • Every open block comment is eventually closed.
  • There are no single-quote, double-quote, or control characters in the source code.
 

Runtime: 4 ms, faster than 96.80% of Java online submissions for Remove Comments.

class Solution {
public List<String> removeComments(String[] source) {
boolean multiline_comment = false;
List<String> ret = new ArrayList<>();
StringBuilder sb = new StringBuilder();
for(String lines : source){
for(int i=; i<lines.length(); i++){
if(!multiline_comment && lines.charAt(i) == '/' && i+ < lines.length() && lines.charAt(i+) == '/'){
break;
}else if(!multiline_comment && lines.charAt(i) == '/' && i+ < lines.length() && lines.charAt(i+) == '*'){
i++;
multiline_comment = true;
}else if(multiline_comment && lines.charAt(i) == '*' && i+ < lines.length() && lines.charAt(i+) == '/'){
i++;
multiline_comment = false;
}else if(!multiline_comment){
sb.append(lines.charAt(i));
}
}
if(!multiline_comment){
if(sb.length() != ) ret.add(sb.toString());
sb = new StringBuilder();
}
}
return ret;
}
}

LC 722. Remove Comments的更多相关文章

  1. 【LeetCode】722. Remove Comments 解题报告(Python)

    [LeetCode]722. Remove Comments 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/remove-c ...

  2. LeetCode 722. Remove Comments

    原题链接在这里:https://leetcode.com/problems/remove-comments/ 题目: Given a C++ program, remove comments from ...

  3. 【leetcode】722. Remove Comments

    题目如下: Given a C++ program, remove comments from it. The program source is an array where source[i] i ...

  4. 722. Remove Comments

    class Solution { public: vector<string> removeComments(vector<string>& source) { vec ...

  5. [LeetCode] Remove Comments 移除注释

    Given a C++ program, remove comments from it. The program source is an array where source[i] is the ...

  6. [Swift]LeetCode722. 删除注释 | Remove Comments

    Given a C++ program, remove comments from it. The program source is an array where source[i] is the  ...

  7. LC 660. Remove 9 【lock, hard】

    Start from integer 1, remove any integer that contains 9 such as 9, 19, 29... So now, you will have ...

  8. [LC] 82. Remove Adjacent Repeated Characters IV

    Repeatedly remove all adjacent, repeated characters in a given string from left to right. No adjacen ...

  9. [LC] 203. Remove Linked List Elements

    Remove all elements from a linked list of integers that have value val. Example: Input: 1->2-> ...

随机推荐

  1. Winform 多项目共用AssemblyInfo解决方案

    Winform 多项目共用AssemblyInfo解决方案: 操作步骤如下: 第一步:复制任何项目中的AssemblyInfo.cs文件至指定目录 第二步:删除所有项目的AssemblyInfo.cs ...

  2. ContextMenu菜单创建 上下文菜单的基本认识q

    MainActivity.class public class MainActivity extends AppCompatActivity { @Override protected void on ...

  3. storm 的分组策略深入理解(-)

    目录 storm的分组策略 根据实例来分析分组策略 common配置: Shuffle grouping shuffle grouping的实例代码 ShuffleGrouping 样例分析 Fiel ...

  4. Centos7下搭建WebGoat 8和DVWA环境

    搭建WebGoat 安装前置条件说明 我们这里选择WebGoat的jar版本,由于WebGoat 8的jar文件已自带了tomcat和数据库,所以不需要再另外安装tomcat和mysql这种东西,只需 ...

  5. CSS 中用户自定义字体 @font-face

    @font-face 允许网页中使用自定义的字体,这些自定义的字体被放置在服务器上,从而让网页摆脱对访问者计算机上字体环境的依赖. 简单的说,有了@font-face,只需将字体上传到服务器端,无论访 ...

  6. CSS基础学习 21.CSS居中总结

    注意:*在IE中并不代表通配符的意思,是代表根元素的意思,所以为了匹配适应各种浏览器,进行页面初始化 <style> *{ margin:0; padding:0; } </styl ...

  7. bzoj1458: 士兵占领(最大流)

    题目描述 有一个M * N的棋盘,有的格子是障碍.现在你要选择一些格子来放置一些士兵,一个格子里最多可以放置一个士兵,障碍格里不能放置士兵.我们称这些士兵占领了整个棋盘当满足第i行至少放置了Li个士兵 ...

  8. 【leetcode】1290. Convert Binary Number in a Linked List to Integer

    题目如下: Given head which is a reference node to a singly-linked list. The value of each node in the li ...

  9. Java数据库小项目00---基础知识

    目录 JDBC的简单使用 向JDBC注入攻击 防止注入攻击 自建JDBC工具类 自建工具类优化--使用配置文件 使用数据库连接池优化工具类 JDBC的简单使用 package Test; import ...

  10. 【Python之路】特别篇--服务商API认证、Restful、一致性哈希

    API加密方式 1/ 加密方式: Md5 (随机字符串 + 时间戳) 2/ 发送方式: http://127.0.0.1:8888/index?pid= MD5加密值 | 时间戳 | 序号 服务端接收 ...