2018 Nowcoder Multi-University Training Contest 10
J. Rikka with Nickname
题意:
给出\(n\)个字符串,要求依次合并两个串\(s, t\),满足将\(t\)合并到\(s\)中变成\(r\),使得\(s\)是\(r\)的前缀,并且\(t\)是\(r\)的一个子序列。
思路:
动态维护序列自动机,贪心插入即可。
代码:
#include <bits/stdc++.h>
using namespace std;
#define N 1000010
char s[N], res[N];
int nx[N][26];
int n, m, len;
void add(int now) {
for (int i = now; i <= len; ++i) {
res[++m] = s[i];
for (int j = m - 1; j >= 0; --j) {
nx[j][res[m] - 'a'] = m;
if (res[j] == s[i]) {
break;
}
}
}
}
int main() {
int T; scanf("%d", &T);
while (T--) {
m = 0;
memset(nx, -1, sizeof nx);
scanf("%d", &n);
for (int i = 1; i <= n; ++i) {
scanf("%s", s + 1);
len = strlen(s + 1);
if (i == 1) {
add(1);
} else {
int now = 0;
for (int j = 1; j <= len; ++j) {
now = nx[now][s[j] - 'a'];
if (now == -1) {
add(j);
break;
}
}
}
}
res[m + 1] = 0;
printf("%s\n", res + 1);
}
return 0;
}
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