HDOJ 1303 Doubles(简单题)
Problem Description
As part of an arithmetic competency program, your students will be given randomly generated lists of from 2 to 15 unique positive integers and asked to determine how many items in each list are twice some other item in the same list. You will need a program to help you with the grading. This program should be able to scan the lists and output the correct answer for each one. For example, given the list
1 4 3 2 9 7 18 22
your program should answer 3, as 2 is twice 1, 4 is twice 2, and 18 is twice 9.
Input
The input file will consist of one or more lists of numbers. There will be one list of numbers per line. Each list will contain from 2 to 15 unique positive integers. No integer will be larger than 99. Each line will be terminated with the integer 0, which is not considered part of the list. A line with the single number -1 will mark the end of the file. The example input below shows 3 separate lists. Some lists may not contain any doubles.
Output
The output will consist of one line per input list, containing a count of the items that are double some other item.
Sample Input
1 4 3 2 9 7 18 22 0
2 4 8 10 0
7 5 11 13 1 3 0
-1
Sample Output
3
2
0
题意:就是判断输入的一行数中,有多少对数字相差2倍。
输入的数据不会有重复的。
import java.util.Scanner;
public class Main{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while(sc.hasNext()){
String strNum = sc.nextLine();
String[] strsNum = strNum.split(" ");
int[] num = new int[strsNum.length];
for(int i=0;i<strsNum.length;i++){
num[i] = Integer.parseInt(strsNum[i]);
}
if(num[0]==-1){
return ;
}
int t=0;
for(int i=0;i<num.length;i++){
for(int j=0;j<num.length;j++){
if(i!=j){
//注意除数不能为0!
if(num[j]!=0){
double two = (num[i]*1.0)/(1.0*num[j]);
if(two==2){
t++;
break;
}
}
}
}
}
System.out.println(t);
}
}
}
HDOJ 1303 Doubles(简单题)的更多相关文章
- hdu 1303 Doubles
题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1303 Doubles Description As part of an arithmetic com ...
- BZOJ 2683: 简单题
2683: 简单题 Time Limit: 50 Sec Memory Limit: 128 MBSubmit: 913 Solved: 379[Submit][Status][Discuss] ...
- 【BZOJ-1176&2683】Mokia&简单题 CDQ分治
1176: [Balkan2007]Mokia Time Limit: 30 Sec Memory Limit: 162 MBSubmit: 1854 Solved: 821[Submit][St ...
- Bzoj4066 简单题
Time Limit: 50 Sec Memory Limit: 20 MBSubmit: 2185 Solved: 581 Description 你有一个N*N的棋盘,每个格子内有一个整数,初 ...
- Bzoj2683 简单题
Time Limit: 50 Sec Memory Limit: 128 MBSubmit: 1071 Solved: 428 Description 你有一个N*N的棋盘,每个格子内有一个整数, ...
- 这样leetcode简单题都更完了
这样leetcode简单题都更完了,作为水题王的我开始要更新leetcode中等题和难题了,有些挖了很久的坑也将在在这个阶段一一揭晓,接下来的算法性更强,我就要开始分专题更新题目,而不是再以我的A题顺 ...
- [BZOJ2683][BZOJ4066]简单题
[BZOJ2683][BZOJ4066]简单题 试题描述 你有一个N*N的棋盘,每个格子内有一个整数,初始时的时候全部为0,现在需要维护两种操作: 命令 参数限制 内容 1 x y A 1<=x ...
- HDU 1753 大明A+B(字符串模拟,简单题)
简单题,但要考虑一些细节: 前导0不要,后导0不要,小数长度不一样时,有进位时,逆置处理输出 然后处理起来就比较麻烦了. 题目链接 我的代码纯模拟,把小数点前后分开来处理,写的很繁杂,纯当纪念——可怜 ...
- 团体程序设计天梯赛-练习集L1-014. 简单题
L1-014. 简单题 时间限制 400 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 陈越 这次真的没骗你 —— 这道超级简单的题目没有任何输入. ...
随机推荐
- redis常见错误
1.Redis Error --MISCONF Redis is configured to save RDB snapshots省略 分析:(linux)未用root启动,用的app用户(没有最高权 ...
- Android ArrayAdapter MultiAutoCompleteTextView
MultiAutoCompleteTextView 继承自AutoCompleteTextView,它和AutoCompleteTextView不同的就是能处理多个输入字段,如发送短信界面的联系人列表 ...
- CSS3之渐变Gradient
渐变是CSS3中比较好玩的属性,学会了渐变,那么可以做出非常炫的东东哟.CSS3 中渐变——Gradient分为linear-gradient(线性渐变)和radial-gradient(径向渐变). ...
- (2)入门指南——(2)jQuery可以做什么(What jQuery does)
The jQuery library provides a general-purpose abstraction layer for common web scripting, and is, th ...
- Linux磁盘分区实战案例
一.查看新添加磁盘 [root@localhost /]# fdisk -l 磁盘 /dev/sda:53.7 GB, 53687091200 字节,104857600 个扇区 Units = ...
- -bash: ulimit: open files: cannot modify limit: Operation not permitted
普通用户登录系统报错,提示: -bash: ulimit: open files: cannot modify limit: Operation not permitted. 处理方法: #vi /e ...
- java06switch
public class SwitchTest { public static void main(String[] args) { /** * 如果第一名,参加麻省理工大学组织的1个月夏令营 * 如 ...
- Linux中命令行编译java接口总是提示找不到符号的疑难杂症的解决
今天学习java的接口,在linux的命令行下写代码练练手吧,啪啪啪一顿猛敲,写了一个接口UsbInserface,UDisk继承UsbInterface,写完了那就编译到bin目录呗. 当时写程序的 ...
- mysql怎么限制某些查询语句的执行?
mysql怎么限制某些查询语句的执行? 比如某些sql语句执行时间很长,超过10s,怎么样超过10s就不让其执行? 后续更新中...
- apache的域名添加虚拟端口号
1. vi /etc/httpd/conf/httpd.conf 2. 搜索Listen 80,在后面添加Listen 8080 3. 重启apache服务器./usr/sbin/apachectl ...