贪心水题,每次取最短的两个绳子合并,长度缩减成一半

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <string.h>
#include <string>
#include <map>
using namespace std;
const int maxn=+;
int a[maxn];
int main()
{
int n;
scanf("%d",&n);
for(int i=;i<n;i++)
cin>>a[i];
sort(a,a+n);
float lastlen=a[];
for(int i=;i<n;i++){
lastlen=(lastlen+a[i])/;
}
printf("%d\n",(int)lastlen);
return ;
}

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