PAT T1015 Letter-moving Gam
双下标法找最长公共子序列(不能删除字符)
#include<bits/stdc++.h>
using namespace std;
const int maxn=;
string s;
string t;
int main () {
cin>>s>>t;
int maxLength=;
int st,ed;
for (int i=;i<s.length();i++) {
st=i;
ed=;
while (st<s.length()&&ed<s.length()) {
if (s[ed]==t[st]) st++;
ed++;
}
maxLength=max(maxLength,st-i);
}
printf ("%d",s.length()-maxLength);
return ;
}
PAT T1015 Letter-moving Gam的更多相关文章
- PAT A1153 Decode Registration Card of PAT (25 分)——多种情况排序
A registration card number of PAT consists of 4 parts: the 1st letter represents the test level, nam ...
- PAT 1032 Sharing[hash][链表][一般上]
1032 Sharing (25)(25 分) To store English words, one method is to use linked lists and store a word l ...
- 1153 Decode Registration Card of PAT (25 分)
A registration card number of PAT consists of 4 parts: the 1st letter represents the test level, nam ...
- PAT_A1153#Decode Registration Card of PAT
Source: PAT A1153 Decode Registration Card of PAT (25 分) Description: A registration card number of ...
- PAT(B) 1057 数零壹(Java)字符串
题目链接:1057 数零壹 (20 point(s)) 题目描述 给定一串长度不超过 105 的字符串,本题要求你将其中所有英文字母的序号(字母 a-z 对应序号 1-26,不分大小写)相加,得 ...
- PAT Advanced 1153 Decode Registration Card of PAT (25 分)
A registration card number of PAT consists of 4 parts: the 1st letter represents the test level, nam ...
- PAT甲级【2019年3月考题】——A1157 Anniversary【25】
Zhejiang University is about to celebrate her 122th anniversary in 2019. To prepare for the celebrat ...
- PAT甲级——A1153 DecodeRegistrationCardofPAT【25】
A registration card number of PAT consists of 4 parts: the 1st letter represents the test level, nam ...
- PAT甲级——A1032 Sharing
To store English words, one method is to use linked lists and store a word letter by letter. To save ...
随机推荐
- 吴裕雄 python 机器学习——数据预处理过滤式特征选取SelectPercentile模型
from sklearn.feature_selection import SelectPercentile,f_classif #数据预处理过滤式特征选取SelectPercentile模型 def ...
- windows CMakeLists.txt
在windows下写好CMakeLists.txt,然后配合cmake-gui使用. CMakeLists.txt写的不够好,后期优化,以下仅供参考: # set(OpenCV_DIR D:/Prog ...
- JavaScript - 获取当前页面某个节点的个数
document.getElementsByTagName(<tag_name>).length;
- C语言随笔2: rom ram 及其运行的过程
内存的分配方式 五个区 :堆区.栈区.全局区.文字常量区.程序代码区 这五个区是ram中的.或者说,堆栈段.数据段.代码段 而rom中,没有堆区和栈区,只有数据段和代码段. ram是在程序运行是的内存 ...
- 安装Anaconda3时出现conda不是内部或者外部命令
在win10,64位,python版本为3.7的环境下安装anaconda3的时候,无法在命令行执行conda命令,一直提示conda不是内部或者外部命令,参考网上的修改环境变量,修改完后还是没有用, ...
- 【前端开发API】豆瓣开放API
转载:https://www.cnblogs.com/HuangJie-sol/articles/10884622.html#_label6 阅读目录 前言 具体api 1.正在热映 2.即将上映 3 ...
- Abaqus 粘聚力模型(Cohesive Model)
目录 1. 问题描述 2. 有限元模型建立--Cohesive单元 3. 有限元模型建立--接触方法 Abaqus提供了两种方法模拟胶结特性: 使用Cohesive单元模拟胶结,通过定义材料属性和截面 ...
- vue基础总结
Vue语法: new Vue({ //挂载: el: '#app', //初始化数据: data: {}, //监听 data 的数据变化: watch: { todos: { //深度监视 hand ...
- java处理节假日和工作时间的工具类
import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.ArrayList; impo ...
- python--小游戏(循环+随机)
1 import time 2 import random 3 4 player_victory = 0 5 enemy_victory = 0 6 a1 = True 7 while a1: 8 f ...