题目描述

Little A gets to know a new friend, Little B, recently. One day, they realize that they are family 500 years ago. Now, Little A wants to know whether Little B is his elder, younger or brother.

输入

There are multiple test cases.

For each test case, the first line has a single integer, n (n<=1000). The next n lines have two integers a and b (1<=a,b<=2000) each, indicating b is the father of a. One person has exactly one father, of course. Little A is numbered 1 and Little B is numbered 2.

Proceed to the end of file.

输出

For each test case, if Little B is Little A’s younger, print “You are my younger”. Otherwise, if Little B is Little A’s elder, print “You are my elder”. Otherwise, print “You are my brother”. The output for each test case occupied exactly one line.

样例输入

5
1 3
2 4
3 5
4 6
5 6
6
1 3
2 4
3 5
4 6
5 7
6 7

样例输出

You are my elder
You are my brother
#include<iostream>
#include<cstring>
using namespace std;
int main()
{
int n;
while(cin>>n)
{
int a,b,la=,lb=,da=,db=;
for(int i=;i<=n;i++)
{
cin>>a>>b;
if(la==a){la=b;da++;}
if(lb==a){lb=b;db++;}
}
if(db<da)cout<<"You are my elder"<<endl;
else if(db==da) cout<<"You are my brother"<<endl;
else if(db>da) cout<<"You are my younger"<<endl;
}
return ;
}

fzoj1314 You are my brother的更多相关文章

  1. 远程监控显示brother数控机床数据

    最近几个月公司太忙了,到现在已经连续出差两个多月了. 这个项目这要做mes系统,涉及到产品在机床的加工过程监控,然后led看板显示产品进度. 这里的主角是日本的brother数控机床,服务器按照一定频 ...

  2. Ubuntu 安装 Brother MFC7470D 驱动

    Ubuntu 安装 Brother MFC7470D 驱动 办公室的打印机是 Brother MFC7470D ,在 Ubuntu 中安装打印机驱动时,发现没有这个型号的驱动.只有 MFC7450 的 ...

  3. FJNU 1154 Fat Brother And His Love(胖哥与女神)

    FJNU 1154 Fat Brother And His Love(胖哥与女神) Time Limit: 2000MS   Memory Limit: 257792K [Description] [ ...

  4. FJNU 1153 Fat Brother And XOR(胖哥与异或)

    FJNU 1153 Fat Brother And XOR(胖哥与异或) Time Limit: 1000MS   Memory Limit: 257792K [Description] [题目描述] ...

  5. FJNU 1155 Fat Brother’s prediction(胖哥的预言)

    FJNU 1155 Fat Brother’s prediction(胖哥的预言) Time Limit: 1000MS   Memory Limit: 257792K [Description] [ ...

  6. FJNU 1152 Fat Brother And Integer(胖哥与整数)

    FJNU 1152 Fat Brother And Integer(胖哥与整数) Time Limit: 1000MS   Memory Limit: 257792K [Description] [题 ...

  7. FJNU 1156 Fat Brother’s Gorehowl(胖哥的血吼)

    FJNU 1156 Fat Brother’s Gorehowl(胖哥的血吼) Time Limit: 1000MS   Memory Limit: 257792K [Description] [题目 ...

  8. FJNU 1151 Fat Brother And Geometry(胖哥与几何)

    FJNU 1151 Fat Brother And Geometry(胖哥与几何) Time Limit: 1000MS   Memory Limit: 257792K [Description] [ ...

  9. FJNU 1157 Fat Brother’s ruozhi magic(胖哥的弱智术)

    FJNU 1157 Fat Brother’s ruozhi magic(胖哥的弱智术) Time Limit: 1000MS   Memory Limit: 257792K [Description ...

随机推荐

  1. 解密FFmpeg播放track mode控制

    上一篇文章(http://www.cnblogs.com/yangdanny/p/4421130.html)我们解决了在FFmpeg下如何处理H264和AAC的扩展数据,根据解出的NALU长度恢复了H ...

  2. spark standalone ha spark submit

    when you build a spark standalone ha cluster, when you submit your app,  you should send it to the l ...

  3. Android APP 读取 AndroidManifest.xml 中的版本信息详解

    APP都会涉及到版本的问题,Android APP的版本信息保存在AndroidManifest.xml文件的顶部.如下图: 有2个属性表示,“android:versionCode”和“androi ...

  4. (转)基于jQuery的form转json示例

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/ ...

  5. java笔记

    ANT概述:http://www.blogjava.net/amigoxie/archive/2007/11/09/159413.html http://baitai.iteye.com/blog/7 ...

  6. 《In Search of an Understandable Consensus Algorithm》翻译

    Abstract Raft是一种用于管理replicated log的consensus algorithm.它能和Paxos产生同样的结果,有着和Paxos同样的性能,但是结构却不同于Paxos:它 ...

  7. NOIP2010关押罪犯[并查集|二分答案+二分图染色 | 种类并查集]

    题目描述 S 城现有两座监狱,一共关押着N 名罪犯,编号分别为1~N.他们之间的关系自然也极不和谐.很多罪犯之间甚至积怨已久,如果客观条件具备则随时可能爆发冲突.我们用“怨气值”(一个正整数值)来表示 ...

  8. POJ3928Ping pong[树状数组 仿逆序对]

    Ping pong Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 3109   Accepted: 1148 Descrip ...

  9. 让easyui 的alert 消息框中的确定按钮支持空格键

    var _messager = $.extend({},$.messager);$.extend($.messager,{ alert:function(title, msg, icon, fn){ ...

  10. jquery easyui 1.4.1 API( CHM版)

    ChangeLog Bug The combogrid has different height than other combo components. fixed. datagrid: The r ...