'''
merge two configure files, basic file is aFile
insert the added content of bFile compare to aFile
for example, 'bbb' is added content
-----------------------------------------------------------
a file content | b file content | c merged file content
111 | 111 | 111
aaa | bbb | aaa
| | bbb
222 | 222 | 222
------------------------------------------------------------
'''
def mergeFiles(aPath, bPath, cPath): with open(aPath, 'r') as f:
aLines = f.readlines();
aLines = [ line.strip() + '\n' for line in aLines] with open(bPath, 'r') as f:
bLines = f.readlines();
bLines = [ line.strip() + '\n' for line in bLines] cLines = mergeSequences(aLines, bLines) with open(cPath, 'w') as f:
for line in cLines:
f.write(line) '''
merge the sequence
'''
def mergeSequences(aLines, bLines):
record = {}
lcs = findLCS(record, aLines, 0, bLines, 0)
currA = currB = 0
merged = []
for (line, aI, bI) in lcs: # add deleted
if aI > currA:
merged.extend(aLines[currA:aI])
currA = aI + 1 # add added
if bI > currB:
merged.extend(bLines[currB:bI])
currB = bI + 1 # add common
merged.append(line) if currA < len(aLines):
merged.extend(aLines[currA:])
if currB < len(bLines):
merged.extend(bLines[currB:]) return merged '''
find Longest common subsequence
return list of (line, x, y)
line is common line, x is the index in aLines, y is the index in bLines
TODO: eliminate recursive invoke, use dynamic algorithm
'''
def findLCS(record, aLines, aStart, bLines, bStart): key = lcsKey(aStart, bStart)
if record.has_key(key):
return record[key] aL = aLines[aStart:]
bL = bLines[bStart:]
if len(aL) > 0 and len(bL) > 0:
if aL[0] == bL[0]:
lsc = [(aL[0], aStart, bStart)]
lsc.extend(findLCS(record, aLines, aStart + 1, bLines, bStart + 1))
record[key] = lsc
return lsc
else:
aLsc = findLCS(record, aLines, aStart, bLines, bStart + 1)
bLsc = findLCS(record, aLines, aStart + 1, bLines, bStart) if len(aLsc) > len(bLsc):
record[key] = aLsc
return aLsc
else:
record[key] = bLsc
return bLsc
else:
return [] Code

最长公共字串算法, 文本比较算法, longest common subsequence(LCS) algorithm的更多相关文章

  1. 最长公共子序列与最长公共字串 (dp)转载http://blog.csdn.net/u012102306/article/details/53184446

    1. 问题描述 子串应该比较好理解,至于什么是子序列,这里给出一个例子:有两个母串 cnblogs belong 比如序列bo, bg, lg在母串cnblogs与belong中都出现过并且出现顺序与 ...

  2. URAL 1517 Freedom of Choice(后缀数组,最长公共字串)

    题目 输出最长公共字串 #define maxn 200010 int wa[maxn],wb[maxn],wv[maxn],ws[maxn]; int cmp(int *r,int a,int b, ...

  3. (字符串)最长公共字串(Longest-Common-SubString,LCS)

    题目: 给定两个字符串X,Y,求二者最长的公共子串,例如X=[aaaba],Y=[abaa].二者的最长公共子串为[aba],长度为3. 子序列是不要求连续的,字串必须是连续的. 思路与代码: 1.简 ...

  4. 动态规划求最长公共子序列(Longest Common Subsequence, LCS)

    1. 问题描述 子串应该比较好理解,至于什么是子序列,这里给出一个例子:有两个母串 cnblogs belong 比如序列bo, bg, lg在母串cnblogs与belong中都出现过并且出现顺序与 ...

  5. poj 3080 kmp求解多个字符串的最长公共字串,(数据小,有点小暴力 16ms)

    Blue Jeans Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 14113   Accepted: 6260 Descr ...

  6. java_基础知识_字符串练习题_计算两个字符串的最长公共字串长度

    package tek; Java算法——求出两个字符串的最长公共字符串 /** * @Title: 问题:有两个字符串str1和str2,求出两个字符串中最长公共字符串. * @author 匹夫( ...

  7. 【水:最长公共子序列】【HDU1159】【Common Subsequence】

    Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Other ...

  8. 动态规划 ---- 最长公共子序列(Longest Common Subsequence, LCS)

    分析: 完整代码: // 最长公共子序列 #include <stdio.h> #include <algorithm> using namespace std; ; char ...

  9. HDU 1423 最长公共字串+上升子序列

    http://acm.hdu.edu.cn/showproblem.php?pid=1423 在前一道题的基础上多了一次筛选 要选出一个最长的递增数列 lower_bound()函数很好用,二分搜索找 ...

随机推荐

  1. sql优化 in 和 not in 语句

    WHY? IN 和 NOT IN 是比较常用的关键字,为什么要尽量避免呢? 1.效率低 可以参看我之前遇到的一个例子([小问题笔记(九)] SQL语句Not IN 效率低,用 NOT EXISTS试试 ...

  2. 03 Java 修饰符

    Java 修饰符主要分为两类: 访问修饰符 非访问修饰符 访问修饰符 public,对所有类可见 protected,对同一包内的类和子类可见 default,同一个包内的类可见 private,对当 ...

  3. firefox解决flash崩溃

    1.地址栏输入 about:config 2.查找dom.ipc.plugins.flash.subprocess.crashreporter.enabled 更改为false

  4. 关于SelectedValue的众多解决方案

    Combox联动效果

  5. ListView控件的不为人知的秘密

    使用ListView控件展示数据 1.图像列表控件(ImageList控件) 图像列表控件(ImageList控件)是含有图像对象的集合,可以通过索引或关键字引用该集合的每个对象,ImageList控 ...

  6. [LeetCode] Restore IP Addresses 回溯

    Given a string containing only digits, restore it by returning all possible valid IP address combina ...

  7. CPU负载监控

    #!/usr/bin/python #-*- encoding: utf-8 -*- import os import time while True: loadavg=os.popen(" ...

  8. python--jinja2

    from jinja2 import Template # 创建一个Template模板去渲染它 s = "my name is {{mashiro}}" t = Template ...

  9. pycharm配置pep8

    可以使用外部工具,来检查代码是否符合pep8的风格: 1)下载 autopep8,这个简单,pip3 install pep8 2)在pychamr中配置: A)file-setting..-tool ...

  10. (2)C语言 基础2

    一.函数 二.指针 1.指针是一个用来存储内存地址的变量. int * p ; 定义了一个指针变量p,p中存储的是一个地址,改地址里必定会存储一个int类型的数据. *号表示变量p是一个指针.*和指针 ...