leetcode 24. Swap Nodes in Pairs(链表)

Given a linked list, swap every two adjacent nodes and return its head.

For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.

Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.

题解：就把每两个节点的值换一下就ok了。

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* swapPairs(ListNode* head) {
        ListNode* p=head;
        while(p&&p->next){
            int t=p->val;
            p->val=p->next->val;
            p->next->val=t;
            p=p->next->next;
        }
        return head;
    }
};