HDU 2602.Bone Collector-动态规划0-1背包

Bone Collector

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 85530    Accepted Submission(s): 35381

Problem Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

 

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

 

Output

One integer per line representing the maximum of the total value (this number will be less than 2³¹).

 

Sample Input

1
5 10
1 2 3 4 5
5 4 3 2 1

 

Sample Output

14

 

Author

Teddy

 

Source

HDU 1st “Vegetable-Birds Cup” Programming Open Contest

 

 

 

代码(一维数组):

 #include<bits/stdc++.h>
 using namespace std;
 const int N=1e5+;
 int val[N],wei[N],dp[N];
 int main(){
     int t,n,m;
     scanf("%d",&t);
     while(t--){
             memset(val,,sizeof(val));
             memset(wei,,sizeof(wei));
             memset(dp,,sizeof(dp));
         scanf("%d%d",&n,&m);
         for(int i=;i<n;i++)
             scanf("%d",&val[i]);
         for(int i=;i<n;i++)
             scanf("%d",&wei[i]);
         for(int i=;i<n;i++){
             for(int j=m;j>=wei[i];j--){
                 dp[j]=max(dp[j],dp[j-wei[i]]+val[i]);
             }
         }
         printf("%d\n",dp[m]);
     }
     return ;
 }

代码(二维数组):

 #include<bits/stdc++.h>
 using namespace std;
 const int N=1e3+;
 int val[N],wei[N],dp[N][N];
 int main(){
     int t,n,m;
     scanf("%d",&t);
     while(t--){
         memset(dp,,sizeof(dp));
         scanf("%d%d",&n,&m);
         for(int i=;i<=n;i++)
             scanf("%d",&val[i]);
         for(int i=;i<=n;i++)
             scanf("%d",&wei[i]);
         for(int i=;i<=n;i++){
             for(int j=;j<=m;j++){
                 if(wei[i]<=j)dp[i][j]=max(dp[i-][j],dp[i-][j-wei[i]]+val[i]);
                 else dp[i][j]=dp[i-][j];
             }
         }
         printf("%d\n",dp[n][m]);
     }
     return ;
 }